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TRS Standard pair #487073667
details
property
value
status
complete
benchmark
TypeEx1.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n192.star.cs.uiowa.edu
space
Applicative_05
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.33037 seconds
cpu usage
4.11485
user time
3.21625
system time
0.8986
max virtual memory
3882844.0
max residence set size
73584.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: ap(ap(ff(),x),x) -> ap(ap(x,ap(ff(),x)),ap(ap(cons(),x),nil())) Proof: Extended Uncurrying Processor: application symbol: ap symbol table: nil ==> nil0/0 cons ==> cons0/0 cons1/1 cons2/2 ff ==> ff0/0 ff1/1 ff2/2 uncurry-rules: ap(ff1(x1),x2) -> ff2(x1,x2) ap(ff0(),x1) -> ff1(x1) ap(cons1(x4),x5) -> cons2(x4,x5) ap(cons0(),x4) -> cons1(x4) eta-rules: problem: ff2(x,x) -> ap(ap(x,ff1(x)),cons2(x,nil0())) ap(ff1(x1),x2) -> ff2(x1,x2) ap(ff0(),x1) -> ff1(x1) ap(cons1(x4),x5) -> cons2(x4,x5) ap(cons0(),x4) -> cons1(x4) DP Processor: DPs: ff{2,#}(x,x) -> ap#(x,ff1(x)) ff{2,#}(x,x) -> ap#(ap(x,ff1(x)),cons2(x,nil0())) ap#(ff1(x1),x2) -> ff{2,#}(x1,x2) TRS: ff2(x,x) -> ap(ap(x,ff1(x)),cons2(x,nil0())) ap(ff1(x1),x2) -> ff2(x1,x2) ap(ff0(),x1) -> ff1(x1) ap(cons1(x4),x5) -> cons2(x4,x5) ap(cons0(),x4) -> cons1(x4) TDG Processor: DPs: ff{2,#}(x,x) -> ap#(x,ff1(x)) ff{2,#}(x,x) -> ap#(ap(x,ff1(x)),cons2(x,nil0())) ap#(ff1(x1),x2) -> ff{2,#}(x1,x2) TRS: ff2(x,x) -> ap(ap(x,ff1(x)),cons2(x,nil0())) ap(ff1(x1),x2) -> ff2(x1,x2) ap(ff0(),x1) -> ff1(x1) ap(cons1(x4),x5) -> cons2(x4,x5) ap(cons0(),x4) -> cons1(x4) graph: ap#(ff1(x1),x2) -> ff{2,#}(x1,x2) -> ff{2,#}(x,x) -> ap#(ap(x,ff1(x)),cons2(x,nil0())) ap#(ff1(x1),x2) -> ff{2,#}(x1,x2) -> ff{2,#}(x,x) -> ap#(x,ff1(x)) ff{2,#}(x,x) -> ap#(ap(x,ff1(x)),cons2(x,nil0())) -> ap#(ff1(x1),x2) -> ff{2,#}(x1,x2) ff{2,#}(x,x) -> ap#(x,ff1(x)) -> ap#(ff1(x1),x2) -> ff{2,#}(x1,x2) Arctic Interpretation Processor: dimension: 1 usable rules: ff2(x,x) -> ap(ap(x,ff1(x)),cons2(x,nil0())) ap(ff1(x1),x2) -> ff2(x1,x2) ap(ff0(),x1) -> ff1(x1) ap(cons1(x4),x5) -> cons2(x4,x5) ap(cons0(),x4) -> cons1(x4) interpretation: [ff0] = 5, [cons1](x0) = 6, [ap](x0, x1) = -4x0 + -8x1 + 0, [ff1](x0) = 1, [nil0] = 14, [cons0] = 10, [ap#](x0, x1) = 1x0 + 1x1 + 0, [ff{2,#}](x0, x1) = 1x1 + 2, [cons2](x0, x1) = -14x1 + 0, [ff2](x0, x1) = -8x1 + 0 orientation: ff{2,#}(x,x) = 1x + 2 >= 1x + 2 = ap#(x,ff1(x)) ff{2,#}(x,x) = 1x + 2 >= -3x + 1 = ap#(ap(x,ff1(x)),cons2(x,nil0())) ap#(ff1(x1),x2) = 1x2 + 2 >= 1x2 + 2 = ff{2,#}(x1,x2) ff2(x,x) = -8x + 0 >= -8x + 0 = ap(ap(x,ff1(x)),cons2(x,nil0())) ap(ff1(x1),x2) = -8x2 + 0 >= -8x2 + 0 = ff2(x1,x2) ap(ff0(),x1) = -8x1 + 1 >= 1 = ff1(x1) ap(cons1(x4),x5) = -8x5 + 2 >= -14x5 + 0 = cons2(x4,x5) ap(cons0(),x4) = -8x4 + 6 >= 6 = cons1(x4)
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