details

property	value
status	complete
benchmark	17.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n192.star.cs.uiowa.edu
space	Der95

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	0.018487 seconds
cpu usage	0.018912
user time	0.004385
system time	0.014527
max virtual memory	113188.0
max residence set size	5328.0

stage attributes

key	value
starexec-result	YES

output

YES Problem 1: (VAR v_NonEmpty:S x:S y:S z:S) (RULES .(.(x:S,y:S),z:S) -> .(x:S,.(y:S,z:S)) .(i(x:S),x:S) -> 1 .(i(y:S),.(y:S,z:S)) -> z:S .(1,x:S) -> x:S .(x:S,i(x:S)) -> 1 .(x:S,1) -> x:S .(y:S,.(i(y:S),z:S)) -> z:S i(.(x:S,y:S)) -> .(i(y:S),i(x:S)) i(i(x:S)) -> x:S i(1) -> 1 ) Problem 1: Dependency Pairs Processor: -> Pairs: .#(.(x:S,y:S),z:S) -> .#(x:S,.(y:S,z:S)) .#(.(x:S,y:S),z:S) -> .#(y:S,z:S) I(.(x:S,y:S)) -> .#(i(y:S),i(x:S)) I(.(x:S,y:S)) -> I(x:S) I(.(x:S,y:S)) -> I(y:S) -> Rules: .(.(x:S,y:S),z:S) -> .(x:S,.(y:S,z:S)) .(i(x:S),x:S) -> 1 .(i(y:S),.(y:S,z:S)) -> z:S .(1,x:S) -> x:S .(x:S,i(x:S)) -> 1 .(x:S,1) -> x:S .(y:S,.(i(y:S),z:S)) -> z:S i(.(x:S,y:S)) -> .(i(y:S),i(x:S)) i(i(x:S)) -> x:S i(1) -> 1 Problem 1: SCC Processor: -> Pairs: .#(.(x:S,y:S),z:S) -> .#(x:S,.(y:S,z:S)) .#(.(x:S,y:S),z:S) -> .#(y:S,z:S) I(.(x:S,y:S)) -> .#(i(y:S),i(x:S)) I(.(x:S,y:S)) -> I(x:S) I(.(x:S,y:S)) -> I(y:S) -> Rules: .(.(x:S,y:S),z:S) -> .(x:S,.(y:S,z:S)) .(i(x:S),x:S) -> 1 .(i(y:S),.(y:S,z:S)) -> z:S .(1,x:S) -> x:S .(x:S,i(x:S)) -> 1 .(x:S,1) -> x:S .(y:S,.(i(y:S),z:S)) -> z:S i(.(x:S,y:S)) -> .(i(y:S),i(x:S)) i(i(x:S)) -> x:S i(1) -> 1 ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: .#(.(x:S,y:S),z:S) -> .#(x:S,.(y:S,z:S)) .#(.(x:S,y:S),z:S) -> .#(y:S,z:S) ->->-> Rules: .(.(x:S,y:S),z:S) -> .(x:S,.(y:S,z:S)) .(i(x:S),x:S) -> 1 .(i(y:S),.(y:S,z:S)) -> z:S .(1,x:S) -> x:S .(x:S,i(x:S)) -> 1 .(x:S,1) -> x:S .(y:S,.(i(y:S),z:S)) -> z:S i(.(x:S,y:S)) -> .(i(y:S),i(x:S)) i(i(x:S)) -> x:S i(1) -> 1 ->->Cycle: ->->-> Pairs: I(.(x:S,y:S)) -> I(x:S) I(.(x:S,y:S)) -> I(y:S) ->->-> Rules: .(.(x:S,y:S),z:S) -> .(x:S,.(y:S,z:S)) .(i(x:S),x:S) -> 1 .(i(y:S),.(y:S,z:S)) -> z:S .(1,x:S) -> x:S .(x:S,i(x:S)) -> 1 .(x:S,1) -> x:S .(y:S,.(i(y:S),z:S)) -> z:S i(.(x:S,y:S)) -> .(i(y:S),i(x:S)) i(i(x:S)) -> x:S i(1) -> 1 The problem is decomposed in 2 subproblems. Problem 1.1: Subterm Processor: -> Pairs: .#(.(x:S,y:S),z:S) -> .#(x:S,.(y:S,z:S)) .#(.(x:S,y:S),z:S) -> .#(y:S,z:S) popout

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job log

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actions

all output return to TRS Standard