details

property	value
status	complete
benchmark	213051.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n150.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	9.21154 seconds
cpu usage	9.43465
user time	8.56436
system time	0.870287
max virtual memory	715756.0
max residence set size	23864.0

stage attributes

key	value
starexec-result	YES

output

YES Problem 1: (VAR v_NonEmpty:S x1:S) (RULES 0(0(4(1(x1:S)))) -> 1(4(0(3(0(3(x1:S)))))) 0(0(5(5(1(x1:S))))) -> 1(0(0(3(5(5(x1:S)))))) 0(0(5(1(x1:S)))) -> 0(0(3(1(2(5(x1:S)))))) 0(0(1(1(x1:S)))) -> 1(2(0(0(3(1(x1:S)))))) 0(0(1(x1:S))) -> 0(1(2(0(3(2(x1:S)))))) 0(0(1(x1:S))) -> 0(1(2(0(3(x1:S))))) 0(0(1(x1:S))) -> 1(2(0(0(3(2(x1:S)))))) 0(0(2(1(x1:S)))) -> 2(2(0(3(0(1(x1:S)))))) 0(4(4(1(x1:S)))) -> 2(4(0(3(4(1(x1:S)))))) 0(4(1(0(x1:S)))) -> 0(4(0(1(2(x1:S))))) 0(4(1(4(1(x1:S))))) -> 4(4(0(1(2(1(x1:S)))))) 0(4(1(x1:S))) -> 4(0(3(1(x1:S)))) 0(4(1(x1:S))) -> 4(2(1(2(0(3(x1:S)))))) 0(4(1(x1:S))) -> 2(4(0(5(3(1(x1:S)))))) 0(4(1(x1:S))) -> 2(4(0(3(2(1(x1:S)))))) 0(4(2(1(x1:S)))) -> 4(0(3(5(1(2(x1:S)))))) 0(4(2(1(x1:S)))) -> 4(0(3(2(2(1(x1:S)))))) 0(5(0(1(x1:S)))) -> 0(2(0(3(5(1(x1:S)))))) 0(5(0(1(x1:S)))) -> 5(2(0(3(0(1(x1:S)))))) 0(5(5(4(1(x1:S))))) -> 4(1(0(5(5(3(x1:S)))))) 0(5(1(0(x1:S)))) -> 0(1(2(0(3(5(x1:S)))))) 0(5(1(0(x1:S)))) -> 2(0(1(3(5(0(x1:S)))))) 0(1(0(5(0(x1:S))))) -> 0(1(5(2(0(0(x1:S)))))) 0(1(0(x1:S))) -> 2(0(3(1(2(0(x1:S)))))) 0(1(4(1(x1:S)))) -> 0(1(2(4(1(2(x1:S)))))) 0(1(5(0(x1:S)))) -> 1(2(5(0(0(3(x1:S)))))) 0(1(1(0(x1:S)))) -> 1(2(0(0(1(2(x1:S)))))) 0(2(4(1(x1:S)))) -> 4(0(5(3(1(2(x1:S)))))) 0(2(5(0(1(x1:S))))) -> 2(0(3(5(0(1(x1:S)))))) 0(3(1(0(0(x1:S))))) -> 0(0(3(0(1(2(x1:S)))))) 4(0(5(1(x1:S)))) -> 1(4(0(5(3(2(x1:S)))))) 4(4(1(0(5(x1:S))))) -> 4(0(5(3(4(1(x1:S)))))) 4(1(0(0(x1:S)))) -> 0(4(1(2(0(x1:S))))) 4(1(0(1(x1:S)))) -> 1(1(2(0(4(x1:S))))) 4(1(0(x1:S))) -> 1(2(0(4(x1:S)))) 4(1(5(0(0(x1:S))))) -> 1(2(0(4(5(0(x1:S)))))) 4(1(5(0(x1:S)))) -> 1(4(0(3(5(x1:S))))) 4(1(5(0(x1:S)))) -> 1(2(0(5(4(x1:S))))) 4(1(5(5(0(x1:S))))) -> 5(1(3(0(5(4(x1:S)))))) 4(3(1(0(1(x1:S))))) -> 1(1(2(3(0(4(x1:S)))))) 4(3(1(0(x1:S)))) -> 1(4(2(0(3(x1:S))))) 4(3(1(0(x1:S)))) -> 2(0(2(1(3(4(x1:S)))))) 4(3(1(0(x1:S)))) -> 2(1(4(2(0(3(x1:S)))))) 4(3(1(0(x1:S)))) -> 2(2(4(0(1(3(x1:S)))))) 4(3(1(5(0(x1:S))))) -> 5(1(0(3(2(4(x1:S)))))) 4(3(1(1(0(x1:S))))) -> 1(2(0(1(4(3(x1:S)))))) 5(0(1(0(x1:S)))) -> 0(3(5(1(2(0(x1:S)))))) 5(0(1(0(x1:S)))) -> 1(5(2(0(3(0(x1:S)))))) 5(4(1(0(x1:S)))) -> 0(1(2(4(5(2(x1:S)))))) ) Problem 1: Dependency Pairs Processor: -> Pairs: 0#(0(4(1(x1:S)))) -> 0#(3(0(3(x1:S)))) 0#(0(4(1(x1:S)))) -> 0#(3(x1:S)) 0#(0(4(1(x1:S)))) -> 4#(0(3(0(3(x1:S))))) 0#(0(5(5(1(x1:S))))) -> 0#(0(3(5(5(x1:S))))) 0#(0(5(5(1(x1:S))))) -> 0#(3(5(5(x1:S)))) 0#(0(5(5(1(x1:S))))) -> 5#(5(x1:S)) 0#(0(5(5(1(x1:S))))) -> 5#(x1:S) 0#(0(5(1(x1:S)))) -> 0#(0(3(1(2(5(x1:S)))))) 0#(0(5(1(x1:S)))) -> 0#(3(1(2(5(x1:S))))) 0#(0(5(1(x1:S)))) -> 5#(x1:S) 0#(0(1(1(x1:S)))) -> 0#(0(3(1(x1:S)))) 0#(0(1(1(x1:S)))) -> 0#(3(1(x1:S))) 0#(0(1(x1:S))) -> 0#(1(2(0(3(x1:S))))) 0#(0(1(x1:S))) -> 0#(3(x1:S)) 0#(0(2(1(x1:S)))) -> 0#(1(x1:S)) 0#(0(2(1(x1:S)))) -> 0#(3(0(1(x1:S)))) 0#(4(4(1(x1:S)))) -> 0#(3(4(1(x1:S)))) 0#(4(4(1(x1:S)))) -> 4#(0(3(4(1(x1:S))))) 0#(4(1(x1:S))) -> 0#(3(1(x1:S))) 0#(4(1(x1:S))) -> 0#(3(x1:S)) 0#(4(1(x1:S))) -> 4#(0(3(1(x1:S)))) 0#(4(1(x1:S))) -> 4#(2(1(2(0(3(x1:S)))))) 0#(5(0(1(x1:S)))) -> 0#(3(0(1(x1:S)))) 0#(5(0(1(x1:S)))) -> 5#(2(0(3(0(1(x1:S)))))) 0#(5(5(4(1(x1:S))))) -> 4#(1(0(5(5(3(x1:S)))))) 0#(5(1(0(x1:S)))) -> 0#(1(2(0(3(5(x1:S)))))) 0#(5(1(0(x1:S)))) -> 0#(1(3(5(0(x1:S))))) 0#(5(1(0(x1:S)))) -> 0#(3(5(x1:S))) 0#(5(1(0(x1:S)))) -> 5#(0(x1:S)) 0#(5(1(0(x1:S)))) -> 5#(x1:S) 0#(1(0(5(0(x1:S))))) -> 0#(0(x1:S)) 0#(1(0(5(0(x1:S))))) -> 0#(1(5(2(0(0(x1:S)))))) 0#(1(0(5(0(x1:S))))) -> 5#(2(0(0(x1:S)))) 0#(1(0(x1:S))) -> 0#(3(1(2(0(x1:S))))) 0#(1(5(0(x1:S)))) -> 0#(0(3(x1:S))) 0#(1(5(0(x1:S)))) -> 0#(3(x1:S)) 0#(1(5(0(x1:S)))) -> 5#(0(0(3(x1:S)))) 0#(1(1(0(x1:S)))) -> 0#(0(1(2(x1:S)))) 0#(2(5(0(1(x1:S))))) -> 0#(3(5(0(1(x1:S))))) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to SRS Standard