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TRS Relative pair #487081865
details
property
value
status
complete
benchmark
rt3-9.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n145.star.cs.uiowa.edu
space
Relative_05
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.42078 seconds
cpu usage
4.56485
user time
3.43816
system time
1.12669
max virtual memory
4067648.0
max residence set size
67584.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: strict: l(m(x)) -> m(l(x)) m(r(x)) -> r(m(x)) f(m(x),y) -> f(x,m(y)) weak: b() -> l(b()) f(x,y) -> f(x,r(y)) Proof: Bounds Processor: bound: 1 enrichment: match-rt automaton: final states: {6} transitions: m0(6) -> 6* f0(6,6) -> 6* r0(6) -> 6* f1(6,20) -> 6* r1(20) -> 20* r1(6) -> 20* l0(6) -> 6* b0() -> 6* l1(39) -> 39,6 m1(20) -> 20* m1(6) -> 20* b1() -> 39* problem: strict: l(m(x)) -> m(l(x)) m(r(x)) -> r(m(x)) weak: b() -> l(b()) f(x,y) -> f(x,r(y)) Matrix Interpretation Processor: dim=2 interpretation: [0] [b] = [1], [1 0] [l](x0) = [0 0]x0, [2 0] [1 0] [f](x0, x1) = [0 0]x0 + [0 0]x1, [2 2] [m](x0) = [0 1]x0, [0] [r](x0) = x0 + [1] orientation: [2 2] [2 0] l(m(x)) = [0 0]x >= [0 0]x = m(l(x)) [2 2] [2] [2 2] [0] m(r(x)) = [0 1]x + [1] >= [0 1]x + [1] = r(m(x)) [0] [0] b() = [1] >= [0] = l(b()) [2 0] [1 0] [2 0] [1 0] f(x,y) = [0 0]x + [0 0]y >= [0 0]x + [0 0]y = f(x,r(y)) problem: strict: l(m(x)) -> m(l(x)) weak: b() -> l(b()) f(x,y) -> f(x,r(y)) Matrix Interpretation Processor: dim=2 interpretation: [0] [b] = [0], [2 2] [l](x0) = [0 2]x0, [2 0] [2 0] [2] [f](x0, x1) = [0 0]x0 + [0 1]x1 + [0], [0] [m](x0) = x0 + [1], [r](x0) = x0 orientation: [2 2] [2] [2 2] [0] l(m(x)) = [0 2]x + [2] >= [0 2]x + [1] = m(l(x)) [0] [0] b() = [0] >= [0] = l(b()) [2 0] [2 0] [2] [2 0] [2 0] [2] f(x,y) = [0 0]x + [0 1]y + [0] >= [0 0]x + [0 1]y + [0] = f(x,r(y)) problem: strict:
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