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TRS Standard pair #487072737
details
property
value
status
complete
benchmark
7.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n072.star.cs.uiowa.edu
space
Secret_06_TRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.500719 seconds
cpu usage
0.994073
user time
0.765359
system time
0.228714
max virtual memory
96176.0
max residence set size
63616.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: c(c(c(a(x,y)))) -> b(c(c(c(c(y)))),x) c(c(b(c(y),0()))) -> a(0(),c(c(a(y,0())))) c(c(a(a(y,0()),x))) -> c(y) Proof: Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = 2x0, [0] = 1, [a](x0, x1) = x0 + 2x1, [b](x0, x1) = x0 + 6x1 orientation: c(c(c(a(x,y)))) = 8x + 16y >= 6x + 16y = b(c(c(c(c(y)))),x) c(c(b(c(y),0()))) = 8y + 24 >= 8y + 17 = a(0(),c(c(a(y,0())))) c(c(a(a(y,0()),x))) = 8x + 4y + 8 >= 2y = c(y) problem: c(c(c(a(x,y)))) -> b(c(c(c(c(y)))),x) Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = x0, [a](x0, x1) = x0 + x1 + 3, [b](x0, x1) = x0 + x1 orientation: c(c(c(a(x,y)))) = x + y + 3 >= x + y = b(c(c(c(c(y)))),x) problem: Qed
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