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SRS Standard pair #487085630
details
property
value
status
complete
benchmark
12.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n143.star.cs.uiowa.edu
space
Bouchare_06
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
44.8574 seconds
cpu usage
175.547
user time
171.595
system time
3.95239
max virtual memory
1.164574E7
max residence set size
116452.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Proof: DP Processor: DPs: b#(a(a(x1))) -> b#(x1) b#(a(a(x1))) -> b#(a(b(x1))) TRS: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Arctic Interpretation Processor: dimension: 2 usable rules: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) interpretation: [-& 1 ] [0] [a](x0) = [1 -&]x0 + [1], [3 0 ] [3] [b](x0) = [1 -&]x0 + [1], [b#](x0) = [0 -&]x0 + [0] orientation: b#(a(a(x1))) = [2 -&]x1 + [2] >= [0 -&]x1 + [0] = b#(x1) b#(a(a(x1))) = [2 -&]x1 + [2] >= [2 -&]x1 + [2] = b#(a(b(x1))) [6 3] [6] [-& 3 ] [2] b(b(x1)) = [4 1]x1 + [4] >= [3 -&]x1 + [3] = a(a(a(x1))) [5 1 ] [5] [-& 1 ] [0] b(a(b(x1))) = [3 -&]x1 + [3] >= [1 -&]x1 + [1] = a(x1) [5 2 ] [5] [5 1 ] [5] b(a(a(x1))) = [3 -&]x1 + [3] >= [3 -&]x1 + [3] = b(a(b(x1))) problem: DPs: b#(a(a(x1))) -> b#(a(b(x1))) TRS: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Restore Modifier: DPs: b#(a(a(x1))) -> b#(a(b(x1))) TRS: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Arctic Interpretation Processor: dimension: 2 usable rules: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) interpretation: [-& 1 ] [1] [a](x0) = [1 -&]x0 + [0], [-& 0 ] [0] [b](x0) = [0 3 ]x0 + [3], [b#](x0) = [-& 0 ]x0 + [0] orientation: b#(a(a(x1))) = [-& 2 ]x1 + [2] >= [-& 1 ]x1 + [1] = b#(a(b(x1))) [0 3] [3] [-& 3 ] [3] b(b(x1)) = [3 6]x1 + [6] >= [3 -&]x1 + [2] = a(a(a(x1))) [-& 1 ] [1] [-& 1 ] [1] b(a(b(x1))) = [1 4 ]x1 + [4] >= [1 -&]x1 + [0] = a(x1) [-& 2 ] [2] [-& 1 ] [1] b(a(a(x1))) = [2 5 ]x1 + [5] >= [1 4 ]x1 + [4] = b(a(b(x1))) problem: DPs: TRS: b(b(x1)) -> a(a(a(x1))) b(a(b(x1))) -> a(x1) b(a(a(x1))) -> b(a(b(x1))) Qed
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