details

property	value
status	complete
benchmark	divExp.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n174.star.cs.uiowa.edu
space	Secret_06_TRS

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	20.2477 seconds
cpu usage	20.2323
user time	16.3957
system time	3.83659
max virtual memory	597920.0
max residence set size	6172.0

stage attributes

key	value
starexec-result	YES

output

YES Problem 1: (VAR v_NonEmpty:S b:S x:S y:S) (RULES div(0,s(y:S)) -> 0 div(s(x:S),s(y:S)) -> s(div(minus(x:S,y:S),s(y:S))) f(x:S,0,b:S) -> x:S f(x:S,s(y:S),b:S) -> div(f(x:S,minus(s(y:S),s(0)),b:S),b:S) minus(0,x:S) -> 0 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S minus(x:S,x:S) -> 0 ) Problem 1: Dependency Pairs Processor: -> Pairs: DIV(s(x:S),s(y:S)) -> DIV(minus(x:S,y:S),s(y:S)) DIV(s(x:S),s(y:S)) -> MINUS(x:S,y:S) F(x:S,s(y:S),b:S) -> DIV(f(x:S,minus(s(y:S),s(0)),b:S),b:S) F(x:S,s(y:S),b:S) -> F(x:S,minus(s(y:S),s(0)),b:S) F(x:S,s(y:S),b:S) -> MINUS(s(y:S),s(0)) MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) -> Rules: div(0,s(y:S)) -> 0 div(s(x:S),s(y:S)) -> s(div(minus(x:S,y:S),s(y:S))) f(x:S,0,b:S) -> x:S f(x:S,s(y:S),b:S) -> div(f(x:S,minus(s(y:S),s(0)),b:S),b:S) minus(0,x:S) -> 0 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S minus(x:S,x:S) -> 0 Problem 1: SCC Processor: -> Pairs: DIV(s(x:S),s(y:S)) -> DIV(minus(x:S,y:S),s(y:S)) DIV(s(x:S),s(y:S)) -> MINUS(x:S,y:S) F(x:S,s(y:S),b:S) -> DIV(f(x:S,minus(s(y:S),s(0)),b:S),b:S) F(x:S,s(y:S),b:S) -> F(x:S,minus(s(y:S),s(0)),b:S) F(x:S,s(y:S),b:S) -> MINUS(s(y:S),s(0)) MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) -> Rules: div(0,s(y:S)) -> 0 div(s(x:S),s(y:S)) -> s(div(minus(x:S,y:S),s(y:S))) f(x:S,0,b:S) -> x:S f(x:S,s(y:S),b:S) -> div(f(x:S,minus(s(y:S),s(0)),b:S),b:S) minus(0,x:S) -> 0 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S minus(x:S,x:S) -> 0 ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) ->->-> Rules: div(0,s(y:S)) -> 0 div(s(x:S),s(y:S)) -> s(div(minus(x:S,y:S),s(y:S))) f(x:S,0,b:S) -> x:S f(x:S,s(y:S),b:S) -> div(f(x:S,minus(s(y:S),s(0)),b:S),b:S) minus(0,x:S) -> 0 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S minus(x:S,x:S) -> 0 ->->Cycle: ->->-> Pairs: DIV(s(x:S),s(y:S)) -> DIV(minus(x:S,y:S),s(y:S)) ->->-> Rules: div(0,s(y:S)) -> 0 div(s(x:S),s(y:S)) -> s(div(minus(x:S,y:S),s(y:S))) f(x:S,0,b:S) -> x:S f(x:S,s(y:S),b:S) -> div(f(x:S,minus(s(y:S),s(0)),b:S),b:S) minus(0,x:S) -> 0 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S minus(x:S,x:S) -> 0 ->->Cycle: ->->-> Pairs: F(x:S,s(y:S),b:S) -> F(x:S,minus(s(y:S),s(0)),b:S) ->->-> Rules: div(0,s(y:S)) -> 0 div(s(x:S),s(y:S)) -> s(div(minus(x:S,y:S),s(y:S))) f(x:S,0,b:S) -> x:S f(x:S,s(y:S),b:S) -> div(f(x:S,minus(s(y:S),s(0)),b:S),b:S) minus(0,x:S) -> 0 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S minus(x:S,x:S) -> 0 The problem is decomposed in 3 subproblems. Problem 1.1: Subterm Processor: -> Pairs: popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS Standard