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SRS Standard pair #487088004
details
property
value
status
complete
benchmark
157593.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n145.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
6.19356 seconds
cpu usage
5.9354
user time
5.40819
system time
0.527211
max virtual memory
806528.0
max residence set size
51176.0
stage attributes
key
value
starexec-result
YES
output
YES Problem 1: (VAR v_NonEmpty:S x1:S) (RULES 0(0(0(1(x1:S)))) -> 0(1(0(0(2(3(x1:S)))))) 0(0(4(0(0(x1:S))))) -> 0(4(2(0(0(0(x1:S)))))) 0(0(4(1(x1:S)))) -> 0(2(1(4(2(0(x1:S)))))) 0(0(4(1(x1:S)))) -> 1(0(5(4(2(0(x1:S)))))) 0(0(4(1(x1:S)))) -> 4(2(0(1(0(x1:S))))) 0(0(4(1(x1:S)))) -> 3(4(2(0(1(0(x1:S)))))) 0(1(3(5(0(x1:S))))) -> 0(1(3(0(5(3(x1:S)))))) 0(4(4(0(x1:S)))) -> 0(4(0(2(4(2(x1:S)))))) 0(4(4(0(x1:S)))) -> 4(4(2(0(0(x1:S))))) 0(4(4(0(x1:S)))) -> 4(2(0(0(4(2(x1:S)))))) 0(4(4(0(x1:S)))) -> 4(2(0(0(2(4(x1:S)))))) 0(4(4(0(x1:S)))) -> 4(2(0(4(2(0(x1:S)))))) 0(4(4(1(x1:S)))) -> 0(1(4(4(2(3(x1:S)))))) 0(4(4(1(x1:S)))) -> 0(1(4(4(2(x1:S))))) 0(4(4(1(x1:S)))) -> 0(1(5(4(4(2(x1:S)))))) 0(4(4(1(x1:S)))) -> 1(4(4(2(0(x1:S))))) 0(4(4(1(x1:S)))) -> 1(5(4(4(2(0(x1:S)))))) 0(4(4(1(x1:S)))) -> 4(2(4(2(1(0(x1:S)))))) 0(4(4(1(x1:S)))) -> 2(4(0(1(5(4(x1:S)))))) 0(4(4(1(x1:S)))) -> 2(4(4(1(2(0(x1:S)))))) 0(4(4(1(x1:S)))) -> 2(4(5(4(0(1(x1:S)))))) 0(4(3(4(0(x1:S))))) -> 0(2(3(4(4(0(x1:S)))))) 0(3(4(0(0(x1:S))))) -> 3(4(2(0(0(0(x1:S)))))) 0(3(4(0(x1:S)))) -> 0(4(5(3(0(5(x1:S)))))) 0(3(4(0(x1:S)))) -> 0(3(0(2(4(2(x1:S)))))) 0(3(4(0(x1:S)))) -> 0(3(4(2(0(2(x1:S)))))) 0(3(5(0(1(x1:S))))) -> 0(1(0(5(2(3(x1:S)))))) 0(3(5(4(1(x1:S))))) -> 5(1(0(4(5(3(x1:S)))))) 1(4(4(0(0(x1:S))))) -> 4(1(4(2(0(0(x1:S)))))) 1(4(4(0(1(x1:S))))) -> 1(4(4(1(2(0(x1:S)))))) 1(4(4(0(x1:S)))) -> 5(4(4(2(0(1(x1:S)))))) 1(4(4(1(x1:S)))) -> 2(1(4(1(2(4(x1:S)))))) 1(4(4(1(x1:S)))) -> 2(4(1(2(1(4(x1:S)))))) 1(4(4(1(x1:S)))) -> 2(4(2(1(4(1(x1:S)))))) 1(4(4(1(x1:S)))) -> 2(3(4(1(4(1(x1:S)))))) 1(4(4(4(1(x1:S))))) -> 2(4(1(4(4(1(x1:S)))))) 4(0(0(0(x1:S)))) -> 0(4(2(0(0(5(x1:S)))))) 4(0(0(1(x1:S)))) -> 2(3(0(1(0(4(x1:S)))))) 4(0(0(4(1(x1:S))))) -> 4(4(2(0(1(0(x1:S)))))) 4(0(4(0(x1:S)))) -> 2(4(2(0(0(4(x1:S)))))) 4(0(4(0(x1:S)))) -> 3(4(2(0(4(0(x1:S)))))) 4(0(4(1(x1:S)))) -> 2(4(2(0(4(1(x1:S)))))) 4(0(4(4(0(x1:S))))) -> 4(0(4(2(4(0(x1:S)))))) 4(1(0(0(1(x1:S))))) -> 4(2(0(1(1(0(x1:S)))))) 4(1(3(4(0(x1:S))))) -> 3(1(4(2(4(0(x1:S)))))) 4(4(0(0(1(x1:S))))) -> 4(0(4(2(0(1(x1:S)))))) 4(4(4(0(x1:S)))) -> 2(4(2(4(4(0(x1:S)))))) 4(4(4(1(x1:S)))) -> 4(2(4(1(2(4(x1:S)))))) 4(4(4(1(x1:S)))) -> 4(5(4(1(5(4(x1:S)))))) 4(4(4(1(x1:S)))) -> 2(4(2(4(1(4(x1:S)))))) 4(4(4(4(1(x1:S))))) -> 4(4(4(1(2(4(x1:S)))))) 4(4(5(0(1(x1:S))))) -> 4(5(0(1(4(2(x1:S)))))) 4(3(1(0(0(x1:S))))) -> 1(4(2(3(0(0(x1:S)))))) 4(3(1(0(0(x1:S))))) -> 3(1(4(2(0(0(x1:S)))))) 4(3(1(5(0(x1:S))))) -> 1(4(5(3(0(1(x1:S)))))) 4(3(4(0(x1:S)))) -> 0(4(2(3(4(2(x1:S)))))) 4(3(4(0(x1:S)))) -> 4(0(3(4(2(x1:S))))) 4(3(4(0(x1:S)))) -> 4(4(2(0(3(x1:S))))) 4(3(4(0(x1:S)))) -> 4(4(2(3(0(2(x1:S)))))) 4(3(4(0(x1:S)))) -> 4(4(5(3(0(3(x1:S)))))) 4(3(4(0(x1:S)))) -> 4(2(0(4(2(3(x1:S)))))) 4(3(4(0(x1:S)))) -> 4(3(0(5(4(2(x1:S)))))) 4(3(4(0(x1:S)))) -> 2(4(0(3(4(2(x1:S)))))) 4(3(4(0(x1:S)))) -> 2(3(0(4(4(5(x1:S)))))) 4(3(4(0(x1:S)))) -> 2(3(4(4(0(2(x1:S)))))) 4(3(4(1(x1:S)))) -> 1(4(2(4(2(3(x1:S)))))) 4(3(4(1(x1:S)))) -> 2(4(2(3(1(4(x1:S)))))) 4(3(4(1(x1:S)))) -> 2(3(1(4(5(4(x1:S)))))) 4(3(4(1(x1:S)))) -> 2(3(4(2(1(4(x1:S)))))) 4(3(4(1(x1:S)))) -> 3(1(4(2(4(2(x1:S)))))) 4(3(4(1(x1:S)))) -> 3(4(2(4(1(x1:S))))) 4(3(4(1(x1:S)))) -> 3(4(2(4(5(1(x1:S)))))) 4(3(4(1(x1:S)))) -> 3(4(5(3(4(1(x1:S)))))) 4(3(4(4(1(x1:S))))) -> 4(4(3(1(4(2(x1:S)))))) 4(3(2(4(0(x1:S))))) -> 4(2(0(3(4(2(x1:S)))))) 4(3(5(0(0(x1:S))))) -> 4(0(5(2(3(0(x1:S)))))) 4(3(5(0(1(x1:S))))) -> 2(3(5(4(0(1(x1:S)))))) 4(3(5(4(0(x1:S))))) -> 0(4(5(3(4(2(x1:S)))))) 4(3(5(4(0(x1:S))))) -> 0(3(4(5(4(5(x1:S)))))) 4(3(5(4(0(x1:S))))) -> 4(4(5(3(0(2(x1:S)))))) 4(3(5(4(0(x1:S))))) -> 5(4(3(4(2(0(x1:S)))))) 4(3(5(4(1(x1:S))))) -> 3(4(2(4(5(1(x1:S)))))) 4(3(5(5(0(x1:S))))) -> 0(2(3(5(4(5(x1:S)))))) 4(3(5(5(1(x1:S))))) -> 1(5(4(2(5(3(x1:S)))))) ) Problem 1: Dependency Pairs Processor: -> Pairs: 0#(0(4(0(0(x1:S))))) -> 0#(0(0(x1:S))) 0#(0(4(0(0(x1:S))))) -> 0#(4(2(0(0(0(x1:S)))))) 0#(0(4(0(0(x1:S))))) -> 4#(2(0(0(0(x1:S))))) 0#(0(4(1(x1:S)))) -> 0#(1(0(x1:S)))
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