details

property	value
status	complete
benchmark	96224.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n145.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.855316 seconds
cpu usage	1.91527
user time	1.46032
system time	0.454949
max virtual memory	6625128.0
max residence set size	66780.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: 0(1(2(2(3(0(4(4(x1)))))))) -> 0(4(5(0(3(4(0(4(x1)))))))) 0(2(2(2(0(5(2(5(4(x1))))))))) -> 0(0(0(3(4(3(0(1(0(x1))))))))) 2(1(1(3(4(3(1(1(5(x1))))))))) -> 1(0(2(3(1(0(5(1(5(x1))))))))) 5(4(0(4(3(3(1(2(5(3(0(x1))))))))))) -> 5(5(2(5(3(1(5(0(3(5(2(x1))))))))))) 2(4(5(0(1(1(3(3(5(3(0(0(x1)))))))))))) -> 4(4(2(2(1(0(4(0(1(3(2(0(x1)))))))))))) 4(4(3(0(3(1(5(3(5(1(3(1(5(3(x1)))))))))))))) -> 0(2(4(5(0(0(0(5(1(0(5(4(4(x1))))))))))))) 2(2(0(0(2(1(0(5(3(2(2(1(4(0(5(x1))))))))))))))) -> 0(0(3(5(3(0(4(3(1(3(0(2(5(5(x1)))))))))))))) 3(0(0(4(2(5(5(1(3(0(2(3(3(5(1(4(5(x1))))))))))))))))) -> 3(4(0(1(0(5(5(3(1(4(0(3(5(3(2(2(5(x1))))))))))))))))) 5(1(1(4(1(5(3(0(4(3(2(5(4(1(3(3(5(x1))))))))))))))))) -> 5(0(1(0(4(0(2(4(5(1(5(4(1(5(3(3(5(x1))))))))))))))))) 0(1(4(4(3(2(0(4(1(4(3(4(4(1(5(3(4(4(x1)))))))))))))))))) -> 0(2(4(2(3(1(0(1(1(1(3(0(2(4(4(1(1(2(x1)))))))))))))))))) 1(1(4(1(0(1(0(3(3(4(4(1(5(4(0(4(4(5(5(3(x1)))))))))))))))))))) -> 1(3(0(3(2(2(4(4(2(0(3(3(4(0(3(0(4(3(4(0(x1)))))))))))))))))))) 2(0(3(3(3(4(1(1(0(4(4(0(3(3(3(0(0(1(5(3(x1)))))))))))))))))))) -> 5(3(3(1(4(0(4(5(4(4(4(2(4(3(1(1(1(5(4(x1))))))))))))))))))) 2(3(3(2(1(5(0(5(0(1(3(3(2(5(1(5(0(3(0(5(x1)))))))))))))))))))) -> 3(4(0(2(5(5(2(4(2(4(3(1(1(4(4(5(5(3(5(x1))))))))))))))))))) 3(3(2(2(3(3(4(0(0(0(2(5(0(5(3(0(0(1(1(4(x1)))))))))))))))))))) -> 3(1(1(0(3(3(5(4(2(2(1(0(1(1(0(5(0(3(4(0(x1)))))))))))))))))))) 4(2(4(1(0(5(0(4(1(0(3(0(2(5(4(3(5(3(5(3(x1)))))))))))))))))))) -> 4(2(5(4(4(2(4(5(0(0(3(1(5(0(2(0(2(2(1(x1))))))))))))))))))) Proof: String Reversal Processor: 4(4(0(3(2(2(1(0(x1)))))))) -> 4(0(4(3(0(5(4(0(x1)))))))) 4(5(2(5(0(2(2(2(0(x1))))))))) -> 0(1(0(3(4(3(0(0(0(x1))))))))) 5(1(1(3(4(3(1(1(2(x1))))))))) -> 5(1(5(0(1(3(2(0(1(x1))))))))) 0(3(5(2(1(3(3(4(0(4(5(x1))))))))))) -> 2(5(3(0(5(1(3(5(2(5(5(x1))))))))))) 0(0(3(5(3(3(1(1(0(5(4(2(x1)))))))))))) -> 0(2(3(1(0(4(0(1(2(2(4(4(x1)))))))))))) 3(5(1(3(1(5(3(5(1(3(0(3(4(4(x1)))))))))))))) -> 4(4(5(0(1(5(0(0(0(5(4(2(0(x1))))))))))))) 5(0(4(1(2(2(3(5(0(1(2(0(0(2(2(x1))))))))))))))) -> 5(5(2(0(3(1(3(4(0(3(5(3(0(0(x1)))))))))))))) 5(4(1(5(3(3(2(0(3(1(5(5(2(4(0(0(3(x1))))))))))))))))) -> 5(2(2(3(5(3(0(4(1(3(5(5(0(1(0(4(3(x1))))))))))))))))) 5(3(3(1(4(5(2(3(4(0(3(5(1(4(1(1(5(x1))))))))))))))))) -> 5(3(3(5(1(4(5(1(5(4(2(0(4(0(1(0(5(x1))))))))))))))))) 4(4(3(5(1(4(4(3(4(1(4(0(2(3(4(4(1(0(x1)))))))))))))))))) -> 2(1(1(4(4(2(0(3(1(1(1(0(1(3(2(4(2(0(x1)))))))))))))))))) 3(5(5(4(4(0(4(5(1(4(4(3(3(0(1(0(1(4(1(1(x1)))))))))))))))))))) -> 0(4(3(4(0(3(0(4(3(3(0(2(4(4(2(2(3(0(3(1(x1)))))))))))))))))))) 3(5(1(0(0(3(3(3(0(4(4(0(1(1(4(3(3(3(0(2(x1)))))))))))))))))))) -> 4(5(1(1(1(3(4(2(4(4(4(5(4(0(4(1(3(3(5(x1))))))))))))))))))) 5(0(3(0(5(1(5(2(3(3(1(0(5(0(5(1(2(3(3(2(x1)))))))))))))))))))) -> 5(3(5(5(4(4(1(1(3(4(2(4(2(5(5(2(0(4(3(x1))))))))))))))))))) 4(1(1(0(0(3(5(0(5(2(0(0(0(4(3(3(2(2(3(3(x1)))))))))))))))))))) -> 0(4(3(0(5(0(1(1(0(1(2(2(4(5(3(3(0(1(1(3(x1)))))))))))))))))))) 3(5(3(5(3(4(5(2(0(3(0(1(4(0(5(0(1(4(2(4(x1)))))))))))))))))))) -> 1(2(2(0(2(0(5(1(3(0(0(5(4(2(4(4(5(2(4(x1))))))))))))))))))) KBO Processor: weight function: w0 = 1 w(5) = w(1) = w(2) = w(3) = w(0) = w(4) = 1 precedence: 4 > 3 > 0 > 2 > 1 > 5 problem: Qed popout

output may be truncated. 'popout' for the full output.

job log

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