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SRS Standard pair #487085808
details
property
value
status
complete
benchmark
214320.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n144.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
0.649359 seconds
cpu usage
0.618657
user time
0.523453
system time
0.095204
max virtual memory
712300.0
max residence set size
10484.0
stage attributes
key
value
starexec-result
YES
output
YES Problem 1: (VAR v_NonEmpty:S x1:S) (RULES 0(0(1(0(x1:S)))) -> 0(1(5(0(0(2(x1:S)))))) 0(0(1(0(x1:S)))) -> 1(0(0(2(0(x1:S))))) 0(3(0(1(0(x1:S))))) -> 0(3(0(0(2(1(x1:S)))))) 0(3(1(0(x1:S)))) -> 1(2(3(0(5(0(x1:S)))))) 0(1(0(0(0(x1:S))))) -> 0(0(5(1(0(0(x1:S)))))) 0(1(0(3(x1:S)))) -> 1(0(3(3(0(2(x1:S)))))) 0(1(0(3(x1:S)))) -> 1(0(5(3(2(0(x1:S)))))) 0(1(0(x1:S))) -> 0(0(2(1(0(x1:S))))) 0(1(0(x1:S))) -> 0(0(2(1(2(x1:S))))) 0(1(0(x1:S))) -> 0(3(2(1(0(x1:S))))) 0(1(0(x1:S))) -> 0(5(2(5(1(0(x1:S)))))) 0(1(0(x1:S))) -> 0(5(2(1(2(0(x1:S)))))) 0(1(0(x1:S))) -> 0(2(1(0(3(2(x1:S)))))) 0(1(0(x1:S))) -> 0(2(1(0(2(x1:S))))) 0(1(0(x1:S))) -> 0(2(1(0(x1:S)))) 0(1(0(x1:S))) -> 0(4(0(4(1(3(x1:S)))))) 0(1(0(x1:S))) -> 0(4(2(2(1(0(x1:S)))))) 0(1(0(x1:S))) -> 3(0(0(4(1(4(x1:S)))))) 0(1(0(x1:S))) -> 5(0(0(4(1(x1:S))))) 0(1(0(x1:S))) -> 5(5(1(0(0(2(x1:S)))))) 0(1(0(x1:S))) -> 5(1(0(4(0(x1:S))))) 0(1(0(x1:S))) -> 1(0(0(0(2(x1:S))))) 0(1(0(x1:S))) -> 1(0(0(5(4(4(x1:S)))))) 0(1(0(x1:S))) -> 1(0(0(2(0(x1:S))))) 0(1(0(x1:S))) -> 1(0(4(2(0(x1:S))))) 0(1(0(x1:S))) -> 1(0(4(4(4(0(x1:S)))))) 0(1(0(x1:S))) -> 1(5(0(0(4(2(x1:S)))))) 0(1(0(x1:S))) -> 1(4(0(4(0(x1:S))))) 0(1(0(x1:S))) -> 4(0(0(2(1(x1:S))))) 0(1(0(x1:S))) -> 4(5(1(0(2(0(x1:S)))))) 0(1(3(0(x1:S)))) -> 1(0(3(0(2(x1:S))))) 0(1(5(0(x1:S)))) -> 0(5(1(4(0(x1:S))))) 0(1(5(0(x1:S)))) -> 1(5(3(0(2(0(x1:S)))))) 0(1(1(0(x1:S)))) -> 0(4(4(1(1(0(x1:S)))))) 0(1(1(3(x1:S)))) -> 3(4(5(1(1(0(x1:S)))))) 0(1(2(0(x1:S)))) -> 0(0(4(2(5(1(x1:S)))))) 0(1(2(0(x1:S)))) -> 3(0(2(1(0(4(x1:S)))))) 0(1(2(0(x1:S)))) -> 3(0(2(1(0(x1:S))))) 0(1(2(0(x1:S)))) -> 1(1(0(2(0(x1:S))))) 0(1(2(0(x1:S)))) -> 1(1(2(0(4(0(x1:S)))))) 0(1(2(0(x1:S)))) -> 4(1(0(0(2(x1:S))))) 0(1(2(5(0(x1:S))))) -> 1(0(2(0(5(4(x1:S)))))) 0(1(2(4(0(x1:S))))) -> 0(0(5(4(2(1(x1:S)))))) 0(1(4(0(0(x1:S))))) -> 0(0(0(4(1(0(x1:S)))))) 0(1(4(0(x1:S)))) -> 0(3(4(2(1(0(x1:S)))))) 0(1(4(5(0(x1:S))))) -> 1(5(0(0(4(2(x1:S)))))) 3(0(3(1(0(x1:S))))) -> 0(1(3(2(3(0(x1:S)))))) 5(0(1(0(x1:S)))) -> 1(4(0(0(5(1(x1:S)))))) 5(0(1(0(x1:S)))) -> 2(1(0(0(4(5(x1:S)))))) 5(0(1(2(0(x1:S))))) -> 0(0(5(2(1(0(x1:S)))))) ) Problem 1: Dependency Pairs Processor: -> Pairs: 0#(0(1(0(x1:S)))) -> 0#(0(2(0(x1:S)))) 0#(0(1(0(x1:S)))) -> 0#(1(5(0(0(2(x1:S)))))) 0#(0(1(0(x1:S)))) -> 0#(2(0(x1:S))) 0#(3(1(0(x1:S)))) -> 0#(5(0(x1:S))) 0#(3(1(0(x1:S)))) -> 3#(0(5(0(x1:S)))) 0#(3(1(0(x1:S)))) -> 5#(0(x1:S)) 0#(1(0(0(0(x1:S))))) -> 0#(0(5(1(0(0(x1:S)))))) 0#(1(0(0(0(x1:S))))) -> 0#(5(1(0(0(x1:S))))) 0#(1(0(0(0(x1:S))))) -> 5#(1(0(0(x1:S)))) 0#(1(0(3(x1:S)))) -> 0#(5(3(2(0(x1:S))))) 0#(1(0(3(x1:S)))) -> 0#(x1:S) 0#(1(0(3(x1:S)))) -> 3#(2(0(x1:S))) 0#(1(0(3(x1:S)))) -> 5#(3(2(0(x1:S)))) 0#(1(0(x1:S))) -> 0#(0(2(0(x1:S)))) 0#(1(0(x1:S))) -> 0#(0(2(1(0(x1:S))))) 0#(1(0(x1:S))) -> 0#(3(2(1(0(x1:S))))) 0#(1(0(x1:S))) -> 0#(5(2(5(1(0(x1:S)))))) 0#(1(0(x1:S))) -> 0#(5(2(1(2(0(x1:S)))))) 0#(1(0(x1:S))) -> 0#(2(0(x1:S))) 0#(1(0(x1:S))) -> 0#(2(1(0(x1:S)))) 0#(1(0(x1:S))) -> 0#(4(0(4(1(3(x1:S)))))) 0#(1(0(x1:S))) -> 0#(4(0(x1:S))) 0#(1(0(x1:S))) -> 0#(4(1(3(x1:S)))) 0#(1(0(x1:S))) -> 0#(4(2(0(x1:S)))) 0#(1(0(x1:S))) -> 0#(4(2(2(1(0(x1:S)))))) 0#(1(0(x1:S))) -> 0#(4(4(4(0(x1:S))))) 0#(1(0(x1:S))) -> 3#(2(1(0(x1:S)))) 0#(1(0(x1:S))) -> 3#(x1:S) 0#(1(0(x1:S))) -> 5#(1(0(2(0(x1:S))))) 0#(1(0(x1:S))) -> 5#(1(0(4(0(x1:S))))) 0#(1(0(x1:S))) -> 5#(1(0(x1:S))) 0#(1(0(x1:S))) -> 5#(2(5(1(0(x1:S))))) 0#(1(0(x1:S))) -> 5#(2(1(2(0(x1:S))))) 0#(1(5(0(x1:S)))) -> 0#(5(1(4(0(x1:S))))) 0#(1(5(0(x1:S)))) -> 0#(2(0(x1:S))) 0#(1(5(0(x1:S)))) -> 3#(0(2(0(x1:S)))) 0#(1(5(0(x1:S)))) -> 5#(3(0(2(0(x1:S))))) 0#(1(5(0(x1:S)))) -> 5#(1(4(0(x1:S))))
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