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TRS Relative pair #487081838
details
property
value
status
complete
benchmark
ijcar2006.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n148.star.cs.uiowa.edu
space
Mixed_relative_TRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.952735 seconds
cpu usage
2.74019
user time
1.91977
system time
0.82042
max virtual memory
963104.0
max residence set size
62792.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: strict: f(a(),g(y),z) -> f(a(),y,g(y)) f(b(),g(y),z) -> f(a(),y,z) a() -> b() weak: f(x,y,z) -> f(x,y,g(z)) Proof: Matrix Interpretation Processor: dim=2 interpretation: [1 0] [0] [g](x0) = [2 1]x0 + [1], [0] [b] = [1], [0] [a] = [1], [2 1] [1 1] [2 0] [0] [f](x0, x1, x2) = [0 2]x0 + [0 0]x1 + [0 0]x2 + [1] orientation: [3 1] [2 0] [2] [3 1] [1] f(a(),g(y),z) = [0 0]y + [0 0]z + [3] >= [0 0]y + [3] = f(a(),y,g(y)) [3 1] [2 0] [2] [1 1] [2 0] [1] f(b(),g(y),z) = [0 0]y + [0 0]z + [3] >= [0 0]y + [0 0]z + [3] = f(a(),y,z) [0] [0] a() = [1] >= [1] = b() [2 1] [1 1] [2 0] [0] [2 1] [1 1] [2 0] [0] f(x,y,z) = [0 2]x + [0 0]y + [0 0]z + [1] >= [0 2]x + [0 0]y + [0 0]z + [1] = f(x,y,g(z)) problem: strict: a() -> b() weak: f(x,y,z) -> f(x,y,g(z)) Matrix Interpretation Processor: dim=5 interpretation: [1 0 0 0 0] [0 0 0 0 0] [g](x0) = [0 0 0 0 0]x0 [0 0 0 0 0] [0 0 0 0 0] , [0] [0] [b] = [0] [0] [0], [1] [0] [a] = [0] [0] [0], [1 0 0 0 0] [1 0 0 0 0] [1 0 0 0 0] [0] [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] [f](x0, x1, x2) = [0 0 0 0 0]x0 + [0 0 0 0 0]x1 + [0 1 0 0 0]x2 + [1] [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] orientation: [1] [0] [0] [0] a() = [0] >= [0] = b() [0] [0] [0] [0] [1 0 0 0 0] [1 0 0 0 0] [1 0 0 0 0] [0] [1 0 0 0 0] [1 0 0 0 0] [1 0 0 0 0] [0] [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] f(x,y,z) = [0 0 0 0 0]x + [0 0 0 0 0]y + [0 1 0 0 0]z + [1] >= [0 0 0 0 0]x + [0 0 0 0 0]y + [0 0 0 0 0]z + [1] = f(x,y,g(z)) [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] [0 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [0] problem: strict: weak: f(x,y,z) -> f(x,y,g(z)) Qed
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