details

property	value
status	complete
benchmark	Ex4_7_37_Bor03_Z.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n173.star.cs.uiowa.edu
space	Transformed_CSR_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.88815 seconds
cpu usage	4.10025
user time	3.90738
system time	0.192866
max virtual memory	1.8408912E7
max residence set size	254384.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) AND (5) QDP (6) UsableRulesProof [EQUIVALENT, 0 ms] (7) QDP (8) QDPSizeChangeProof [EQUIVALENT, 0 ms] (9) YES (10) QDP (11) QDPOrderProof [EQUIVALENT, 13 ms] (12) QDP (13) PisEmptyProof [EQUIVALENT, 0 ms] (14) YES (15) QDP (16) UsableRulesProof [EQUIVALENT, 0 ms] (17) QDP (18) QDPSizeChangeProof [EQUIVALENT, 0 ms] (19) YES (20) QDP (21) QDPSizeChangeProof [EQUIVALENT, 0 ms] (22) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: from(X) -> cons(X, n__from(s(X))) sel(0, cons(X, XS)) -> X sel(s(N), cons(X, XS)) -> sel(N, activate(XS)) minus(X, 0) -> 0 minus(s(X), s(Y)) -> minus(X, Y) quot(0, s(Y)) -> 0 quot(s(X), s(Y)) -> s(quot(minus(X, Y), s(Y))) zWquot(XS, nil) -> nil zWquot(nil, XS) -> nil zWquot(cons(X, XS), cons(Y, YS)) -> cons(quot(X, Y), n__zWquot(activate(XS), activate(YS))) from(X) -> n__from(X) zWquot(X1, X2) -> n__zWquot(X1, X2) activate(n__from(X)) -> from(X) activate(n__zWquot(X1, X2)) -> zWquot(X1, X2) activate(X) -> X Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: SEL(s(N), cons(X, XS)) -> SEL(N, activate(XS)) SEL(s(N), cons(X, XS)) -> ACTIVATE(XS) MINUS(s(X), s(Y)) -> MINUS(X, Y) QUOT(s(X), s(Y)) -> QUOT(minus(X, Y), s(Y)) QUOT(s(X), s(Y)) -> MINUS(X, Y) ZWQUOT(cons(X, XS), cons(Y, YS)) -> QUOT(X, Y) ZWQUOT(cons(X, XS), cons(Y, YS)) -> ACTIVATE(XS) ZWQUOT(cons(X, XS), cons(Y, YS)) -> ACTIVATE(YS) ACTIVATE(n__from(X)) -> FROM(X) ACTIVATE(n__zWquot(X1, X2)) -> ZWQUOT(X1, X2) The TRS R consists of the following rules: from(X) -> cons(X, n__from(s(X))) sel(0, cons(X, XS)) -> X sel(s(N), cons(X, XS)) -> sel(N, activate(XS)) minus(X, 0) -> 0 minus(s(X), s(Y)) -> minus(X, Y) quot(0, s(Y)) -> 0 quot(s(X), s(Y)) -> s(quot(minus(X, Y), s(Y))) zWquot(XS, nil) -> nil zWquot(nil, XS) -> nil zWquot(cons(X, XS), cons(Y, YS)) -> cons(quot(X, Y), n__zWquot(activate(XS), activate(YS))) from(X) -> n__from(X) zWquot(X1, X2) -> n__zWquot(X1, X2) activate(n__from(X)) -> from(X) activate(n__zWquot(X1, X2)) -> zWquot(X1, X2) activate(X) -> X Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- popout

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job log

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actions

all output return to TRS Standard