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TRS Standard pair #487070703
details
property
value
status
complete
benchmark
ExIntrod_GM99_GM.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n177.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
23.3207 seconds
cpu usage
87.7179
user time
82.9983
system time
4.71959
max virtual memory
3.739282E7
max residence set size
6901696.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 19 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 274 ms] (6) QDP (7) QDPOrderProof [EQUIVALENT, 232 ms] (8) QDP (9) DependencyGraphProof [EQUIVALENT, 0 ms] (10) QDP (11) QDPOrderProof [EQUIVALENT, 218 ms] (12) QDP (13) DependencyGraphProof [EQUIVALENT, 0 ms] (14) QDP (15) QDPOrderProof [EQUIVALENT, 227 ms] (16) QDP (17) QDPOrderProof [EQUIVALENT, 233 ms] (18) QDP (19) DependencyGraphProof [EQUIVALENT, 0 ms] (20) QDP (21) QDPOrderProof [EQUIVALENT, 229 ms] (22) QDP (23) QDPOrderProof [EQUIVALENT, 215 ms] (24) QDP (25) DependencyGraphProof [EQUIVALENT, 0 ms] (26) QDP (27) QDPOrderProof [EQUIVALENT, 193 ms] (28) QDP (29) DependencyGraphProof [EQUIVALENT, 0 ms] (30) QDP (31) QDPOrderProof [EQUIVALENT, 166 ms] (32) QDP (33) QDPOrderProof [EQUIVALENT, 203 ms] (34) QDP (35) QDPOrderProof [EQUIVALENT, 190 ms] (36) QDP (37) QDPOrderProof [EQUIVALENT, 118 ms] (38) QDP (39) DependencyGraphProof [EQUIVALENT, 0 ms] (40) QDP (41) QDPSizeChangeProof [EQUIVALENT, 0 ms] (42) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a__primes -> a__sieve(a__from(s(s(0)))) a__from(X) -> cons(mark(X), from(s(X))) a__head(cons(X, Y)) -> mark(X) a__tail(cons(X, Y)) -> mark(Y) a__if(true, X, Y) -> mark(X) a__if(false, X, Y) -> mark(Y) a__filter(s(s(X)), cons(Y, Z)) -> a__if(divides(s(s(mark(X))), mark(Y)), filter(s(s(X)), Z), cons(Y, filter(X, sieve(Y)))) a__sieve(cons(X, Y)) -> cons(mark(X), filter(X, sieve(Y))) mark(primes) -> a__primes mark(sieve(X)) -> a__sieve(mark(X)) mark(from(X)) -> a__from(mark(X)) mark(head(X)) -> a__head(mark(X)) mark(tail(X)) -> a__tail(mark(X)) mark(if(X1, X2, X3)) -> a__if(mark(X1), X2, X3) mark(filter(X1, X2)) -> a__filter(mark(X1), mark(X2)) mark(s(X)) -> s(mark(X)) mark(0) -> 0 mark(cons(X1, X2)) -> cons(mark(X1), X2) mark(true) -> true mark(false) -> false mark(divides(X1, X2)) -> divides(mark(X1), mark(X2)) a__primes -> primes a__sieve(X) -> sieve(X) a__from(X) -> from(X) a__head(X) -> head(X) a__tail(X) -> tail(X) a__if(X1, X2, X3) -> if(X1, X2, X3) a__filter(X1, X2) -> filter(X1, X2) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules:
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