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SRS Standard pair #487087264
details
property
value
status
complete
benchmark
212094.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n147.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
10.232 seconds
cpu usage
37.5439
user time
36.0907
system time
1.45326
max virtual memory
4.0589696E7
max residence set size
3841460.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 191 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) QDP (8) UsableRulesProof [EQUIVALENT, 1 ms] (9) QDP (10) QDPOrderProof [EQUIVALENT, 7 ms] (11) QDP (12) PisEmptyProof [EQUIVALENT, 0 ms] (13) YES (14) QDP (15) QDPOrderProof [EQUIVALENT, 1049 ms] (16) QDP (17) DependencyGraphProof [EQUIVALENT, 0 ms] (18) QDP (19) UsableRulesProof [EQUIVALENT, 0 ms] (20) QDP (21) QDPOrderProof [EQUIVALENT, 0 ms] (22) QDP (23) PisEmptyProof [EQUIVALENT, 0 ms] (24) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(1(1(2(x1)))) -> 1(3(0(1(2(x1))))) 0(1(1(2(x1)))) -> 1(3(1(0(2(x1))))) 0(1(1(2(x1)))) -> 2(3(1(3(0(1(x1)))))) 0(1(2(0(x1)))) -> 1(0(0(2(2(x1))))) 0(1(2(4(x1)))) -> 0(2(3(4(1(x1))))) 0(1(2(4(x1)))) -> 1(0(4(2(3(x1))))) 0(1(2(4(x1)))) -> 1(2(3(0(4(x1))))) 0(1(2(4(x1)))) -> 2(1(4(0(3(x1))))) 0(1(2(4(x1)))) -> 1(2(3(4(0(5(x1)))))) 0(1(2(4(x1)))) -> 2(1(1(0(3(4(x1)))))) 0(1(2(4(x1)))) -> 4(1(2(2(3(0(x1)))))) 0(1(2(4(x1)))) -> 4(5(0(2(3(1(x1)))))) 0(4(2(0(x1)))) -> 0(4(2(3(0(x1))))) 0(4(2(0(x1)))) -> 2(3(0(4(0(0(x1)))))) 0(4(2(0(x1)))) -> 3(4(0(2(3(0(x1)))))) 0(4(2(0(x1)))) -> 4(2(3(0(4(0(x1)))))) 0(4(2(0(x1)))) -> 4(3(0(0(5(2(x1)))))) 0(4(2(4(x1)))) -> 4(0(2(3(1(4(x1)))))) 0(4(2(4(x1)))) -> 4(0(4(2(0(3(x1)))))) 5(1(2(0(x1)))) -> 2(1(3(5(0(x1))))) 5(1(2(0(x1)))) -> 3(1(0(2(5(x1))))) 5(1(2(0(x1)))) -> 2(3(0(0(1(5(x1)))))) 5(1(2(4(x1)))) -> 3(2(5(1(4(x1))))) 5(1(2(4(x1)))) -> 5(2(1(3(4(x1))))) 5(1(2(4(x1)))) -> 5(5(2(1(4(x1))))) 5(1(2(4(x1)))) -> 0(3(4(5(2(1(x1)))))) 5(1(4(2(x1)))) -> 3(4(5(2(1(x1))))) 5(1(4(2(x1)))) -> 2(1(3(4(5(4(x1)))))) 5(1(4(2(x1)))) -> 3(3(4(2(1(5(x1)))))) 5(4(1(4(x1)))) -> 3(4(4(1(5(4(x1)))))) 5(4(1(4(x1)))) -> 4(1(3(5(0(4(x1)))))) 5(4(1(4(x1)))) -> 5(1(3(4(5(4(x1)))))) 5(4(1(4(x1)))) -> 5(1(5(3(4(4(x1)))))) 5(4(2(0(x1)))) -> 5(4(2(3(0(x1))))) 5(4(2(0(x1)))) -> 0(1(2(3(4(5(x1)))))) 5(4(2(0(x1)))) -> 4(5(3(3(0(2(x1)))))) 0(1(2(0(4(x1))))) -> 0(2(4(1(3(0(x1)))))) 0(1(2(0(4(x1))))) -> 2(0(3(4(0(1(x1)))))) 0(1(2(0(4(x1))))) -> 4(0(2(3(1(0(x1)))))) 0(1(4(2(2(x1))))) -> 1(2(3(4(0(2(x1)))))) 5(0(1(2(4(x1))))) -> 3(0(2(1(4(5(x1)))))) 5(1(2(2(4(x1))))) -> 5(2(2(1(4(5(x1)))))) 5(1(2(4(0(x1))))) -> 5(0(2(1(3(4(x1)))))) 5(1(2(4(0(x1))))) -> 5(0(3(2(1(4(x1)))))) 5(1(3(1(4(x1))))) -> 1(5(1(3(4(0(x1)))))) 5(1(4(1(2(x1))))) -> 2(1(5(3(4(1(x1)))))) 5(4(1(1(4(x1))))) -> 1(1(3(4(5(4(x1)))))) 5(4(1(4(0(x1))))) -> 3(4(0(4(5(1(x1)))))) 5(4(3(2(0(x1))))) -> 5(4(0(3(2(3(x1)))))) 5(4(5(2(0(x1))))) -> 5(0(5(4(4(2(x1)))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ----------------------------------------
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