Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
TRS Standard pair #487072692
details
property
value
status
complete
benchmark
6.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n189.star.cs.uiowa.edu
space
Secret_06_TRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.439634 seconds
cpu usage
0.734775
user time
0.562186
system time
0.172589
max virtual memory
96176.0
max residence set size
58996.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: b(x,y) -> c(a(c(y),a(0(),x))) a(y,x) -> y a(y,c(b(a(0(),x),0()))) -> b(a(c(b(0(),y)),x),0()) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [c](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [1 0 0] [a](x0, x1) = [0 1 1]x0 + [0 0 0]x1 [0 1 1] [0 0 0] , [1 0 0] [1 1 0] [b](x0, x1) = [0 1 0]x0 + [0 0 0]x1 [0 0 0] [1 0 0] , [0] [0] = [0] [1] orientation: [1 0 0] [1 1 0] [1 0 0] [1 1 0] b(x,y) = [0 1 0]x + [0 0 0]y >= [0 0 0]x + [0 0 0]y = c(a(c(y),a(0(),x))) [0 0 0] [1 0 0] [0 0 0] [0 0 0] [1 0 0] [1 1 0] a(y,x) = [0 0 0]x + [0 1 1]y >= y = y [0 0 0] [0 1 1] [1 0 0] [1 1 0] [1] [1 0 0] [1 1 0] a(y,c(b(a(0(),x),0()))) = [0 0 0]x + [0 1 1]y + [0] >= [0 0 0]x + [0 0 0]y = b(a(c(b(0(),y)),x),0()) [0 0 0] [0 1 1] [0] [0 0 0] [0 0 0] problem: b(x,y) -> c(a(c(y),a(0(),x))) a(y,x) -> y Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = x0, [a](x0, x1) = x0 + 2x1, [b](x0, x1) = 4x0 + x1 + 1, [0] = 0 orientation: b(x,y) = 4x + y + 1 >= 4x + y = c(a(c(y),a(0(),x))) a(y,x) = 2x + y >= y = y problem: a(y,x) -> y Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1] [a](x0, x1) = x0 + [0 0 0]x1 + [0] [0 0 0] [0] orientation: [1 0 0] [1] a(y,x) = [0 0 0]x + y + [0] >= y = y [0 0 0] [0] problem: Qed
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to TRS Standard