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TRS Standard pair #487072667
details
property
value
status
complete
benchmark
8.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n074.star.cs.uiowa.edu
space
Secret_06_TRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.425056 seconds
cpu usage
0.670467
user time
0.518923
system time
0.151544
max virtual memory
96176.0
max residence set size
59316.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: b(b(0(),y),x) -> y c(c(c(y))) -> c(c(a(a(c(b(0(),y)),0()),0()))) a(y,0()) -> b(y,0()) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [b](x0, x1) = [0 0 1]x0 + [0 0 0]x1 [0 0 1] [0 1 1] , [1 0 1] [1 0 0] [a](x0, x1) = [0 0 1]x0 + [0 0 0]x1 [0 0 1] [0 0 0] , [0] [0] = [0] [0], [1 0 1] [0] [c](x0) = [0 0 0]x0 + [1] [0 1 0] [0] orientation: [1 0 0] [1 0 0] b(b(0(),y),x) = [0 0 0]x + [0 1 1]y >= y = y [0 1 1] [0 1 1] [1 1 1] [1] [1 1 1] [0] c(c(c(y))) = [0 0 0]y + [1] >= [0 0 0]y + [1] = c(c(a(a(c(b(0(),y)),0()),0()))) [0 0 0] [1] [0 0 0] [1] [1 0 1] [1 0 0] a(y,0()) = [0 0 1]y >= [0 0 1]y = b(y,0()) [0 0 1] [0 0 1] problem: b(b(0(),y),x) -> y a(y,0()) -> b(y,0()) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [b](x0, x1) = [0 1 1]x0 + [0 0 1]x1 [0 1 0] [0 1 0] , [1 0 0] [1 0 0] [1] [a](x0, x1) = [0 1 1]x0 + [0 0 0]x1 + [0] [0 1 1] [0 0 0] [0], [0] [0] = [0] [0] orientation: [1 0 0] [1 0 0] b(b(0(),y),x) = [0 0 1]x + [0 1 1]y >= y = y [0 1 0] [0 0 1] [1 0 0] [1] [1 0 0] a(y,0()) = [0 1 1]y + [0] >= [0 1 1]y = b(y,0()) [0 1 1] [0] [0 1 0] problem: b(b(0(),y),x) -> y Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [1 0 0] [b](x0, x1) = [0 1 0]x0 + [0 1 1]x1 [0 1 0] [0 0 0] , [0] [0] = [1] [0] orientation: [1 0 0] [1 0 0] [1] b(b(0(),y),x) = [0 1 1]x + [0 1 1]y + [1] >= y = y [0 0 0] [0 1 1] [1] problem: Qed
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