details

property	value
status	complete
benchmark	212693.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n151.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	3.76842 seconds
cpu usage	11.8408
user time	11.3735
system time	0.467345
max virtual memory	1.9958376E7
max residence set size	1251300.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 127 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) QDP (8) QDPSizeChangeProof [EQUIVALENT, 0 ms] (9) YES (10) QDP (11) UsableRulesProof [EQUIVALENT, 0 ms] (12) QDP (13) DependencyGraphProof [EQUIVALENT, 0 ms] (14) QDP (15) UsableRulesProof [EQUIVALENT, 0 ms] (16) QDP (17) QDPSizeChangeProof [EQUIVALENT, 0 ms] (18) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(1(2(x1))) -> 0(0(2(1(x1)))) 0(1(2(x1))) -> 0(2(1(3(x1)))) 0(1(2(x1))) -> 0(0(2(1(4(4(x1)))))) 0(3(1(x1))) -> 0(1(3(4(0(x1))))) 0(3(1(x1))) -> 0(1(3(4(4(x1))))) 0(3(1(x1))) -> 1(3(4(4(4(0(x1)))))) 0(3(2(x1))) -> 0(2(1(3(x1)))) 0(3(2(x1))) -> 0(2(3(4(x1)))) 0(3(2(x1))) -> 0(0(2(4(3(x1))))) 0(3(2(x1))) -> 0(2(1(4(3(x1))))) 0(3(2(x1))) -> 0(2(4(3(3(x1))))) 0(3(2(x1))) -> 0(2(1(3(3(4(x1)))))) 0(3(2(x1))) -> 0(2(3(4(5(5(x1)))))) 0(3(2(x1))) -> 2(4(4(3(4(0(x1)))))) 0(4(1(x1))) -> 0(1(4(4(x1)))) 0(4(1(x1))) -> 0(2(1(4(x1)))) 0(4(2(x1))) -> 0(2(1(4(x1)))) 0(4(2(x1))) -> 0(2(3(4(x1)))) 0(4(2(x1))) -> 0(2(4(3(x1)))) 2(0(1(x1))) -> 5(0(2(1(x1)))) 2(3(1(x1))) -> 1(3(5(2(x1)))) 2(3(1(x1))) -> 0(2(1(3(5(x1))))) 2(3(1(x1))) -> 1(4(3(5(2(x1))))) 0(2(0(1(x1)))) -> 5(0(0(2(1(x1))))) 0(3(1(1(x1)))) -> 0(1(4(1(3(4(x1)))))) 0(3(2(1(x1)))) -> 0(0(3(4(2(1(x1)))))) 0(3(2(2(x1)))) -> 1(3(4(0(2(2(x1)))))) 0(4(1(2(x1)))) -> 1(4(0(2(5(x1))))) 0(4(3(2(x1)))) -> 2(3(4(4(0(0(x1)))))) 0(5(3(1(x1)))) -> 0(1(4(3(5(4(x1)))))) 0(5(3(1(x1)))) -> 0(1(5(3(4(0(x1)))))) 0(5(3(2(x1)))) -> 0(2(4(5(3(x1))))) 0(5(3(2(x1)))) -> 0(2(5(3(3(x1))))) 2(0(3(1(x1)))) -> 2(0(1(3(5(2(x1)))))) 2(0(4(1(x1)))) -> 2(0(1(4(5(x1))))) 2(5(3(2(x1)))) -> 2(5(2(3(3(x1))))) 2(5(4(2(x1)))) -> 0(2(5(2(4(x1))))) 0(0(3(2(1(x1))))) -> 0(0(1(3(5(2(x1)))))) 0(1(0(3(2(x1))))) -> 0(1(4(3(2(0(x1)))))) 0(1(0(3(2(x1))))) -> 2(3(1(0(0(5(x1)))))) 0(3(2(5(1(x1))))) -> 0(2(5(1(3(3(x1)))))) 0(5(1(1(2(x1))))) -> 0(2(4(1(1(5(x1)))))) 0(5(1(2(2(x1))))) -> 0(2(5(2(1(2(x1)))))) 0(5(3(2(1(x1))))) -> 0(1(3(4(2(5(x1)))))) 0(5(5(3(2(x1))))) -> 0(2(5(1(3(5(x1)))))) 2(0(3(1(1(x1))))) -> 2(1(0(1(3(4(x1)))))) 2(2(0(3(1(x1))))) -> 1(3(0(2(5(2(x1)))))) 2(2(0(5(1(x1))))) -> 2(0(2(1(5(1(x1)))))) 2(5(5(4(1(x1))))) -> 5(5(2(1(3(4(x1)))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 2(1(0(x1))) -> 1(2(0(0(x1)))) 2(1(0(x1))) -> 3(1(2(0(x1)))) popout

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all output return to SRS Standard