details

property	value
status	complete
benchmark	gm.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n073.star.cs.uiowa.edu
space	Rubio_04

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.799638 seconds
cpu usage	2.07594
user time	1.54001
system time	0.53593
max virtual memory	3688024.0
max residence set size	68860.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: minus(X,0()) -> X minus(s(X),s(Y)) -> p(minus(X,Y)) p(s(X)) -> X div(0(),s(Y)) -> 0() div(s(X),s(Y)) -> s(div(minus(X,Y),s(Y))) Proof: DP Processor: DPs: minus#(s(X),s(Y)) -> minus#(X,Y) minus#(s(X),s(Y)) -> p#(minus(X,Y)) div#(s(X),s(Y)) -> minus#(X,Y) div#(s(X),s(Y)) -> div#(minus(X,Y),s(Y)) TRS: minus(X,0()) -> X minus(s(X),s(Y)) -> p(minus(X,Y)) p(s(X)) -> X div(0(),s(Y)) -> 0() div(s(X),s(Y)) -> s(div(minus(X,Y),s(Y))) TDG Processor: DPs: minus#(s(X),s(Y)) -> minus#(X,Y) minus#(s(X),s(Y)) -> p#(minus(X,Y)) div#(s(X),s(Y)) -> minus#(X,Y) div#(s(X),s(Y)) -> div#(minus(X,Y),s(Y)) TRS: minus(X,0()) -> X minus(s(X),s(Y)) -> p(minus(X,Y)) p(s(X)) -> X div(0(),s(Y)) -> 0() div(s(X),s(Y)) -> s(div(minus(X,Y),s(Y))) graph: div#(s(X),s(Y)) -> div#(minus(X,Y),s(Y)) -> div#(s(X),s(Y)) -> div#(minus(X,Y),s(Y)) div#(s(X),s(Y)) -> div#(minus(X,Y),s(Y)) -> div#(s(X),s(Y)) -> minus#(X,Y) div#(s(X),s(Y)) -> minus#(X,Y) -> minus#(s(X),s(Y)) -> p#(minus(X,Y)) div#(s(X),s(Y)) -> minus#(X,Y) -> minus#(s(X),s(Y)) -> minus#(X,Y) minus#(s(X),s(Y)) -> minus#(X,Y) -> minus#(s(X),s(Y)) -> p#(minus(X,Y)) minus#(s(X),s(Y)) -> minus#(X,Y) -> minus#(s(X),s(Y)) -> minus#(X,Y) SCC Processor: #sccs: 2 #rules: 2 #arcs: 6/16 DPs: div#(s(X),s(Y)) -> div#(minus(X,Y),s(Y)) TRS: minus(X,0()) -> X minus(s(X),s(Y)) -> p(minus(X,Y)) p(s(X)) -> X div(0(),s(Y)) -> 0() div(s(X),s(Y)) -> s(div(minus(X,Y),s(Y))) Subterm Criterion Processor: simple projection: pi(minus) = 0 pi(p) = 0 pi(div#) = 0 problem: DPs: TRS: minus(X,0()) -> X minus(s(X),s(Y)) -> p(minus(X,Y)) p(s(X)) -> X div(0(),s(Y)) -> 0() div(s(X),s(Y)) -> s(div(minus(X,Y),s(Y))) Qed DPs: minus#(s(X),s(Y)) -> minus#(X,Y) TRS: minus(X,0()) -> X minus(s(X),s(Y)) -> p(minus(X,Y)) p(s(X)) -> X div(0(),s(Y)) -> 0() div(s(X),s(Y)) -> s(div(minus(X,Y),s(Y))) Subterm Criterion Processor: simple projection: pi(minus#) = 0 problem: DPs: TRS: minus(X,0()) -> X minus(s(X),s(Y)) -> p(minus(X,Y)) p(s(X)) -> X div(0(),s(Y)) -> 0() div(s(X),s(Y)) -> s(div(minus(X,Y),s(Y))) Qed popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Standard