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TRS Standard pair #487073259
details
property
value
status
complete
benchmark
thiemann12.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n173.star.cs.uiowa.edu
space
AProVE_07
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
0.125781 seconds
cpu usage
0.112793
user time
0.06769
system time
0.045103
max virtual memory
113188.0
max residence set size
5784.0
stage attributes
key
value
starexec-result
YES
output
YES Problem 1: (VAR v_NonEmpty:S x:S y:S) (RULES half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> log2(half(x:S),y:S) if(ttrue,x:S,s(y:S)) -> y:S inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) log(x:S) -> log2(x:S,0) log2(x:S,y:S) -> if(le(x:S,s(0)),x:S,inc(y:S)) ) Problem 1: Innermost Equivalent Processor: -> Rules: half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> log2(half(x:S),y:S) if(ttrue,x:S,s(y:S)) -> y:S inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) log(x:S) -> log2(x:S,0) log2(x:S,y:S) -> if(le(x:S,s(0)),x:S,inc(y:S)) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: HALF(s(s(x:S))) -> HALF(x:S) IF(ffalse,x:S,y:S) -> HALF(x:S) IF(ffalse,x:S,y:S) -> LOG2(half(x:S),y:S) INC(s(x:S)) -> INC(x:S) LE(s(x:S),s(y:S)) -> LE(x:S,y:S) LOG(x:S) -> LOG2(x:S,0) LOG2(x:S,y:S) -> IF(le(x:S,s(0)),x:S,inc(y:S)) LOG2(x:S,y:S) -> INC(y:S) LOG2(x:S,y:S) -> LE(x:S,s(0)) -> Rules: half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> log2(half(x:S),y:S) if(ttrue,x:S,s(y:S)) -> y:S inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) log(x:S) -> log2(x:S,0) log2(x:S,y:S) -> if(le(x:S,s(0)),x:S,inc(y:S)) Problem 1: SCC Processor: -> Pairs: HALF(s(s(x:S))) -> HALF(x:S) IF(ffalse,x:S,y:S) -> HALF(x:S) IF(ffalse,x:S,y:S) -> LOG2(half(x:S),y:S) INC(s(x:S)) -> INC(x:S) LE(s(x:S),s(y:S)) -> LE(x:S,y:S) LOG(x:S) -> LOG2(x:S,0) LOG2(x:S,y:S) -> IF(le(x:S,s(0)),x:S,inc(y:S)) LOG2(x:S,y:S) -> INC(y:S) LOG2(x:S,y:S) -> LE(x:S,s(0)) -> Rules: half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S)) if(ffalse,x:S,y:S) -> log2(half(x:S),y:S) if(ttrue,x:S,s(y:S)) -> y:S inc(0) -> 0 inc(s(x:S)) -> s(inc(x:S)) le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) log(x:S) -> log2(x:S,0) log2(x:S,y:S) -> if(le(x:S,s(0)),x:S,inc(y:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: LE(s(x:S),s(y:S)) -> LE(x:S,y:S) ->->-> Rules: half(0) -> 0 half(s(0)) -> 0 half(s(s(x:S))) -> s(half(x:S))
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