details

property	value
status	complete
benchmark	ExProp7_Luc06_C.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n186.star.cs.uiowa.edu
space	Transformed_CSR_04

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	3.37018 seconds
cpu usage	8.34209
user time	7.22884
system time	1.11325
max virtual memory	2042576.0
max residence set size	134948.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: active(f(0())) -> mark(cons(0(),f(s(0())))) active(f(s(0()))) -> mark(f(p(s(0())))) active(p(s(X))) -> mark(X) active(f(X)) -> f(active(X)) active(cons(X1,X2)) -> cons(active(X1),X2) active(s(X)) -> s(active(X)) active(p(X)) -> p(active(X)) f(mark(X)) -> mark(f(X)) cons(mark(X1),X2) -> mark(cons(X1,X2)) s(mark(X)) -> mark(s(X)) p(mark(X)) -> mark(p(X)) proper(f(X)) -> f(proper(X)) proper(0()) -> ok(0()) proper(cons(X1,X2)) -> cons(proper(X1),proper(X2)) proper(s(X)) -> s(proper(X)) proper(p(X)) -> p(proper(X)) f(ok(X)) -> ok(f(X)) cons(ok(X1),ok(X2)) -> ok(cons(X1,X2)) s(ok(X)) -> ok(s(X)) p(ok(X)) -> ok(p(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [cons](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 1] [0 0 0] , [ok](x0) = x0 , [1 0 0] [f](x0) = [0 0 0]x0 [0 1 1] , [s](x0) = x0 , [1 1 1] [mark](x0) = [0 0 0]x0 [0 0 0] , [0] [0] = [1] [0], [proper](x0) = x0 , [1 0 1] [0] [top](x0) = [0 0 0]x0 + [1] [0 0 0] [1], [1 0 0] [p](x0) = [0 0 0]x0 [0 1 1] , [1 0 1] [active](x0) = [0 0 0]x0 [0 0 0] orientation: [1] [0] active(f(0())) = [0] >= [0] = mark(cons(0(),f(s(0())))) [0] [0] [1] [1] active(f(s(0()))) = [0] >= [0] = mark(f(p(s(0())))) [0] [0] [1 1 1] [1 1 1] active(p(s(X))) = [0 0 0]X >= [0 0 0]X = mark(X) [0 0 0] [0 0 0] [1 1 1] [1 0 1] active(f(X)) = [0 0 0]X >= [0 0 0]X = f(active(X)) [0 0 0] [0 0 0] [1 0 1] [1 0 0] [1 0 1] [1 0 0] active(cons(X1,X2)) = [0 0 0]X1 + [0 0 0]X2 >= [0 0 0]X1 + [0 0 0]X2 = cons(active(X1),X2) [0 0 0] [0 0 0] [0 0 0] [0 0 0] [1 0 1] [1 0 1] active(s(X)) = [0 0 0]X >= [0 0 0]X = s(active(X)) [0 0 0] [0 0 0] [1 1 1] [1 0 1] active(p(X)) = [0 0 0]X >= [0 0 0]X = p(active(X)) [0 0 0] [0 0 0] [1 1 1] [1 1 1] f(mark(X)) = [0 0 0]X >= [0 0 0]X = mark(f(X)) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Standard