details

property	value
status	complete
benchmark	17.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n183.star.cs.uiowa.edu
space	Der95

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.482592 seconds
cpu usage	0.911201
user time	0.69649
system time	0.214711
max virtual memory	96176.0
max residence set size	61204.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: .(1(),x) -> x .(x,1()) -> x .(i(x),x) -> 1() .(x,i(x)) -> 1() i(1()) -> 1() i(i(x)) -> x .(i(y),.(y,z)) -> z .(y,.(i(y),z)) -> z .(.(x,y),z) -> .(x,.(y,z)) i(.(x,y)) -> .(i(y),i(x)) Proof: Matrix Interpretation Processor: dim=1 interpretation: [.](x0, x1) = x0 + x1 + 2, [1] = 1, [i](x0) = x0 orientation: .(1(),x) = x + 3 >= x = x .(x,1()) = x + 3 >= x = x .(i(x),x) = 2x + 2 >= 1 = 1() .(x,i(x)) = 2x + 2 >= 1 = 1() i(1()) = 1 >= 1 = 1() i(i(x)) = x >= x = x .(i(y),.(y,z)) = 2y + z + 4 >= z = z .(y,.(i(y),z)) = 2y + z + 4 >= z = z .(.(x,y),z) = x + y + z + 4 >= x + y + z + 4 = .(x,.(y,z)) i(.(x,y)) = x + y + 2 >= x + y + 2 = .(i(y),i(x)) problem: i(1()) -> 1() i(i(x)) -> x .(.(x,y),z) -> .(x,.(y,z)) i(.(x,y)) -> .(i(y),i(x)) Matrix Interpretation Processor: dim=1 interpretation: [.](x0, x1) = x0 + x1 + 2, [1] = 0, [i](x0) = 4x0 orientation: i(1()) = 0 >= 0 = 1() i(i(x)) = 16x >= x = x .(.(x,y),z) = x + y + z + 4 >= x + y + z + 4 = .(x,.(y,z)) i(.(x,y)) = 4x + 4y + 8 >= 4x + 4y + 2 = .(i(y),i(x)) problem: i(1()) -> 1() i(i(x)) -> x .(.(x,y),z) -> .(x,.(y,z)) Matrix Interpretation Processor: dim=1 interpretation: [.](x0, x1) = 4x0 + x1 + 4, [1] = 0, [i](x0) = 3x0 + 6 orientation: i(1()) = 6 >= 0 = 1() i(i(x)) = 9x + 24 >= x = x .(.(x,y),z) = 16x + 4y + z + 20 >= 4x + 4y + z + 8 = .(x,.(y,z)) problem: Qed popout

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all output return to TRS Standard