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TRS Relative pair #487081689
details
property
value
status
complete
benchmark
ex7.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n151.star.cs.uiowa.edu
space
INVY_15
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.87859 seconds
cpu usage
3.81188
user time
3.60919
system time
0.202693
max virtual memory
1.9207336E7
max residence set size
259604.0
stage attributes
key
value
starexec-result
NO
output
NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given RelTRS could be disproven: (0) RelTRS (1) RelTRSLoopFinderProof [COMPLETE, 0 ms] (2) NO ---------------------------------------- (0) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: f(s(x)) -> f(x) The relative TRS consists of the following S rules: inf -> s(inf) ---------------------------------------- (1) RelTRSLoopFinderProof (COMPLETE) The following loop was found: ---------- Loop: ---------- f(inf) -> f(s(inf)) with rule inf -> s(inf) at position [0] and matcher [ ] f(s(inf)) -> f(inf) with rule f(s(x)) -> f(x) at position [] and matcher [x / inf] Now an instance of the first term with Matcher [ ] occurs in the last term at position []. Context: [] Therefore, the relative TRS problem does not terminate. ---------------------------------------- (2) NO
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