details

property	value
status	complete
benchmark	secret3.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n187.star.cs.uiowa.edu
space	Secret_07_TRS

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.71209 seconds
cpu usage	3.87074
user time	3.71692
system time	0.153819
max virtual memory	1.8408912E7
max residence set size	243548.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 116 ms] (2) QTRS (3) RisEmptyProof [EQUIVALENT, 0 ms] (4) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: app(nil, k) -> k app(l, nil) -> l app(cons(x, l), k) -> cons(x, app(l, k)) sum(cons(x, nil)) -> cons(x, nil) sum(cons(x, cons(y, l))) -> sum(cons(a(x, y, h), l)) a(h, h, x) -> s(x) a(x, s(y), h) -> a(x, y, s(h)) a(x, s(y), s(z)) -> a(x, y, a(x, s(y), z)) a(s(x), h, z) -> a(x, z, z) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Quasi precedence: app_2 > cons_2 > [a_3, h] > s_1 > nil sum_1 > cons_2 > [a_3, h] > s_1 > nil Status: app_2: [2,1] nil: multiset status cons_2: [2,1] sum_1: multiset status a_3: [1,2,3] h: multiset status s_1: multiset status With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: app(nil, k) -> k app(l, nil) -> l app(cons(x, l), k) -> cons(x, app(l, k)) sum(cons(x, nil)) -> cons(x, nil) sum(cons(x, cons(y, l))) -> sum(cons(a(x, y, h), l)) a(h, h, x) -> s(x) a(x, s(y), h) -> a(x, y, s(h)) a(x, s(y), s(z)) -> a(x, y, a(x, s(y), z)) a(s(x), h, z) -> a(x, z, z) ---------------------------------------- (2) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (3) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (4) YES popout

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all output return to TRS Standard