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SRS Standard pair #487085528
details
property
value
status
complete
benchmark
size-12-alpha-3-num-550.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n139.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
41.5994 seconds
cpu usage
185.363
user time
182.572
system time
2.79112
max virtual memory
1.1445396E7
max residence set size
130124.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(b(x1)) -> x1 a(c(x1)) -> b(c(a(b(c(a(x1)))))) b(c(x1)) -> x1 Proof: String Reversal Processor: b(a(x1)) -> x1 c(a(x1)) -> a(c(b(a(c(b(x1)))))) c(b(x1)) -> x1 DP Processor: DPs: c#(a(x1)) -> b#(x1) c#(a(x1)) -> c#(b(x1)) c#(a(x1)) -> b#(a(c(b(x1)))) c#(a(x1)) -> c#(b(a(c(b(x1))))) TRS: b(a(x1)) -> x1 c(a(x1)) -> a(c(b(a(c(b(x1)))))) c(b(x1)) -> x1 TDG Processor: DPs: c#(a(x1)) -> b#(x1) c#(a(x1)) -> c#(b(x1)) c#(a(x1)) -> b#(a(c(b(x1)))) c#(a(x1)) -> c#(b(a(c(b(x1))))) TRS: b(a(x1)) -> x1 c(a(x1)) -> a(c(b(a(c(b(x1)))))) c(b(x1)) -> x1 graph: c#(a(x1)) -> c#(b(a(c(b(x1))))) -> c#(a(x1)) -> c#(b(a(c(b(x1))))) c#(a(x1)) -> c#(b(a(c(b(x1))))) -> c#(a(x1)) -> b#(a(c(b(x1)))) c#(a(x1)) -> c#(b(a(c(b(x1))))) -> c#(a(x1)) -> c#(b(x1)) c#(a(x1)) -> c#(b(a(c(b(x1))))) -> c#(a(x1)) -> b#(x1) c#(a(x1)) -> c#(b(x1)) -> c#(a(x1)) -> c#(b(a(c(b(x1))))) c#(a(x1)) -> c#(b(x1)) -> c#(a(x1)) -> b#(a(c(b(x1)))) c#(a(x1)) -> c#(b(x1)) -> c#(a(x1)) -> c#(b(x1)) c#(a(x1)) -> c#(b(x1)) -> c#(a(x1)) -> b#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 8/16 DPs: c#(a(x1)) -> c#(b(a(c(b(x1))))) c#(a(x1)) -> c#(b(x1)) TRS: b(a(x1)) -> x1 c(a(x1)) -> a(c(b(a(c(b(x1)))))) c(b(x1)) -> x1 Arctic Interpretation Processor: dimension: 1 usable rules: b(a(x1)) -> x1 c(a(x1)) -> a(c(b(a(c(b(x1)))))) c(b(x1)) -> x1 interpretation: [c#](x0) = x0 + 1, [a](x0) = 1x0 + 2, [b](x0) = -1x0 + 0, [c](x0) = 1x0 + 0 orientation: c#(a(x1)) = 1x1 + 2 >= x1 + 1 = c#(b(a(c(b(x1))))) c#(a(x1)) = 1x1 + 2 >= -1x1 + 1 = c#(b(x1)) b(a(x1)) = x1 + 1 >= x1 = x1 c(a(x1)) = 2x1 + 3 >= 2x1 + 3 = a(c(b(a(c(b(x1)))))) c(b(x1)) = x1 + 1 >= x1 = x1 problem: DPs: TRS: b(a(x1)) -> x1 c(a(x1)) -> a(c(b(a(c(b(x1)))))) c(b(x1)) -> x1 Qed
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