details

property	value
status	complete
benchmark	#3.2.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n072.star.cs.uiowa.edu
space	Applicative_first_order_05

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	1.12181 seconds
cpu usage	3.02347
user time	2.42678
system time	0.596682
max virtual memory	1764348.0
max residence set size	81972.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: app(pred(),app(s(),x)) -> x app(app(minus(),x),0()) -> x app(app(minus(),x),app(s(),y)) -> app(pred(),app(app(minus(),x),y)) app(app(quot(),0()),app(s(),y)) -> 0() app(app(quot(),app(s(),x)),app(s(),y)) -> app(s(),app(app(quot(),app(app(minus(),x),y)),app(s(),y))) app(app(map(),f),nil()) -> nil() app(app(map(),f),app(app(cons(),x),xs)) -> app(app(cons(),app(f,x)),app(app(map(),f),xs)) app(app(filter(),f),nil()) -> nil() app(app(filter(),f),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(f,x)),f),x),xs) app(app(app(app(filter2(),true()),f),x),xs) -> app(app(cons(),x),app(app(filter(),f),xs)) app(app(app(app(filter2(),false()),f),x),xs) -> app(app(filter(),f),xs) Proof: Extended Uncurrying Processor: application symbol: app symbol table: false ==> false0/0 true ==> true0/0 filter2 ==> filter20/0 filter21/1 filter22/2 filter23/3 filter24/4 filter ==> filter0/0 filter1/1 filter2/2 cons ==> cons0/0 cons1/1 cons2/2 nil ==> nil0/0 map ==> map0/0 map1/1 map2/2 quot ==> quot0/0 quot1/1 quot2/2 0 ==> 00/0 minus ==> minus0/0 minus1/1 minus2/2 s ==> s0/0 s1/1 pred ==> pred0/0 pred1/1 uncurry-rules: app(pred0(),x4) -> pred1(x4) app(s0(),x6) -> s1(x6) app(minus1(x8),x9) -> minus2(x8,x9) app(minus0(),x8) -> minus1(x8) app(quot1(x12),x13) -> quot2(x12,x13) app(quot0(),x12) -> quot1(x12) app(map1(x15),x16) -> map2(x15,x16) app(map0(),x15) -> map1(x15) app(cons1(x19),x20) -> cons2(x19,x20) app(cons0(),x19) -> cons1(x19) app(filter1(x22),x23) -> filter2(x22,x23) app(filter0(),x22) -> filter1(x22) app(filter23(x25,x26,x27),x28) -> filter24(x25,x26,x27,x28) app(filter22(x25,x26),x27) -> filter23(x25,x26,x27) app(filter21(x25),x26) -> filter22(x25,x26) app(filter20(),x25) -> filter21(x25) eta-rules: problem: pred1(s1(x)) -> x minus2(x,00()) -> x minus2(x,s1(y)) -> pred1(minus2(x,y)) quot2(00(),s1(y)) -> 00() quot2(s1(x),s1(y)) -> s1(quot2(minus2(x,y),s1(y))) map2(f,nil0()) -> nil0() map2(f,cons2(x,xs)) -> cons2(app(f,x),map2(f,xs)) filter2(f,nil0()) -> nil0() filter2(f,cons2(x,xs)) -> filter24(app(f,x),f,x,xs) filter24(true0(),f,x,xs) -> cons2(x,filter2(f,xs)) filter24(false0(),f,x,xs) -> filter2(f,xs) app(pred0(),x4) -> pred1(x4) app(s0(),x6) -> s1(x6) app(minus1(x8),x9) -> minus2(x8,x9) app(minus0(),x8) -> minus1(x8) app(quot1(x12),x13) -> quot2(x12,x13) app(quot0(),x12) -> quot1(x12) app(map1(x15),x16) -> map2(x15,x16) app(map0(),x15) -> map1(x15) app(cons1(x19),x20) -> cons2(x19,x20) app(cons0(),x19) -> cons1(x19) app(filter1(x22),x23) -> filter2(x22,x23) app(filter0(),x22) -> filter1(x22) app(filter23(x25,x26,x27),x28) -> filter24(x25,x26,x27,x28) app(filter22(x25,x26),x27) -> filter23(x25,x26,x27) app(filter21(x25),x26) -> filter22(x25,x26) app(filter20(),x25) -> filter21(x25) DP Processor: DPs: minus{2,#}(x,s1(y)) -> minus{2,#}(x,y) minus{2,#}(x,s1(y)) -> pred{1,#}(minus2(x,y)) quot{2,#}(s1(x),s1(y)) -> minus{2,#}(x,y) quot{2,#}(s1(x),s1(y)) -> quot{2,#}(minus2(x,y),s1(y)) map{2,#}(f,cons2(x,xs)) -> map{2,#}(f,xs) map{2,#}(f,cons2(x,xs)) -> app#(f,x) filter{2,#}(f,cons2(x,xs)) -> app#(f,x) filter{2,#}(f,cons2(x,xs)) -> filter2{4,#}(app(f,x),f,x,xs) filter2{4,#}(true0(),f,x,xs) -> filter{2,#}(f,xs) filter2{4,#}(false0(),f,x,xs) -> filter{2,#}(f,xs) app#(pred0(),x4) -> pred{1,#}(x4) app#(minus1(x8),x9) -> minus{2,#}(x8,x9) app#(quot1(x12),x13) -> quot{2,#}(x12,x13) app#(map1(x15),x16) -> map{2,#}(x15,x16) app#(filter1(x22),x23) -> filter{2,#}(x22,x23) app#(filter23(x25,x26,x27),x28) -> filter2{4,#}(x25,x26,x27,x28) TRS: pred1(s1(x)) -> x popout

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