SRS Standard pair #487086281

details

property	value
status	complete
benchmark	212534.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n150.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	MultumNonMulta 20 June 2020 20G sparse
configuration	default
runtime (wallclock)	2.74911 seconds
cpu usage	8.82
user time	7.72
system time	1.1
max virtual memory	2.6234236E7
max residence set size	835984.0

stage attributes

key	value
starexec-result	YES

output

YES

After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4, 5->5 }, 
it remains to prove termination of the 48-rule system
{ 0 1 2 -> 2 1 0 3 ,
  0 1 2 -> 2 1 3 0 ,
  0 1 2 -> 2 1 3 0 4 ,
  0 1 2 -> 2 1 3 4 0 ,
  0 1 2 -> 2 1 3 4 0 4 ,
  0 0 1 2 -> 0 2 1 0 3 ,
  0 1 1 2 -> 1 0 4 1 2 ,
  0 1 1 2 -> 1 2 1 0 3 ,
  0 1 2 0 -> 2 1 0 3 0 3 ,
  0 1 2 5 -> 2 1 0 3 5 ,
  0 1 2 5 -> 5 1 0 3 2 ,
  0 1 4 2 -> 2 1 3 4 0 ,
  0 1 4 2 -> 2 4 1 0 3 ,
  0 1 4 2 -> 0 2 1 0 3 4 ,
  2 1 1 5 -> 2 5 1 4 1 ,
  2 1 1 5 -> 5 1 3 2 1 ,
  2 1 2 0 -> 2 2 1 0 3 ,
  2 3 5 5 -> 5 1 0 3 2 5 ,
  2 5 3 2 -> 5 1 3 2 2 ,
  5 1 2 0 -> 2 5 1 0 3 ,
  0 1 0 1 2 -> 0 2 1 1 3 0 ,
  0 1 1 2 5 -> 0 1 3 5 1 2 ,
  0 1 1 4 2 -> 4 1 0 3 2 1 ,
  0 1 1 5 0 -> 0 1 0 5 4 1 ,
  0 1 1 5 4 -> 1 4 1 0 3 5 ,
  0 1 2 3 5 -> 0 1 3 4 5 2 ,
  0 1 2 3 5 -> 0 2 5 1 0 3 ,
  0 1 2 3 5 -> 1 0 3 0 2 5 ,
  0 1 2 3 5 -> 5 1 3 0 2 0 ,
  0 1 4 0 2 -> 4 0 1 3 0 2 ,
  0 1 4 0 2 -> 4 0 2 1 3 0 ,
  0 4 5 3 5 -> 5 1 0 3 4 5 ,
  2 1 0 1 5 -> 1 0 3 2 5 1 ,
  2 1 4 3 5 -> 1 3 5 4 4 2 ,
  2 1 4 3 5 -> 5 4 4 1 3 2 ,
  2 1 4 5 0 -> 2 4 1 0 3 5 ,
  2 2 3 5 0 -> 5 2 4 2 0 3 ,
  2 2 4 3 5 -> 5 1 3 4 2 2 ,
  2 3 1 1 2 -> 1 3 2 1 2 0 ,
  2 3 1 1 2 -> 4 1 2 2 1 3 ,
  2 3 2 0 5 -> 2 2 1 0 3 5 ,
  2 3 3 1 5 -> 1 3 5 1 3 2 ,
  2 5 0 3 5 -> 5 2 1 3 0 5 ,
  4 2 0 1 2 -> 4 2 2 1 3 0 ,
  5 0 1 2 2 -> 4 1 5 2 0 2 ,
  5 1 4 2 2 -> 5 1 3 2 4 2 ,
  5 1 4 3 2 -> 4 5 1 3 4 2 ,
  5 5 4 3 2 -> 5 1 3 4 5 2 }


The system was reversed.

After renaming modulo { 2->0, 1->1, 0->2, 3->3, 4->4, 5->5 }, 
it remains to prove termination of the 48-rule system
{ 0 1 2 -> 3 2 1 0 ,
  0 1 2 -> 2 3 1 0 ,
  0 1 2 -> 4 2 3 1 0 ,
  0 1 2 -> 2 4 3 1 0 ,
  0 1 2 -> 4 2 4 3 1 0 ,
  0 1 2 2 -> 3 2 1 0 2 ,
  0 1 1 2 -> 0 1 4 2 1 ,
  0 1 1 2 -> 3 2 1 0 1 ,
  2 0 1 2 -> 3 2 3 2 1 0 ,
  5 0 1 2 -> 5 3 2 1 0 ,
  5 0 1 2 -> 0 3 2 1 5 ,
  0 4 1 2 -> 2 4 3 1 0 ,
  0 4 1 2 -> 3 2 1 4 0 ,
  0 4 1 2 -> 4 3 2 1 0 2 ,
  5 1 1 0 -> 1 4 1 5 0 ,
  5 1 1 0 -> 1 0 3 1 5 ,
  2 0 1 0 -> 3 2 1 0 0 ,
  5 5 3 0 -> 5 0 3 2 1 5 ,
  0 3 5 0 -> 0 0 3 1 5 ,
  2 0 1 5 -> 3 2 1 5 0 ,
  0 1 2 1 2 -> 2 3 1 1 0 2 ,
  5 0 1 1 2 -> 0 1 5 3 1 2 ,
  0 4 1 1 2 -> 1 0 3 2 1 4 ,
  2 5 1 1 2 -> 1 4 5 2 1 2 ,
  4 5 1 1 2 -> 5 3 2 1 4 1 ,
  5 3 0 1 2 -> 0 5 4 3 1 2 ,
  5 3 0 1 2 -> 3 2 1 5 0 2 ,
  5 3 0 1 2 -> 5 0 2 3 2 1 ,
  5 3 0 1 2 -> 2 0 2 3 1 5 ,
  0 2 4 1 2 -> 0 2 3 1 2 4 ,
  0 2 4 1 2 -> 2 3 1 0 2 4 ,
  5 3 5 4 2 -> 5 4 3 2 1 5 ,
  5 1 2 1 0 -> 1 5 0 3 2 1 ,
  5 3 4 1 0 -> 0 4 4 5 3 1 ,
  5 3 4 1 0 -> 0 3 1 4 4 5 ,
  2 5 4 1 0 -> 5 3 2 1 4 0 ,
  2 5 3 0 0 -> 3 2 0 4 0 5 ,
  5 3 4 0 0 -> 0 0 4 3 1 5 ,
  0 1 1 3 0 -> 2 0 1 0 3 1 ,
  0 1 1 3 0 -> 3 1 0 0 1 4 ,
  5 2 0 3 0 -> 5 3 2 1 0 0 ,
  5 1 3 3 0 -> 0 3 1 5 3 1 ,

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