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TRS Standard pair #487073700
details
property
value
status
complete
benchmark
nonTermF.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n187.star.cs.uiowa.edu
space
Applicative_05
run statistics
property
value
solver
NTI-TC20-firstrun
configuration
Default 200
runtime (wallclock)
0.328906 seconds
cpu usage
0.811733
user time
0.760099
system time
0.051634
max virtual memory
113188.0
max residence set size
84012.0
stage attributes
key
value
starexec-result
NO
output
NO Prover = TRS(tech=GUIDED_UNF, nb_unfoldings=unlimited, unfold_variables=true, strategy=LEFTMOST_NE) ** BEGIN proof argument ** The following rule was generated while unfolding the analyzed TRS: [iteration = 2] ap(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),ap(ap(cons,foldr),nil)) -> ap(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),ap(ap(cons,foldr),nil)) Let l be the left-hand side and r be the right-hand side of this rule. Let p = epsilon, theta1 = {} and theta2 = {}. We have r|p = ap(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),ap(ap(cons,foldr),nil)) and theta2(theta1(l)) = theta1(r|p). Hence, the term theta1(l) = ap(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),ap(ap(cons,foldr),nil)) loops w.r.t. the analyzed TRS. ** END proof argument ** ** BEGIN proof description ** ## Searching for a generalized rewrite rule (a rule whose right-hand side contains a variable that does not occur in the left-hand side)... No generalized rewrite rule found! ## Searching for a loop by unfolding (unfolding of variable subterms: ON)... # Iteration 0: no loop detected, 5 unfolded rules generated. # Iteration 1: no loop detected, 39 unfolded rules generated. # Iteration 2: loop detected, 126 unfolded rules generated. Here is the successful unfolding. Let IR be the TRS under analysis. L0 = ap^#(ap(ap(foldr,_0),_1),ap(ap(cons,_2),_3)) -> ap^#(ap(_0,_2),ap(ap(ap(foldr,_0),_1),_3)) is in U_IR^0. Let p0 = [0]. We unfold the rule of L0 forwards at position p0 with the rule ap(ap(f,_0),_0) -> ap(ap(_0,ap(f,_0)),ap(ap(cons,_0),nil)). ==> L1 = ap^#(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),ap(ap(cons,foldr),_0)) -> ap^#(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),ap(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),_0)) is in U_IR^1. Let p1 = [1]. We unfold the rule of L1 forwards at position p1 with the rule ap(ap(ap(foldr,_0),_1),nil) -> _1. ==> L2 = ap^#(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),ap(ap(cons,foldr),nil)) -> ap^#(ap(ap(foldr,ap(f,foldr)),ap(ap(cons,foldr),nil)),ap(ap(cons,foldr),nil)) is in U_IR^2. ** END proof description ** Proof stopped at iteration 2 Number of unfolded rules generated by this proof = 170 Number of unfolded rules generated by all the parallel proofs = 170
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