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SRS Standard pair #487087006
details
property
value
status
complete
benchmark
213560.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n146.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
17.2353 seconds
cpu usage
63.8806
user time
61.5678
system time
2.31278
max virtual memory
6.2813132E7
max residence set size
4690644.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) FlatCCProof [EQUIVALENT, 0 ms] (2) QTRS (3) RootLabelingProof [EQUIVALENT, 2 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 1002 ms] (6) QTRS (7) QTRSRRRProof [EQUIVALENT, 363 ms] (8) QTRS (9) QTRSRRRProof [EQUIVALENT, 271 ms] (10) QTRS (11) QTRSRRRProof [EQUIVALENT, 200 ms] (12) QTRS (13) QTRSRRRProof [EQUIVALENT, 2 ms] (14) QTRS (15) QTRSRRRProof [EQUIVALENT, 1 ms] (16) QTRS (17) RisEmptyProof [EQUIVALENT, 0 ms] (18) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(0(1(2(x1)))) -> 0(2(1(3(3(0(x1)))))) 0(1(0(4(x1)))) -> 0(1(3(0(4(x1))))) 0(1(0(5(x1)))) -> 0(1(3(5(0(x1))))) 0(1(5(0(x1)))) -> 0(1(3(5(0(x1))))) 0(3(1(0(x1)))) -> 0(1(3(5(0(x1))))) 3(1(0(2(x1)))) -> 1(3(5(0(2(x1))))) 3(1(0(2(x1)))) -> 3(2(1(3(0(x1))))) 3(1(0(5(x1)))) -> 1(3(5(3(0(x1))))) 3(1(2(0(x1)))) -> 2(1(3(3(0(x1))))) 3(1(2(0(x1)))) -> 3(0(2(1(4(x1))))) 3(1(2(0(x1)))) -> 3(0(3(2(1(x1))))) 3(1(2(0(x1)))) -> 3(3(2(1(0(x1))))) 3(1(2(0(x1)))) -> 3(5(2(1(0(x1))))) 3(1(2(2(x1)))) -> 3(5(2(2(1(x1))))) 3(4(2(0(x1)))) -> 3(3(2(4(0(x1))))) 4(0(1(0(x1)))) -> 1(3(0(4(0(x1))))) 5(1(0(5(x1)))) -> 1(3(3(5(5(0(x1)))))) 5(2(5(0(x1)))) -> 5(2(3(5(0(x1))))) 5(3(1(0(x1)))) -> 0(1(3(5(5(x1))))) 0(0(4(1(0(x1))))) -> 0(4(1(3(0(0(x1)))))) 0(1(2(0(5(x1))))) -> 0(3(0(5(1(2(x1)))))) 0(1(3(1(2(x1))))) -> 3(0(2(2(1(1(x1)))))) 0(1(5(0(4(x1))))) -> 0(4(1(3(5(0(x1)))))) 0(1(5(3(5(x1))))) -> 0(1(3(5(3(5(x1)))))) 0(2(0(3(4(x1))))) -> 0(4(5(2(3(0(x1)))))) 0(2(3(1(5(x1))))) -> 0(1(3(5(5(2(x1)))))) 0(2(4(1(2(x1))))) -> 0(2(1(1(4(2(x1)))))) 0(2(5(0(2(x1))))) -> 0(0(3(5(2(2(x1)))))) 0(2(5(5(0(x1))))) -> 0(0(2(5(1(5(x1)))))) 0(3(1(5(0(x1))))) -> 1(3(0(5(3(0(x1)))))) 0(5(3(2(0(x1))))) -> 0(0(2(1(3(5(x1)))))) 3(1(0(5(2(x1))))) -> 2(4(1(3(5(0(x1)))))) 3(1(3(0(2(x1))))) -> 2(1(3(3(3(0(x1)))))) 3(1(3(2(0(x1))))) -> 3(1(3(0(5(2(x1)))))) 3(1(4(1(2(x1))))) -> 1(4(3(2(2(1(x1)))))) 3(1(4(2(0(x1))))) -> 2(1(3(3(0(4(x1)))))) 3(1(5(0(2(x1))))) -> 2(5(1(3(0(5(x1)))))) 3(3(1(0(0(x1))))) -> 5(1(3(3(0(0(x1)))))) 3(4(0(2(0(x1))))) -> 3(0(0(2(1(4(x1)))))) 3(4(2(3(2(x1))))) -> 3(3(2(5(4(2(x1)))))) 4(3(1(0(2(x1))))) -> 4(2(1(3(0(1(x1)))))) 4(3(1(2(0(x1))))) -> 1(3(0(1(4(2(x1)))))) 4(5(5(1(2(x1))))) -> 5(4(5(2(1(1(x1)))))) 4(5(5(5(0(x1))))) -> 5(5(1(5(0(4(x1)))))) 5(1(0(1(2(x1))))) -> 2(1(1(3(5(0(x1)))))) 5(1(1(0(4(x1))))) -> 5(1(1(4(3(0(x1)))))) 5(1(5(2(0(x1))))) -> 2(1(3(5(0(5(x1)))))) 5(4(1(0(5(x1))))) -> 4(1(3(5(5(0(x1)))))) Q is empty. ---------------------------------------- (1) FlatCCProof (EQUIVALENT) We used flat context closure [ROOTLAB] As Q is empty the flat context closure was sound AND complete. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(0(1(2(x1)))) -> 0(2(1(3(3(0(x1))))))
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