SRS Standard pair #487087499

details

property	value
status	complete
benchmark	212117.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n146.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	MultumNonMulta 20 June 2020 20G sparse
configuration	default
runtime (wallclock)	2.72112 seconds
cpu usage	9.59554
user time	8.67747
system time	0.918076
max virtual memory	2.634042E7
max residence set size	900484.0

stage attributes

key	value
starexec-result	YES

output

YES

After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4, 5->5 }, 
it remains to prove termination of the 50-rule system
{ 0 1 1 -> 0 1 2 3 4 1 ,
  0 1 1 -> 1 3 1 3 4 0 ,
  0 1 1 -> 5 1 3 0 3 1 ,
  0 1 4 -> 0 1 3 4 ,
  0 1 4 -> 1 3 4 2 0 ,
  0 1 4 -> 1 5 3 4 0 ,
  0 1 4 -> 3 1 3 4 0 ,
  0 1 4 -> 1 1 5 3 4 0 ,
  0 1 4 -> 1 2 3 4 3 0 ,
  0 1 4 -> 1 3 3 4 4 0 ,
  0 1 4 -> 1 3 4 5 0 5 ,
  0 1 4 -> 3 4 5 5 0 1 ,
  1 2 4 -> 1 2 3 4 1 ,
  1 2 4 -> 5 3 4 1 2 ,
  1 2 4 -> 1 5 2 3 4 3 ,
  1 2 4 -> 2 3 3 4 5 1 ,
  5 2 1 -> 1 2 2 3 5 4 ,
  5 2 1 -> 1 3 2 5 3 4 ,
  5 2 4 -> 0 5 2 3 4 ,
  5 2 4 -> 5 5 3 4 2 ,
  5 2 4 -> 0 3 4 4 5 2 ,
  5 2 4 -> 2 2 5 3 4 4 ,
  5 2 4 -> 2 3 3 4 5 5 ,
  5 2 4 -> 2 3 4 3 5 3 ,
  5 2 4 -> 2 5 3 4 0 5 ,
  5 2 4 -> 3 1 2 5 3 4 ,
  5 2 4 -> 5 2 3 4 0 3 ,
  0 0 2 4 -> 0 4 3 0 2 ,
  0 1 1 5 -> 0 1 3 5 1 2 ,
  0 1 2 4 -> 0 1 2 3 3 4 ,
  0 1 4 5 -> 3 4 0 5 1 ,
  0 1 4 5 -> 3 4 5 3 0 1 ,
  0 4 2 1 -> 0 4 1 2 3 4 ,
  0 5 1 4 -> 0 0 3 5 4 1 ,
  1 0 1 4 -> 3 4 0 1 2 1 ,
  1 1 2 4 -> 1 3 4 1 2 ,
  1 2 2 4 -> 2 2 2 3 4 1 ,
  1 2 4 2 -> 1 2 3 4 2 3 ,
  1 5 2 1 -> 1 0 3 5 1 2 ,
  1 5 2 4 -> 3 2 3 5 1 4 ,
  1 5 2 4 -> 5 2 3 3 1 4 ,
  5 0 1 4 -> 3 4 0 5 3 1 ,
  5 2 5 1 -> 3 5 1 5 2 ,
  0 1 1 5 4 -> 0 0 5 4 1 1 ,
  1 0 0 2 4 -> 0 2 0 4 4 1 ,
  1 0 4 2 1 -> 1 2 3 4 1 0 ,
  1 2 5 0 1 -> 2 3 5 1 0 1 ,
  1 5 3 0 4 -> 5 1 3 4 0 4 ,
  5 0 5 2 4 -> 4 0 0 5 5 2 ,
  5 3 2 4 2 -> 2 1 5 3 4 2 }


The system was reversed.

After renaming modulo { 1->0, 0->1, 4->2, 3->3, 2->4, 5->5 }, 
it remains to prove termination of the 50-rule system
{ 0 0 1 -> 0 2 3 4 0 1 ,
  0 0 1 -> 1 2 3 0 3 0 ,
  0 0 1 -> 0 3 1 3 0 5 ,
  2 0 1 -> 2 3 0 1 ,
  2 0 1 -> 1 4 2 3 0 ,
  2 0 1 -> 1 2 3 5 0 ,
  2 0 1 -> 1 2 3 0 3 ,
  2 0 1 -> 1 2 3 5 0 0 ,
  2 0 1 -> 1 3 2 3 4 0 ,
  2 0 1 -> 1 2 2 3 3 0 ,
  2 0 1 -> 5 1 5 2 3 0 ,
  2 0 1 -> 0 1 5 5 2 3 ,
  2 4 0 -> 0 2 3 4 0 ,
  2 4 0 -> 4 0 2 3 5 ,
  2 4 0 -> 3 2 3 4 5 0 ,
  2 4 0 -> 0 5 2 3 3 4 ,
  0 4 5 -> 2 5 3 4 4 0 ,
  0 4 5 -> 2 3 5 4 3 0 ,
  2 4 5 -> 2 3 4 5 1 ,
  2 4 5 -> 4 2 3 5 5 ,
  2 4 5 -> 4 5 2 2 3 1 ,
  2 4 5 -> 2 2 3 5 4 4 ,
  2 4 5 -> 5 5 2 3 3 4 ,
  2 4 5 -> 3 5 3 2 3 4 ,
  2 4 5 -> 5 1 2 3 5 4 ,
  2 4 5 -> 2 3 5 4 0 3 ,
  2 4 5 -> 3 1 2 3 4 5 ,
  2 4 1 1 -> 4 1 3 2 1 ,
  5 0 0 1 -> 4 0 5 3 0 1 ,
  2 4 0 1 -> 2 3 3 4 0 1 ,
  5 2 0 1 -> 0 5 1 2 3 ,
  5 2 0 1 -> 0 1 3 5 2 3 ,
  0 4 2 1 -> 2 3 4 0 2 1 ,
  2 0 5 1 -> 0 2 5 3 1 1 ,
  2 0 1 0 -> 0 4 0 1 2 3 ,
  2 4 0 0 -> 4 0 2 3 0 ,
  2 4 4 0 -> 0 2 3 4 4 4 ,
  4 2 4 0 -> 3 4 2 3 4 0 ,
  0 4 5 0 -> 4 0 5 3 1 0 ,
  2 4 5 0 -> 2 0 5 3 4 3 ,

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