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SRS Standard pair #487087126
details
property
value
status
complete
benchmark
212480.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n141.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
7.25795 seconds
cpu usage
25.5986
user time
24.6603
system time
0.938349
max virtual memory
2.0427536E7
max residence set size
2752816.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 222 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) QDP (8) UsableRulesProof [EQUIVALENT, 0 ms] (9) QDP (10) QDPOrderProof [EQUIVALENT, 22 ms] (11) QDP (12) PisEmptyProof [EQUIVALENT, 0 ms] (13) YES (14) QDP (15) UsableRulesProof [EQUIVALENT, 16 ms] (16) QDP (17) QDPOrderProof [EQUIVALENT, 142 ms] (18) QDP (19) UsableRulesProof [EQUIVALENT, 0 ms] (20) QDP (21) MRRProof [EQUIVALENT, 35 ms] (22) QDP (23) PisEmptyProof [EQUIVALENT, 0 ms] (24) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(1(1(x1))) -> 1(2(1(2(0(x1))))) 0(3(1(x1))) -> 1(3(2(2(0(x1))))) 0(3(1(x1))) -> 3(2(1(2(0(x1))))) 0(3(1(x1))) -> 1(3(3(3(2(0(x1)))))) 0(4(1(x1))) -> 2(1(2(0(4(x1))))) 0(0(4(5(x1)))) -> 0(0(2(5(4(x1))))) 0(1(4(1(x1)))) -> 0(1(2(2(4(1(x1)))))) 0(1(4(5(x1)))) -> 4(0(1(2(5(4(x1)))))) 0(1(5(1(x1)))) -> 1(2(2(5(0(1(x1)))))) 0(1(5(3(x1)))) -> 0(5(3(2(1(x1))))) 0(2(4(1(x1)))) -> 1(3(3(2(0(4(x1)))))) 0(2(4(1(x1)))) -> 4(2(1(2(0(4(x1)))))) 0(2(4(5(x1)))) -> 0(2(2(5(0(4(x1)))))) 0(3(1(5(x1)))) -> 0(1(2(5(3(x1))))) 0(3(1(5(x1)))) -> 1(2(5(3(0(4(x1)))))) 0(3(5(1(x1)))) -> 1(2(5(3(0(x1))))) 0(3(5(1(x1)))) -> 0(5(2(1(2(3(x1)))))) 0(3(5(5(x1)))) -> 0(3(2(5(5(x1))))) 0(4(0(1(x1)))) -> 2(0(4(4(0(1(x1)))))) 0(4(1(5(x1)))) -> 1(2(5(0(4(x1))))) 0(4(3(5(x1)))) -> 0(4(3(2(5(4(x1)))))) 0(4(5(1(x1)))) -> 2(5(4(4(0(1(x1)))))) 3(0(1(5(x1)))) -> 3(1(4(0(5(4(x1)))))) 3(0(3(1(x1)))) -> 1(3(3(2(0(x1))))) 3(0(3(5(x1)))) -> 3(2(5(0(2(3(x1)))))) 3(3(0(1(x1)))) -> 0(1(3(2(2(3(x1)))))) 3(4(5(1(x1)))) -> 3(2(5(4(2(1(x1)))))) 4(1(3(5(x1)))) -> 1(2(5(3(4(4(x1)))))) 4(1(5(1(x1)))) -> 4(4(5(1(2(1(x1)))))) 4(4(1(5(x1)))) -> 4(1(2(5(4(x1))))) 0(1(4(5(5(x1))))) -> 0(5(1(4(2(5(x1)))))) 0(2(1(4(5(x1))))) -> 0(0(1(2(5(4(x1)))))) 0(2(1(5(5(x1))))) -> 0(1(2(2(5(5(x1)))))) 0(4(2(4(1(x1))))) -> 1(3(2(0(4(4(x1)))))) 0(4(5(4(3(x1))))) -> 2(5(0(4(4(3(x1)))))) 0(5(1(5(1(x1))))) -> 0(5(1(1(2(5(x1)))))) 0(5(2(1(5(x1))))) -> 1(2(5(5(0(4(x1)))))) 0(5(2(4(1(x1))))) -> 4(5(2(1(2(0(x1)))))) 3(0(1(4(1(x1))))) -> 0(4(4(1(3(1(x1)))))) 3(0(1(4(1(x1))))) -> 4(3(2(0(1(1(x1)))))) 3(0(3(5(5(x1))))) -> 3(3(2(5(0(5(x1)))))) 3(0(5(3(1(x1))))) -> 1(0(3(3(2(5(x1)))))) 4(0(1(4(1(x1))))) -> 4(4(0(1(3(1(x1)))))) 4(0(1(5(1(x1))))) -> 0(1(2(5(4(1(x1)))))) 4(0(2(4(5(x1))))) -> 4(0(2(5(0(4(x1)))))) 4(1(1(5(1(x1))))) -> 1(1(2(5(4(1(x1)))))) 4(5(1(4(1(x1))))) -> 4(4(1(2(1(5(x1)))))) 4(5(2(3(1(x1))))) -> 4(3(1(2(2(5(x1)))))) 4(5(4(3(1(x1))))) -> 4(1(2(5(3(4(x1)))))) 4(5(5(3(1(x1))))) -> 1(3(2(5(5(4(x1)))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ----------------------------------------
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