SRS Standard pair #487083215

details

property	value
status	complete
benchmark	x04.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n142.star.cs.uiowa.edu
space	Secret_07_SRS

run statistics

property	value
solver	MultumNonMulta 20 June 2020 20G sparse
configuration	default
runtime (wallclock)	2.89185 seconds
cpu usage	9.97142
user time	9.27459
system time	0.696822
max virtual memory	2.6442624E7
max residence set size	1374564.0

stage attributes

key	value
starexec-result	YES

output

YES

After renaming modulo { a->0, b->1, c->2, d->3 }, 
it remains to prove termination of the 8-rule system
{ 0 0 -> 0 1 0 1 0 ,
  2 0 -> 0 1 0 0 2 ,
  1 1 1 -> 0 1 ,
  2 1 -> 0 0 2 ,
  2 1 -> 1 0 3 ,
  3 3 -> 3 1 3 1 3 ,
  2 2 -> 2 3 2 ,
  0 0 0 -> 0 1 1 }


The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 2:

0 is interpreted by
 /   \
| 1 0 |
| 0 1 |
 \   /
1 is interpreted by
 /   \
| 1 0 |
| 0 1 |
 \   /
2 is interpreted by
 /   \
| 1 1 |
| 0 1 |
 \   /
3 is interpreted by
 /   \
| 1 0 |
| 0 1 |
 \   /

After renaming modulo { 0->0, 1->1, 2->2, 3->3 }, 
it remains to prove termination of the 7-rule system
{ 0 0 -> 0 1 0 1 0 ,
  2 0 -> 0 1 0 0 2 ,
  1 1 1 -> 0 1 ,
  2 1 -> 0 0 2 ,
  3 3 -> 3 1 3 1 3 ,
  2 2 -> 2 3 2 ,
  0 0 0 -> 0 1 1 }


The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 3:

0 is interpreted by
 /     \
| 1 0 0 |
| 0 1 0 |
| 0 0 0 |
 \     /
1 is interpreted by
 /     \
| 1 0 0 |
| 0 1 0 |
| 0 0 0 |
 \     /
2 is interpreted by
 /     \
| 1 0 0 |
| 0 1 0 |
| 0 0 0 |
 \     /
3 is interpreted by
 /     \
| 1 0 1 |
| 0 1 0 |
| 0 1 0 |
 \     /

After renaming modulo { 0->0, 1->1, 2->2, 3->3 }, 
it remains to prove termination of the 6-rule system
{ 0 0 -> 0 1 0 1 0 ,
  2 0 -> 0 1 0 0 2 ,
  1 1 1 -> 0 1 ,
  2 1 -> 0 0 2 ,
  2 2 -> 2 3 2 ,
  0 0 0 -> 0 1 1 }


The system was reversed.

After renaming modulo { 0->0, 1->1, 2->2, 3->3 }, 
it remains to prove termination of the 6-rule system
{ 0 0 -> 0 1 0 1 0 ,
  0 2 -> 2 0 0 1 0 ,
  1 1 1 -> 1 0 ,
  1 2 -> 2 0 0 ,
  2 2 -> 2 3 2 ,
  0 0 0 -> 1 1 0 }


Applying the dependency pairs transformation.

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job log

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