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SRS Relative pair #487082813
details
property
value
status
complete
benchmark
88172.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n146.star.cs.uiowa.edu
space
ICFP_2010_relative
run statistics
property
value
solver
MultumNonMulta 20 June 2020 20G sparse
configuration
default
runtime (wallclock)
0.969399 seconds
cpu usage
2.82061
user time
2.49618
system time
0.32443
max virtual memory
2.512166E7
max residence set size
617312.0
stage attributes
key
value
starexec-result
YES
output
YES After renaming modulo { 0->0, 1->1, 2->2, 3->3 }, it remains to prove termination of the 30-rule system { 0 0 0 0 0 1 1 2 0 0 3 1 3 -> 2 3 3 1 1 2 3 1 2 1 1 2 2 1 0 2 3 , 0 0 0 3 1 2 2 3 2 3 1 0 1 -> 3 2 1 3 0 1 3 1 1 2 1 3 3 3 3 1 3 , 0 0 3 0 1 1 2 1 0 1 3 3 3 -> 1 3 3 1 0 2 1 1 2 2 3 2 1 2 1 1 3 , 0 0 3 2 1 3 2 2 3 2 0 0 0 -> 1 2 1 3 2 3 2 2 3 3 1 0 0 2 1 3 3 , 0 3 0 1 3 1 3 2 2 1 2 2 0 -> 2 3 3 0 3 3 3 1 3 2 0 2 2 1 3 1 2 , 0 3 2 2 0 0 3 2 3 1 1 2 1 -> 2 0 3 3 1 2 0 3 1 2 1 2 1 1 0 3 1 , 0 3 3 3 0 1 2 3 1 1 0 0 3 -> 0 2 2 0 1 2 1 2 1 3 1 3 0 3 3 0 3 , 1 0 1 3 1 1 1 1 3 2 0 3 2 -> 3 3 3 1 3 3 0 1 0 1 2 1 2 1 1 0 3 , 1 0 3 2 3 3 0 0 1 2 1 0 1 -> 2 1 1 1 1 3 2 2 2 1 3 3 1 3 2 2 1 , 1 1 0 0 0 2 3 0 1 2 0 1 3 -> 1 2 2 2 1 3 3 2 1 1 2 1 0 2 0 2 3 , 1 1 2 1 0 2 2 0 3 0 0 0 0 -> 2 2 1 3 3 3 1 2 0 1 0 2 3 1 1 0 3 , 1 3 2 3 1 1 2 0 1 2 3 1 0 -> 1 3 2 2 0 2 3 3 0 1 2 1 2 2 1 3 1 , 2 0 3 3 3 2 2 3 2 0 0 3 3 -> 3 3 2 2 0 1 1 2 1 1 2 1 2 2 1 3 3 , 2 1 2 0 2 1 0 1 1 0 1 2 0 -> 0 0 1 1 3 3 1 1 0 0 3 3 3 3 3 3 2 , 2 2 3 1 3 2 2 0 2 2 2 2 0 -> 2 1 3 0 1 3 2 2 1 0 0 2 1 1 3 0 0 , 2 3 0 3 0 2 1 2 0 3 2 0 1 -> 2 1 3 3 0 2 2 1 3 2 0 2 2 2 1 2 1 , 2 3 1 0 1 0 0 1 1 0 1 2 1 -> 1 3 1 3 3 3 3 2 2 1 3 1 2 1 1 0 3 , 2 3 3 1 2 2 3 0 2 2 0 0 1 -> 2 3 1 2 2 1 1 3 1 3 3 3 3 0 3 0 0 , 2 3 3 1 2 2 3 2 3 1 1 0 1 -> 2 2 1 0 2 1 1 1 2 2 1 1 3 3 2 1 3 , 3 0 3 0 2 3 2 3 3 3 1 2 1 -> 2 1 2 1 3 2 1 3 2 1 2 1 3 1 3 3 1 , 3 0 3 0 2 3 3 2 3 2 2 2 1 -> 2 2 2 1 3 3 3 2 1 1 2 1 1 1 1 3 1 , 3 0 3 1 3 2 0 0 1 2 1 0 0 -> 3 1 3 0 3 3 2 2 1 1 2 2 2 1 1 0 2 , 3 1 2 3 1 1 3 1 1 3 0 1 1 -> 3 3 2 1 3 1 2 3 3 3 2 1 1 2 1 0 1 , 3 2 2 1 0 2 0 3 3 3 3 2 1 -> 3 3 3 2 3 1 1 3 3 2 1 2 1 2 1 3 1 , 3 2 3 0 1 1 3 0 0 0 0 2 1 -> 3 3 2 1 1 2 3 2 1 2 0 3 1 3 2 2 1 , 3 2 3 2 3 2 3 0 3 2 0 1 1 -> 2 2 1 1 2 1 3 3 2 0 0 0 0 0 1 3 3 , 3 3 1 3 1 2 3 2 0 2 2 0 0 -> 2 1 2 1 3 0 2 2 0 2 2 1 1 3 3 3 3 , 3 3 2 1 3 1 2 0 0 3 2 3 3 -> 3 2 1 3 2 2 1 3 3 3 1 0 2 1 3 3 3 , 3 1 2 0 1 0 3 2 0 1 2 0 0 ->= 3 1 1 2 1 0 1 1 2 2 1 2 1 3 0 2 3 , 3 3 3 1 2 1 2 2 3 0 0 0 3 ->= 3 3 3 1 2 1 1 2 1 1 0 3 3 2 2 0 3 } The system was reversed. After renaming modulo { 3->0, 1->1, 0->2, 2->3 }, it remains to prove termination of the 30-rule system { 0 1 0 2 2 3 1 1 2 2 2 2 2 -> 0 3 2 1 3 3 1 1 3 1 0 3 1 1 0 0 3 , 1 2 1 0 3 0 3 3 1 0 2 2 2 -> 0 1 0 0 0 0 1 3 1 1 0 1 2 0 1 3 0 , 0 0 0 1 2 1 3 1 1 2 0 2 2 -> 0 1 1 3 1 3 0 3 3 1 1 3 2 1 0 0 1 , 2 2 2 3 0 3 3 0 1 3 0 2 2 -> 0 0 1 3 2 2 1 0 0 3 3 0 3 0 1 3 1 , 2 3 3 1 3 3 0 1 0 1 2 0 2 -> 3 1 0 1 3 3 2 3 0 1 0 0 0 2 0 0 3 , 1 3 1 1 0 3 0 2 2 3 3 0 2 -> 1 0 2 1 1 3 1 3 1 0 2 3 1 0 0 2 3 , 0 2 2 1 1 0 3 1 2 0 0 0 2 -> 0 2 0 0 2 0 1 0 1 3 1 3 1 2 3 3 2 , 3 0 2 3 0 1 1 1 1 0 1 2 1 -> 0 2 1 1 3 1 3 1 2 1 2 0 0 1 0 0 0 , 1 2 1 3 1 2 2 0 0 3 0 2 1 -> 1 3 3 0 1 0 0 1 3 3 3 0 1 1 1 1 3 , 0 1 2 3 1 2 0 3 2 2 2 1 1 -> 0 3 2 3 2 1 3 1 1 3 0 0 1 3 3 3 1 , 2 2 2 2 0 2 3 3 2 1 3 1 1 -> 0 2 1 1 0 3 2 1 2 3 1 0 0 0 1 3 3 , 2 1 0 3 1 2 3 1 1 0 3 0 1 -> 1 0 1 3 3 1 3 1 2 0 0 3 2 3 3 0 1 , 0 0 2 2 3 0 3 3 0 0 0 2 3 -> 0 0 1 3 3 1 3 1 1 3 1 1 2 3 3 0 0 , 2 3 1 2 1 1 2 1 3 2 3 1 3 -> 3 0 0 0 0 0 0 2 2 1 1 0 0 1 1 2 2 , 2 3 3 3 3 2 3 3 0 1 0 3 3 -> 2 2 0 1 1 3 2 2 1 3 3 0 1 2 0 1 3 , 1 2 3 0 2 3 1 3 2 0 2 0 3 -> 1 3 1 3 3 3 2 3 0 1 3 3 2 0 0 1 3 , 1 3 1 2 1 1 2 2 1 2 1 0 3 -> 0 2 1 1 3 1 0 1 3 3 0 0 0 0 1 0 1 , 1 2 2 3 3 2 0 3 3 1 0 0 3 -> 2 2 0 2 0 0 0 0 1 0 1 1 3 3 1 0 3 , 1 2 1 1 0 3 0 3 3 1 0 0 3 -> 0 1 3 0 0 1 1 3 3 1 1 1 3 2 1 3 3 , 1 3 1 0 0 0 3 0 3 2 0 2 0 -> 1 0 0 1 0 1 3 1 3 0 1 3 0 1 3 1 3 , 1 3 3 3 0 3 0 0 3 2 0 2 0 -> 1 0 1 1 1 1 3 1 1 3 0 0 0 1 3 3 3 , 2 2 1 3 1 2 2 3 0 1 0 2 0 -> 3 2 1 1 3 3 3 1 1 3 3 0 0 2 0 1 0 , 1 1 2 0 1 1 0 1 1 0 3 1 0 -> 1 2 1 3 1 1 3 0 0 0 3 1 0 1 3 0 0 , 1 3 0 0 0 0 2 3 2 1 3 3 0 -> 1 0 1 3 1 3 1 3 0 0 1 1 0 3 0 0 0 , 1 3 2 2 2 2 0 1 1 2 0 3 0 -> 1 3 3 0 1 0 2 3 1 3 0 3 1 1 3 0 0 , 1 1 2 3 0 2 0 3 0 3 0 3 0 -> 0 0 1 2 2 2 2 2 3 0 0 1 3 1 1 3 3 , 2 2 3 3 2 3 0 3 1 0 1 0 0 -> 0 0 0 0 1 1 3 3 2 3 3 2 0 1 3 1 3 , 0 0 3 0 2 2 3 1 0 1 3 0 0 -> 0 0 0 1 3 2 1 0 0 0 1 3 3 0 1 3 0 , 2 2 3 1 2 3 0 2 1 2 3 1 0 ->= 0 3 2 0 1 3 1 3 3 1 1 2 1 3 1 1 0 , 0 2 2 2 0 3 3 1 3 1 0 0 0 ->= 0 2 3 3 0 0 2 1 1 3 1 1 3 1 0 0 0 } Applying context closure of depth 1 in the following form: System R over Sigma maps to { fold(xly) -> fold(xry) | l -> r in R, x,y in Sigma } over Sigma^2, where fold(a_1...a_n) = (a_1,a_2)...(a_{n-1},a_{n}) After renaming modulo { [0, 0]->0, [0, 1]->1, [1, 0]->2, [0, 2]->3, [2, 2]->4, [2, 3]->5, [3, 1]->6, [1, 1]->7, [1, 2]->8, [2, 0]->9, [0, 3]->10, [3, 2]->11, [2, 1]->12, [1, 3]->13, [3, 3]->14, [3, 0]->15 }, it remains to prove termination of the 480-rule system { 0 1 2 3 4 5 6 7 8 4 4 4 4 9 -> 0 10 11 12 13 14 6 7 13 6 2 10 6 7 2 0 10 15 , 1 8 12 2 10 15 10 14 6 2 3 4 4 9 -> 0 1 2 0 0 0 1 13 6 7 2 1 8 9 1 13 15 0 , 0 0 0 1 8 12 13 6 7 8 9 3 4 9 -> 0 1 7 13 6 13 15 10 14 6 7 13 11 12 2 0 1 2 , 3 4 4 5 15 10 14 15 1 13 15 3 4 9 -> 0 0 1 13 11 4 12 2 0 10 14 15 10 15 1 13 6 2 , 3 5 14 6 13 14 15 1 2 1 8 9 3 9 -> 10 6 2 1 13 14 11 5 15 1 2 0 0 3 9 0 10 15 , 1 13 6 7 2 10 15 3 4 5 14 15 3 9 -> 1 2 3 12 7 13 6 13 6 2 3 5 6 2 0 3 5 15 , 0 3 4 12 7 2 10 6 8 9 0 0 3 9 -> 0 3 9 0 3 9 1 2 1 13 6 13 6 8 5 14 11 9 , 10 15 3 5 15 1 7 7 7 2 1 8 12 2 -> 0 3 12 7 13 6 13 6 8 12 8 9 0 1 2 0 0 0 , 1 8 12 13 6 8 4 9 0 10 15 3 12 2 -> 1 13 14 15 1 2 0 1 13 14 14 15 1 7 7 7 13 15 , 0 1 8 5 6 8 9 10 11 4 4 12 7 2 -> 0 10 11 5 11 12 13 6 7 13 15 0 1 13 14 14 6 2 , 3 4 4 4 9 3 5 14 11 12 13 6 7 2 -> 0 3 12 7 2 10 11 12 8 5 6 2 0 0 1 13 14 15 , 3 12 2 10 6 8 5 6 7 2 10 15 1 2 -> 1 2 1 13 14 6 13 6 8 9 0 10 11 5 14 15 1 2 , 0 0 3 4 5 15 10 14 15 0 0 3 5 15 -> 0 0 1 13 14 6 13 6 7 13 6 7 8 5 14 15 0 0 , 3 5 6 8 12 7 8 12 13 11 5 6 13 15 -> 10 15 0 0 0 0 0 3 4 12 7 2 0 1 7 8 4 9 , 3 5 14 14 14 11 5 14 15 1 2 10 14 15 -> 3 4 9 1 7 13 11 4 12 13 14 15 1 8 9 1 13 15 , 1 8 5 15 3 5 6 13 11 9 3 9 10 15 -> 1 13 6 13 14 14 11 5 15 1 13 14 11 9 0 1 13 15 , 1 13 6 8 12 7 8 4 12 8 12 2 10 15 -> 0 3 12 7 13 6 2 1 13 14 15 0 0 0 1 2 1 2 , 1 8 4 5 14 11 9 10 14 6 2 0 10 15 -> 3 4 9 3 9 0 0 0 1 2 1 7 13 14 6 2 10 15 , 1 8 12 7 2 10 15 10 14 6 2 0 10 15 -> 0 1 13 15 0 1 7 13 14 6 7 7 13 11 12 13 14 15 , 1 13 6 2 0 0 10 15 10 11 9 3 9 0 -> 1 2 0 1 2 1 13 6 13 15 1 13 15 1 13 6 13 15 , 1 13 14 14 15 10 15 0 10 11 9 3 9 0 -> 1 2 1 7 7 7 13 6 7 13 15 0 0 1 13 14 14 15 , 3 4 12 13 6 8 4 5 15 1 2 3 9 0 -> 10 11 12 7 13 14 14 6 7 13 14 15 0 3 9 1 2 0 ,
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