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SRS Standard pair #487084742
details
property
value
status
complete
benchmark
size-12-alpha-3-num-113.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n142.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
43.4185 seconds
cpu usage
169.861
user time
166.91
system time
2.95076
max virtual memory
1.1281676E7
max residence set size
127580.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(x1) -> x1 a(a(b(x1))) -> b(b(c(a(a(a(x1)))))) c(a(x1)) -> x1 Proof: String Reversal Processor: a(x1) -> x1 b(a(a(x1))) -> a(a(a(c(b(b(x1)))))) a(c(x1)) -> x1 DP Processor: DPs: b#(a(a(x1))) -> b#(x1) b#(a(a(x1))) -> b#(b(x1)) b#(a(a(x1))) -> a#(c(b(b(x1)))) b#(a(a(x1))) -> a#(a(c(b(b(x1))))) b#(a(a(x1))) -> a#(a(a(c(b(b(x1)))))) TRS: a(x1) -> x1 b(a(a(x1))) -> a(a(a(c(b(b(x1)))))) a(c(x1)) -> x1 TDG Processor: DPs: b#(a(a(x1))) -> b#(x1) b#(a(a(x1))) -> b#(b(x1)) b#(a(a(x1))) -> a#(c(b(b(x1)))) b#(a(a(x1))) -> a#(a(c(b(b(x1))))) b#(a(a(x1))) -> a#(a(a(c(b(b(x1)))))) TRS: a(x1) -> x1 b(a(a(x1))) -> a(a(a(c(b(b(x1)))))) a(c(x1)) -> x1 graph: b#(a(a(x1))) -> b#(b(x1)) -> b#(a(a(x1))) -> a#(a(a(c(b(b(x1)))))) b#(a(a(x1))) -> b#(b(x1)) -> b#(a(a(x1))) -> a#(a(c(b(b(x1))))) b#(a(a(x1))) -> b#(b(x1)) -> b#(a(a(x1))) -> a#(c(b(b(x1)))) b#(a(a(x1))) -> b#(b(x1)) -> b#(a(a(x1))) -> b#(b(x1)) b#(a(a(x1))) -> b#(b(x1)) -> b#(a(a(x1))) -> b#(x1) b#(a(a(x1))) -> b#(x1) -> b#(a(a(x1))) -> a#(a(a(c(b(b(x1)))))) b#(a(a(x1))) -> b#(x1) -> b#(a(a(x1))) -> a#(a(c(b(b(x1))))) b#(a(a(x1))) -> b#(x1) -> b#(a(a(x1))) -> a#(c(b(b(x1)))) b#(a(a(x1))) -> b#(x1) -> b#(a(a(x1))) -> b#(b(x1)) b#(a(a(x1))) -> b#(x1) -> b#(a(a(x1))) -> b#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 10/25 DPs: b#(a(a(x1))) -> b#(b(x1)) b#(a(a(x1))) -> b#(x1) TRS: a(x1) -> x1 b(a(a(x1))) -> a(a(a(c(b(b(x1)))))) a(c(x1)) -> x1 Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 b(a(a(x1))) -> a(a(a(c(b(b(x1)))))) a(c(x1)) -> x1 interpretation: [b#](x0) = [0 0]x0 + [0], [0 0] [b](x0) = [0 0]x0, [0 2] [-&] [a](x0) = [0 0]x0 + [0 ], [0 0 ] [c](x0) = [-& -&]x0 orientation: b#(a(a(x1))) = [2 2]x1 + [2] >= [0 0]x1 + [0] = b#(b(x1)) b#(a(a(x1))) = [2 2]x1 + [2] >= [0 0]x1 + [0] = b#(x1) [0 2] [-&] a(x1) = [0 0]x1 + [0 ] >= x1 = x1 [2 2] [2] [2 2] [2] b(a(a(x1))) = [2 2]x1 + [2] >= [2 2]x1 + [2] = a(a(a(c(b(b(x1)))))) [0 0] [-&] a(c(x1)) = [0 0]x1 + [0 ] >= x1 = x1 problem: DPs: TRS: a(x1) -> x1 b(a(a(x1))) -> a(a(a(c(b(b(x1)))))) a(c(x1)) -> x1 Qed
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