details

property	value
status	complete
benchmark	212534.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n145.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	12.3354 seconds
cpu usage	11.8706
user time	10.6576
system time	1.21306
max virtual memory	805244.0
max residence set size	45216.0

stage attributes

key	value
starexec-result	YES

output

YES Problem 1: (VAR v_NonEmpty:S x1:S) (RULES 0(0(1(2(x1:S)))) -> 0(2(1(0(3(x1:S))))) 0(4(5(3(5(x1:S))))) -> 5(1(0(3(4(5(x1:S)))))) 0(1(0(1(2(x1:S))))) -> 0(2(1(1(3(0(x1:S)))))) 0(1(2(0(x1:S)))) -> 2(1(0(3(0(3(x1:S)))))) 0(1(2(5(x1:S)))) -> 2(1(0(3(5(x1:S))))) 0(1(2(5(x1:S)))) -> 5(1(0(3(2(x1:S))))) 0(1(2(3(5(x1:S))))) -> 0(2(5(1(0(3(x1:S)))))) 0(1(2(3(5(x1:S))))) -> 0(1(3(4(5(2(x1:S)))))) 0(1(2(3(5(x1:S))))) -> 5(1(3(0(2(0(x1:S)))))) 0(1(2(3(5(x1:S))))) -> 1(0(3(0(2(5(x1:S)))))) 0(1(2(x1:S))) -> 2(1(0(3(x1:S)))) 0(1(2(x1:S))) -> 2(1(3(0(4(x1:S))))) 0(1(2(x1:S))) -> 2(1(3(0(x1:S)))) 0(1(2(x1:S))) -> 2(1(3(4(0(4(x1:S)))))) 0(1(2(x1:S))) -> 2(1(3(4(0(x1:S))))) 0(1(4(0(2(x1:S))))) -> 4(0(2(1(3(0(x1:S)))))) 0(1(4(0(2(x1:S))))) -> 4(0(1(3(0(2(x1:S)))))) 0(1(4(2(x1:S)))) -> 0(2(1(0(3(4(x1:S)))))) 0(1(4(2(x1:S)))) -> 2(4(1(0(3(x1:S))))) 0(1(4(2(x1:S)))) -> 2(1(3(4(0(x1:S))))) 0(1(1(2(5(x1:S))))) -> 0(1(3(5(1(2(x1:S)))))) 0(1(1(2(x1:S)))) -> 1(0(4(1(2(x1:S))))) 0(1(1(2(x1:S)))) -> 1(2(1(0(3(x1:S))))) 0(1(1(4(2(x1:S))))) -> 4(1(0(3(2(1(x1:S)))))) 0(1(1(5(0(x1:S))))) -> 0(1(0(5(4(1(x1:S)))))) 0(1(1(5(4(x1:S))))) -> 1(4(1(0(3(5(x1:S)))))) 2(2(4(3(5(x1:S))))) -> 5(1(3(4(2(2(x1:S)))))) 2(2(3(5(0(x1:S))))) -> 5(2(4(2(0(3(x1:S)))))) 2(5(0(3(5(x1:S))))) -> 5(2(1(3(0(5(x1:S)))))) 2(5(3(2(x1:S)))) -> 5(1(3(2(2(x1:S))))) 2(1(0(1(5(x1:S))))) -> 1(0(3(2(5(1(x1:S)))))) 2(1(2(0(x1:S)))) -> 2(2(1(0(3(x1:S))))) 2(1(4(5(0(x1:S))))) -> 2(4(1(0(3(5(x1:S)))))) 2(1(4(3(5(x1:S))))) -> 5(4(4(1(3(2(x1:S)))))) 2(1(4(3(5(x1:S))))) -> 1(3(5(4(4(2(x1:S)))))) 2(1(1(5(x1:S)))) -> 2(5(1(4(1(x1:S))))) 2(1(1(5(x1:S)))) -> 5(1(3(2(1(x1:S))))) 2(3(2(0(5(x1:S))))) -> 2(2(1(0(3(5(x1:S)))))) 2(3(5(5(x1:S)))) -> 5(1(0(3(2(5(x1:S)))))) 2(3(1(1(2(x1:S))))) -> 4(1(2(2(1(3(x1:S)))))) 2(3(1(1(2(x1:S))))) -> 1(3(2(1(2(0(x1:S)))))) 2(3(3(1(5(x1:S))))) -> 1(3(5(1(3(2(x1:S)))))) 4(2(0(1(2(x1:S))))) -> 4(2(2(1(3(0(x1:S)))))) 5(0(1(2(2(x1:S))))) -> 4(1(5(2(0(2(x1:S)))))) 5(5(4(3(2(x1:S))))) -> 5(1(3(4(5(2(x1:S)))))) 5(1(2(0(x1:S)))) -> 2(5(1(0(3(x1:S))))) 5(1(4(2(2(x1:S))))) -> 5(1(3(2(4(2(x1:S)))))) 5(1(4(3(2(x1:S))))) -> 4(5(1(3(4(2(x1:S)))))) ) Problem 1: Dependency Pairs Processor: -> Pairs: 0#(4(5(3(5(x1:S))))) -> 0#(3(4(5(x1:S)))) 0#(4(5(3(5(x1:S))))) -> 4#(5(x1:S)) 0#(4(5(3(5(x1:S))))) -> 5#(1(0(3(4(5(x1:S)))))) 0#(1(0(1(2(x1:S))))) -> 0#(2(1(1(3(0(x1:S)))))) 0#(1(0(1(2(x1:S))))) -> 0#(x1:S) 0#(1(0(1(2(x1:S))))) -> 2#(1(1(3(0(x1:S))))) 0#(1(2(5(x1:S)))) -> 0#(3(2(x1:S))) 0#(1(2(5(x1:S)))) -> 0#(3(5(x1:S))) 0#(1(2(5(x1:S)))) -> 2#(1(0(3(5(x1:S))))) 0#(1(2(5(x1:S)))) -> 2#(x1:S) 0#(1(2(5(x1:S)))) -> 5#(1(0(3(2(x1:S))))) 0#(1(2(3(5(x1:S))))) -> 0#(2(0(x1:S))) 0#(1(2(3(5(x1:S))))) -> 0#(2(5(x1:S))) 0#(1(2(3(5(x1:S))))) -> 0#(1(3(4(5(2(x1:S)))))) 0#(1(2(3(5(x1:S))))) -> 0#(3(0(2(5(x1:S))))) 0#(1(2(3(5(x1:S))))) -> 0#(x1:S) 0#(1(2(3(5(x1:S))))) -> 2#(0(x1:S)) 0#(1(2(3(5(x1:S))))) -> 2#(5(x1:S)) 0#(1(2(3(5(x1:S))))) -> 2#(x1:S) 0#(1(2(3(5(x1:S))))) -> 4#(5(2(x1:S))) 0#(1(2(3(5(x1:S))))) -> 5#(2(x1:S)) 0#(1(2(3(5(x1:S))))) -> 5#(1(3(0(2(0(x1:S)))))) 0#(1(2(x1:S))) -> 0#(4(x1:S)) 0#(1(2(x1:S))) -> 0#(x1:S) 0#(1(2(x1:S))) -> 2#(1(3(0(4(x1:S))))) 0#(1(2(x1:S))) -> 2#(1(3(0(x1:S)))) 0#(1(2(x1:S))) -> 2#(1(3(4(0(4(x1:S)))))) 0#(1(2(x1:S))) -> 2#(1(3(4(0(x1:S))))) 0#(1(2(x1:S))) -> 4#(0(4(x1:S))) 0#(1(2(x1:S))) -> 4#(0(x1:S)) 0#(1(2(x1:S))) -> 4#(x1:S) 0#(1(4(0(2(x1:S))))) -> 0#(2(1(3(0(x1:S))))) 0#(1(4(0(2(x1:S))))) -> 0#(1(3(0(2(x1:S))))) 0#(1(4(0(2(x1:S))))) -> 0#(x1:S) 0#(1(4(0(2(x1:S))))) -> 2#(1(3(0(x1:S)))) 0#(1(4(0(2(x1:S))))) -> 4#(0(2(1(3(0(x1:S)))))) 0#(1(4(0(2(x1:S))))) -> 4#(0(1(3(0(2(x1:S)))))) 0#(1(4(2(x1:S)))) -> 0#(2(1(0(3(4(x1:S)))))) 0#(1(4(2(x1:S)))) -> 0#(3(4(x1:S))) 0#(1(4(2(x1:S)))) -> 0#(x1:S) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to SRS Standard