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TRS Standard pair #487071673
details
property
value
status
complete
benchmark
Ex24_Luc06_C.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n187.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.74755 seconds
cpu usage
3.56179
user time
3.39664
system time
0.165146
max virtual memory
1.8343604E7
max residence set size
232480.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSToCSRProof [EQUIVALENT, 0 ms] (2) CSR (3) CSRRRRProof [EQUIVALENT, 48 ms] (4) CSR (5) CSRRRRProof [EQUIVALENT, 0 ms] (6) CSR (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(f(b, X, c)) -> mark(f(X, c, X)) active(c) -> mark(b) active(f(X1, X2, X3)) -> f(X1, active(X2), X3) f(X1, mark(X2), X3) -> mark(f(X1, X2, X3)) proper(f(X1, X2, X3)) -> f(proper(X1), proper(X2), proper(X3)) proper(b) -> ok(b) proper(c) -> ok(c) f(ok(X1), ok(X2), ok(X3)) -> ok(f(X1, X2, X3)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Q is empty. ---------------------------------------- (1) QTRSToCSRProof (EQUIVALENT) The following Q TRS is given: Q restricted rewrite system: The TRS R consists of the following rules: active(f(b, X, c)) -> mark(f(X, c, X)) active(c) -> mark(b) active(f(X1, X2, X3)) -> f(X1, active(X2), X3) f(X1, mark(X2), X3) -> mark(f(X1, X2, X3)) proper(f(X1, X2, X3)) -> f(proper(X1), proper(X2), proper(X3)) proper(b) -> ok(b) proper(c) -> ok(c) f(ok(X1), ok(X2), ok(X3)) -> ok(f(X1, X2, X3)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Q is empty. Special symbols used for the transformation (see [GM04]): top: top_1, active: active_1, mark: mark_1, ok: ok_1, proper: proper_1 The replacement map contains the following entries: f: {2} b: empty set c: empty set The QTRS contained all rules created by the complete Giesl-Middeldorp transformation. Therefore, the inverse transformation is complete (and sound). ---------------------------------------- (2) Obligation: Context-sensitive rewrite system: The TRS R consists of the following rules: f(b, X, c) -> f(X, c, X) c -> b The replacement map contains the following entries: f: {2} b: empty set c: empty set ---------------------------------------- (3) CSRRRRProof (EQUIVALENT) The following CSR is given: Context-sensitive rewrite system: The TRS R consists of the following rules: f(b, X, c) -> f(X, c, X) c -> b The replacement map contains the following entries: f: {2} b: empty set c: empty set Used ordering: Polynomial interpretation [POLO]: POL(b) = 0 POL(c) = 1 POL(f(x_1, x_2, x_3)) = x_2 + x_3
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