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TRS Standard pair #487071347
details
property
value
status
complete
benchmark
Ex24_Luc06_GM.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n191.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.559593 seconds
cpu usage
1.08698
user time
0.731538
system time
0.355442
max virtual memory
96176.0
max residence set size
65936.0
stage attributes
key
value
starexec-result
NO
output
NO Problem: a__f(b(),X,c()) -> a__f(X,a__c(),X) a__c() -> b() mark(f(X1,X2,X3)) -> a__f(X1,mark(X2),X3) mark(c()) -> a__c() mark(b()) -> b() a__f(X1,X2,X3) -> f(X1,X2,X3) a__c() -> c() Proof: Matrix Interpretation Processor: dim=1 interpretation: [f](x0, x1, x2) = x0 + 6x1 + x2, [c] = 2, [a__c] = 2, [mark](x0) = 5x0, [b] = 2, [a__f](x0, x1, x2) = 5x0 + 6x1 + x2 orientation: a__f(b(),X,c()) = 6X + 12 >= 6X + 12 = a__f(X,a__c(),X) a__c() = 2 >= 2 = b() mark(f(X1,X2,X3)) = 5X1 + 30X2 + 5X3 >= 5X1 + 30X2 + X3 = a__f(X1,mark(X2),X3) mark(c()) = 10 >= 2 = a__c() mark(b()) = 10 >= 2 = b() a__f(X1,X2,X3) = 5X1 + 6X2 + X3 >= X1 + 6X2 + X3 = f(X1,X2,X3) a__c() = 2 >= 2 = c() problem: a__f(b(),X,c()) -> a__f(X,a__c(),X) a__c() -> b() mark(f(X1,X2,X3)) -> a__f(X1,mark(X2),X3) a__f(X1,X2,X3) -> f(X1,X2,X3) a__c() -> c() Matrix Interpretation Processor: dim=1 interpretation: [f](x0, x1, x2) = x0 + 2x1 + x2 + 4, [c] = 5, [a__c] = 5, [mark](x0) = 4x0 + 1, [b] = 5, [a__f](x0, x1, x2) = x0 + 2x1 + x2 + 7 orientation: a__f(b(),X,c()) = 2X + 17 >= 2X + 17 = a__f(X,a__c(),X) a__c() = 5 >= 5 = b() mark(f(X1,X2,X3)) = 4X1 + 8X2 + 4X3 + 17 >= X1 + 8X2 + X3 + 9 = a__f(X1,mark(X2),X3) a__f(X1,X2,X3) = X1 + 2X2 + X3 + 7 >= X1 + 2X2 + X3 + 4 = f(X1,X2,X3) a__c() = 5 >= 5 = c() problem: a__f(b(),X,c()) -> a__f(X,a__c(),X) a__c() -> b() a__c() -> c() Unfolding Processor: loop length: 3 terms: a__f(a__c(),a__c(),a__c()) a__f(a__c(),a__c(),c()) a__f(b(),a__c(),c()) context: [] substitution: Qed
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