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TRS Standard pair #487072015
details
property
value
status
complete
benchmark
Ex24_GM04.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n074.star.cs.uiowa.edu
space
Strategy_removed_CSR_05
run statistics
property
value
solver
NTI-TC20-firstrun
configuration
Default 200
runtime (wallclock)
0.187415 seconds
cpu usage
0.258968
user time
0.209637
system time
0.049331
max virtual memory
113188.0
max residence set size
57004.0
stage attributes
key
value
starexec-result
NO
output
NO Prover = TRS(tech=GUIDED_UNF, nb_unfoldings=unlimited, unfold_variables=true, strategy=LEFTMOST_NE) ** BEGIN proof argument ** The following rule was generated while unfolding the analyzed TRS: [iteration = 3] f(c,g(c),g(b)) -> f(c,g(c),g(b)) Let l be the left-hand side and r be the right-hand side of this rule. Let p = epsilon, theta1 = {} and theta2 = {}. We have r|p = f(c,g(c),g(b)) and theta2(theta1(l)) = theta1(r|p). Hence, the term theta1(l) = f(c,g(c),g(b)) loops w.r.t. the analyzed TRS. ** END proof argument ** ** BEGIN proof description ** ## Searching for a generalized rewrite rule (a rule whose right-hand side contains a variable that does not occur in the left-hand side)... No generalized rewrite rule found! ## Searching for a loop by unfolding (unfolding of variable subterms: ON)... # Iteration 0: no loop detected, 1 unfolded rule generated. # Iteration 1: no loop detected, 3 unfolded rules generated. # Iteration 2: no loop detected, 3 unfolded rules generated. # Iteration 3: loop detected, 3 unfolded rules generated. Here is the successful unfolding. Let IR be the TRS under analysis. L0 = f^#(_0,g(_0),_1) -> f^#(_1,_1,_1) is in U_IR^0. Let p0 = [0]. We unfold the rule of L0 forwards at position p0 with the rule g(b) -> c. ==> L1 = f^#(_0,g(_0),g(b)) -> f^#(c,g(b),g(b)) is in U_IR^1. Let p1 = [0]. The subterm at position p1 in the left-hand side of the rule of L1 unifies with the subterm at position p1 in the right-hand side of the rule of L1. ==> L2 = f^#(c,g(c),g(b)) -> f^#(c,g(b),g(b)) is in U_IR^2. Let p2 = [1, 0]. We unfold the rule of L2 forwards at position p2 with the rule b -> c. ==> L3 = f^#(c,g(c),g(b)) -> f^#(c,g(c),g(b)) is in U_IR^3. ** END proof description ** Proof stopped at iteration 3 Number of unfolded rules generated by this proof = 10 Number of unfolded rules generated by all the parallel proofs = 11
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