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TRS Standard pair #487069342
details
property
value
status
complete
benchmark
koen.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n182.star.cs.uiowa.edu
space
Rubio_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.403791 seconds
cpu usage
0.589133
user time
0.406116
system time
0.183017
max virtual memory
96176.0
max residence set size
57992.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: f(s(X),X) -> f(X,a(X)) f(X,c(X)) -> f(s(X),X) f(X,X) -> c(X) Proof: Matrix Interpretation Processor: dim=1 interpretation: [f](x0, x1) = 2x0 + 2x1 + 3, [c](x0) = 4x0, [s](x0) = 4x0, [a](x0) = 4x0 orientation: f(s(X),X) = 10X + 3 >= 10X + 3 = f(X,a(X)) f(X,c(X)) = 10X + 3 >= 10X + 3 = f(s(X),X) f(X,X) = 4X + 3 >= 4X = c(X) problem: f(s(X),X) -> f(X,a(X)) f(X,c(X)) -> f(s(X),X) Matrix Interpretation Processor: dim=1 interpretation: [f](x0, x1) = x0 + x1 + 4, [c](x0) = 7x0 + 1, [s](x0) = 7x0, [a](x0) = 7x0 orientation: f(s(X),X) = 8X + 4 >= 8X + 4 = f(X,a(X)) f(X,c(X)) = 8X + 5 >= 8X + 4 = f(s(X),X) problem: f(s(X),X) -> f(X,a(X)) Matrix Interpretation Processor: dim=1 interpretation: [f](x0, x1) = x0 + 5x1 + 3, [s](x0) = 6x0 + 5, [a](x0) = 2x0 orientation: f(s(X),X) = 11X + 8 >= 11X + 3 = f(X,a(X)) problem: Qed
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