details

property	value
status	complete
benchmark	Ex9_Luc06_C.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n190.star.cs.uiowa.edu
space	Transformed_CSR_04

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	1.26951 seconds
cpu usage	3.84301
user time	3.13576
system time	0.707252
max virtual memory	1865148.0
max residence set size	88868.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: active(f(a(),X,X)) -> mark(f(X,b(),b())) active(b()) -> mark(a()) active(f(X1,X2,X3)) -> f(X1,active(X2),X3) f(X1,mark(X2),X3) -> mark(f(X1,X2,X3)) proper(f(X1,X2,X3)) -> f(proper(X1),proper(X2),proper(X3)) proper(a()) -> ok(a()) proper(b()) -> ok(b()) f(ok(X1),ok(X2),ok(X3)) -> ok(f(X1,X2,X3)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [mark](x0) = [0 1 0]x0 [0 0 0] , [1 1 0] [1 0 0] [1 1 0] [f](x0, x1, x2) = [0 0 0]x0 + [0 0 0]x1 + [0 0 0]x2 [0 0 0] [0 0 0] [0 0 0] , [0] [b] = [0] [0], [1 0 0] [proper](x0) = [0 1 0]x0 [1 0 0] , [0] [a] = [1] [0], [1 0 0] [0] [top](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [1 0 0] [ok](x0) = [0 1 0]x0 [0 0 0] , [1 0 0] [0] [active](x0) = [0 0 0]x0 + [1] [0 0 0] [0] orientation: [2 1 0] [1] [1 1 0] active(f(a(),X,X)) = [0 0 0]X + [1] >= [0 0 0]X = mark(f(X,b(),b())) [0 0 0] [0] [0 0 0] [0] [0] active(b()) = [1] >= [1] = mark(a()) [0] [0] [1 1 0] [1 0 0] [1 1 0] [0] [1 1 0] [1 0 0] [1 1 0] active(f(X1,X2,X3)) = [0 0 0]X1 + [0 0 0]X2 + [0 0 0]X3 + [1] >= [0 0 0]X1 + [0 0 0]X2 + [0 0 0]X3 = f(X1,active(X2),X3) [0 0 0] [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [0 0 0] [1 1 0] [1 0 0] [1 1 0] [1 1 0] [1 0 0] [1 1 0] f(X1,mark(X2),X3) = [0 0 0]X1 + [0 0 0]X2 + [0 0 0]X3 >= [0 0 0]X1 + [0 0 0]X2 + [0 0 0]X3 = mark(f(X1,X2,X3)) [0 0 0] [0 0 0] [0 0 0] [0 0 0] [0 0 0] [0 0 0] [1 1 0] [1 0 0] [1 1 0] [1 1 0] [1 0 0] [1 1 0] proper(f(X1,X2,X3)) = [0 0 0]X1 + [0 0 0]X2 + [0 0 0]X3 >= [0 0 0]X1 + [0 0 0]X2 + [0 0 0]X3 = f(proper(X1),proper(X2),proper(X3)) [1 1 0] [1 0 0] [1 1 0] [0 0 0] [0 0 0] [0 0 0] [0] [0] proper(a()) = [1] >= [1] = ok(a()) [0] [0] [0] [0] proper(b()) = [0] >= [0] = ok(b()) [0] [0] [1 1 0] [1 0 0] [1 1 0] [1 1 0] [1 0 0] [1 1 0] f(ok(X1),ok(X2),ok(X3)) = [0 0 0]X1 + [0 0 0]X2 + [0 0 0]X3 >= [0 0 0]X1 + [0 0 0]X2 + [0 0 0]X3 = ok(f(X1,X2,X3)) [0 0 0] [0 0 0] [0 0 0] [0 0 0] [0 0 0] [0 0 0] [1 0 0] [0] [1 0 0] [0] top(mark(X)) = [0 0 0]X + [1] >= [0 0 0]X + [1] = top(proper(X)) [0 0 0] [0] [0 0 0] [0] [1 0 0] [0] [1 0 0] [0] top(ok(X)) = [0 0 0]X + [1] >= [0 0 0]X + [1] = top(active(X)) [0 0 0] [0] [0 0 0] [0] problem: active(b()) -> mark(a()) active(f(X1,X2,X3)) -> f(X1,active(X2),X3) f(X1,mark(X2),X3) -> mark(f(X1,X2,X3)) proper(f(X1,X2,X3)) -> f(proper(X1),proper(X2),proper(X3)) proper(a()) -> ok(a()) proper(b()) -> ok(b()) f(ok(X1),ok(X2),ok(X3)) -> ok(f(X1,X2,X3)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Matrix Interpretation Processor: dim=3 popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Standard