details

property	value
status	complete
benchmark	test10.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n177.star.cs.uiowa.edu
space	Strategy_removed_mixed_05

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	15.0756 seconds
cpu usage	13.221
user time	12.917
system time	0.304038
max virtual memory	1.8484624E7
max residence set size	422120.0

stage attributes

key	value
starexec-result	NO

output

NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 66 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) QDP (8) UsableRulesProof [EQUIVALENT, 0 ms] (9) QDP (10) QDPSizeChangeProof [EQUIVALENT, 0 ms] (11) YES (12) QDP (13) NonLoopProof [COMPLETE, 0 ms] (14) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: h(X, Z) -> f(X, s(X), Z) f(X, Y, g(X, Y)) -> h(0, g(X, Y)) g(0, Y) -> 0 g(X, s(Y)) -> g(X, Y) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(0) = 0 POL(f(x_1, x_2, x_3)) = x_1 + x_2 + x_3 POL(g(x_1, x_2)) = 2 + 2*x_1 + x_2 POL(h(x_1, x_2)) = 2*x_1 + x_2 POL(s(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: g(0, Y) -> 0 ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: h(X, Z) -> f(X, s(X), Z) f(X, Y, g(X, Y)) -> h(0, g(X, Y)) g(X, s(Y)) -> g(X, Y) Q is empty. ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: H(X, Z) -> F(X, s(X), Z) F(X, Y, g(X, Y)) -> H(0, g(X, Y)) G(X, s(Y)) -> G(X, Y) The TRS R consists of the following rules: h(X, Z) -> f(X, s(X), Z) f(X, Y, g(X, Y)) -> h(0, g(X, Y)) g(X, s(Y)) -> g(X, Y) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs. ---------------------------------------- (6) Complex Obligation (AND) popout

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job log

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actions

all output return to TRS Standard