details

property	value
status	complete
benchmark	Ex1_GM99_GM.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n192.star.cs.uiowa.edu
space	Transformed_CSR_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	3.16848 seconds
cpu usage	6.26549
user time	5.98632
system time	0.279167
max virtual memory	1.8477524E7
max residence set size	395764.0

stage attributes

key	value
starexec-result	NO

output

NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 29 ms] (6) QDP (7) DependencyGraphProof [EQUIVALENT, 0 ms] (8) QDP (9) NonTerminationLoopProof [COMPLETE, 111 ms] (10) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a__f(a, b, X) -> a__f(X, X, mark(X)) a__c -> a a__c -> b mark(f(X1, X2, X3)) -> a__f(X1, X2, mark(X3)) mark(c) -> a__c mark(a) -> a mark(b) -> b a__f(X1, X2, X3) -> f(X1, X2, X3) a__c -> c Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A__F(a, b, X) -> A__F(X, X, mark(X)) A__F(a, b, X) -> MARK(X) MARK(f(X1, X2, X3)) -> A__F(X1, X2, mark(X3)) MARK(f(X1, X2, X3)) -> MARK(X3) MARK(c) -> A__C The TRS R consists of the following rules: a__f(a, b, X) -> a__f(X, X, mark(X)) a__c -> a a__c -> b mark(f(X1, X2, X3)) -> a__f(X1, X2, mark(X3)) mark(c) -> a__c mark(a) -> a mark(b) -> b a__f(X1, X2, X3) -> f(X1, X2, X3) a__c -> c Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: A__F(a, b, X) -> MARK(X) MARK(f(X1, X2, X3)) -> A__F(X1, X2, mark(X3)) A__F(a, b, X) -> A__F(X, X, mark(X)) MARK(f(X1, X2, X3)) -> MARK(X3) The TRS R consists of the following rules: a__f(a, b, X) -> a__f(X, X, mark(X)) a__c -> a a__c -> b mark(f(X1, X2, X3)) -> a__f(X1, X2, mark(X3)) mark(c) -> a__c mark(a) -> a mark(b) -> b a__f(X1, X2, X3) -> f(X1, X2, X3) a__c -> c Q is empty. We have to consider all minimal (P,Q,R)-chains. popout

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job log

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actions

all output return to TRS Standard