details

property	value
status	complete
benchmark	prov.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n070.star.cs.uiowa.edu
space	Rubio_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.59629 seconds
cpu usage	3.57796
user time	3.42024
system time	0.157719
max virtual memory	1.8408912E7
max residence set size	234624.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 63 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 0 ms] (4) QTRS (5) RisEmptyProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: ackin(s(X), s(Y)) -> u21(ackin(s(X), Y), X) u21(ackout(X), Y) -> u22(ackin(Y, X)) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: ackin/2(YES,YES) s/1(YES) u21/2(YES,YES) ackout/1)YES( u22/1)YES( Quasi precedence: [ackin_2, u21_2] > s_1 Status: ackin_2: [1,2] s_1: [1] u21_2: [2,1] With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: ackin(s(X), s(Y)) -> u21(ackin(s(X), Y), X) ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: u21(ackout(X), Y) -> u22(ackin(Y, X)) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Knuth-Bendix order [KBO] with precedence:ackin_2 > u21_2 > u22_1 > ackout_1 and weight map: ackout_1=1 u22_1=1 u21_2=0 ackin_2=0 The variable weight is 1With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: u21(ackout(X), Y) -> u22(ackin(Y, X)) ---------------------------------------- (4) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (5) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (6) popout

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