details

property	value
status	complete
benchmark	Ex1_Zan97.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n190.star.cs.uiowa.edu
space	Strategy_removed_CSR_05

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	2.84629 seconds
cpu usage	7.94726
user time	7.60116
system time	0.346096
max virtual memory	2.0144244E7
max residence set size	719264.0

stage attributes

key	value
starexec-result	NO

output

NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) AAECC Innermost [EQUIVALENT, 4 ms] (4) QTRS (5) DependencyPairsProof [EQUIVALENT, 0 ms] (6) QDP (7) DependencyGraphProof [EQUIVALENT, 0 ms] (8) QDP (9) UsableRulesProof [EQUIVALENT, 0 ms] (10) QDP (11) QReductionProof [EQUIVALENT, 0 ms] (12) QDP (13) MNOCProof [EQUIVALENT, 0 ms] (14) QDP (15) NonTerminationLoopProof [COMPLETE, 0 ms] (16) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: g(X) -> h(X) c -> d h(d) -> g(c) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: g(X) -> h(X) c'(x) -> d'(x) d'(h(x)) -> c'(g(x)) Q is empty. ---------------------------------------- (3) AAECC Innermost (EQUIVALENT) We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is g(X) -> h(X) The TRS R 2 is c'(x) -> d'(x) d'(h(x)) -> c'(g(x)) The signature Sigma is {c'_1, d'_1} ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: g(X) -> h(X) c'(x) -> d'(x) d'(h(x)) -> c'(g(x)) The set Q consists of the following terms: g(x0) c'(x0) d'(h(x0)) ---------------------------------------- (5) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules: C'(x) -> D'(x) D'(h(x)) -> C'(g(x)) D'(h(x)) -> G(x) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Standard