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SRS Standard pair #487083272
details
property
value
status
complete
benchmark
e.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n145.star.cs.uiowa.edu
space
Waldmann_06_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
5.45721 seconds
cpu usage
20.2299
user time
17.1687
system time
3.06112
max virtual memory
6098816.0
max residence set size
77880.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: 2(7(x1)) -> 1(8(x1)) 2(8(1(x1))) -> 8(x1) 2(8(x1)) -> 4(x1) 5(9(x1)) -> 0(x1) 4(x1) -> 5(2(3(x1))) 5(3(x1)) -> 6(0(x1)) 2(8(x1)) -> 7(x1) 4(7(x1)) -> 1(3(x1)) 5(2(6(x1))) -> 6(2(4(x1))) 9(7(x1)) -> 7(5(x1)) 7(2(x1)) -> 4(x1) 7(0(x1)) -> 9(3(x1)) 6(9(x1)) -> 9(x1) 9(5(9(x1))) -> 5(7(x1)) 4(x1) -> 9(6(6(x1))) 9(x1) -> 6(7(x1)) 6(2(x1)) -> 7(7(x1)) 2(4(x1)) -> 0(7(x1)) 6(6(x1)) -> 3(x1) 0(3(x1)) -> 5(3(x1)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [4](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [3](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [2](x0) = [0 1 0]x0 [0 0 0] , [1 0 0] [1](x0) = [0 0 0]x0 [0 0 1] , [1 0 0] [9](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [7](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [0](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [6](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [5](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [0] [8](x0) = [1 0 1]x0 + [1] [0 0 0] [0] orientation: [1 0 0] [1 0 0] 2(7(x1)) = [0 0 0]x1 >= [0 0 0]x1 = 1(8(x1)) [0 0 0] [0 0 0] [2 0 1] [1] [1 0 0] [0] 2(8(1(x1))) = [1 0 1]x1 + [1] >= [1 0 1]x1 + [1] = 8(x1) [0 0 0] [0] [0 0 0] [0] [2 0 1] [1] [1 0 0] 2(8(x1)) = [1 0 1]x1 + [1] >= [0 0 0]x1 = 4(x1) [0 0 0] [0] [0 0 0] [1 0 0] [1 0 0] 5(9(x1)) = [0 0 0]x1 >= [0 0 0]x1 = 0(x1) [0 0 0] [0 0 0] [1 0 0] [1 0 0] 4(x1) = [0 0 0]x1 >= [0 0 0]x1 = 5(2(3(x1))) [0 0 0] [0 0 0] [1 0 0] [1 0 0] 5(3(x1)) = [0 0 0]x1 >= [0 0 0]x1 = 6(0(x1)) [0 0 0] [0 0 0] [2 0 1] [1] [1 0 0] 2(8(x1)) = [1 0 1]x1 + [1] >= [0 0 0]x1 = 7(x1) [0 0 0] [0] [0 0 0] [1 0 0] [1 0 0] 4(7(x1)) = [0 0 0]x1 >= [0 0 0]x1 = 1(3(x1)) [0 0 0] [0 0 0]
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