details

property	value
status	complete
benchmark	212892.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n145.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	298.521 seconds
cpu usage	286.4
user time	248.892
system time	37.5085
max virtual memory	806272.0
max residence set size	62372.0

stage attributes

key	value
starexec-result	YES

output

YES Problem 1: (VAR v_NonEmpty:S x1:S) (RULES 0(0(0(x1:S))) -> 0(2(0(0(x1:S)))) 0(0(1(0(4(x1:S))))) -> 0(0(0(1(4(2(x1:S)))))) 0(0(4(3(x1:S)))) -> 3(0(0(2(1(4(x1:S)))))) 0(0(4(x1:S))) -> 2(4(0(0(3(2(x1:S)))))) 0(0(5(3(x1:S)))) -> 0(5(2(5(0(3(x1:S)))))) 0(0(5(5(3(x1:S))))) -> 0(5(0(3(2(5(x1:S)))))) 0(0(5(x1:S))) -> 0(5(2(0(x1:S)))) 0(0(x1:S)) -> 0(2(3(4(0(2(x1:S)))))) 0(0(x1:S)) -> 1(0(2(0(2(x1:S))))) 0(1(0(3(x1:S)))) -> 2(1(0(3(0(x1:S))))) 0(1(1(0(x1:S)))) -> 2(1(0(0(1(2(x1:S)))))) 0(1(3(x1:S))) -> 3(2(2(1(0(x1:S))))) 0(3(0(x1:S))) -> 2(0(2(3(4(0(x1:S)))))) 0(3(x1:S)) -> 0(2(3(2(x1:S)))) 0(3(x1:S)) -> 0(2(2(2(3(2(x1:S)))))) 0(3(x1:S)) -> 2(0(2(1(3(x1:S))))) 0(3(x1:S)) -> 2(3(0(2(2(x1:S))))) 0(4(0(0(x1:S)))) -> 0(4(0(2(1(0(x1:S)))))) 0(4(1(3(x1:S)))) -> 2(1(4(2(0(3(x1:S)))))) 0(4(3(x1:S))) -> 1(0(2(1(3(4(x1:S)))))) 0(4(3(x1:S))) -> 3(0(2(4(x1:S)))) 0(4(3(x1:S))) -> 2(2(4(3(4(0(x1:S)))))) 0(4(5(3(x1:S)))) -> 4(3(2(5(0(x1:S))))) 0(4(5(3(x1:S)))) -> 4(3(5(0(2(4(x1:S)))))) 0(4(5(x1:S))) -> 2(4(0(5(2(5(x1:S)))))) 0(4(5(x1:S))) -> 5(3(2(4(4(0(x1:S)))))) 0(5(0(4(x1:S)))) -> 5(0(0(2(4(x1:S))))) 0(5(0(x1:S))) -> 0(5(2(4(0(x1:S))))) 0(5(0(x1:S))) -> 5(0(2(3(2(0(x1:S)))))) 0(5(3(x1:S))) -> 3(2(5(3(2(0(x1:S)))))) 0(5(5(3(x1:S)))) -> 2(3(5(5(0(x1:S))))) 1(0(0(x1:S))) -> 1(0(2(5(0(2(x1:S)))))) 1(0(3(x1:S))) -> 2(1(3(0(5(2(x1:S)))))) 1(0(4(x1:S))) -> 3(0(2(1(4(x1:S))))) 1(0(4(x1:S))) -> 2(1(2(1(4(0(x1:S)))))) 1(3(0(4(x1:S)))) -> 4(0(1(2(3(x1:S))))) 3(0(0(x1:S))) -> 3(0(2(0(x1:S)))) 3(0(3(x1:S))) -> 3(0(2(3(x1:S)))) 3(0(3(x1:S))) -> 3(3(2(2(0(x1:S))))) 3(0(4(3(4(x1:S))))) -> 3(0(3(4(2(4(x1:S)))))) 3(0(4(x1:S))) -> 2(3(4(2(0(3(x1:S)))))) 3(0(4(x1:S))) -> 2(2(3(4(0(x1:S))))) 3(0(4(x1:S))) -> 5(5(2(4(0(3(x1:S)))))) 3(3(0(4(5(x1:S))))) -> 1(4(5(3(0(3(x1:S)))))) 3(3(4(x1:S))) -> 3(2(1(3(2(4(x1:S)))))) 3(4(2(0(3(x1:S))))) -> 2(3(0(2(3(4(x1:S)))))) 3(5(0(x1:S))) -> 3(5(1(0(2(1(x1:S)))))) 4(0(3(5(x1:S)))) -> 5(2(3(4(2(0(x1:S)))))) 4(0(4(x1:S))) -> 0(2(4(4(0(x1:S))))) 4(0(4(x1:S))) -> 1(4(0(2(4(0(x1:S)))))) ) Problem 1: Dependency Pairs Processor: -> Pairs: 0#(0(0(x1:S))) -> 0#(2(0(0(x1:S)))) 0#(0(1(0(4(x1:S))))) -> 0#(0(0(1(4(2(x1:S)))))) 0#(0(1(0(4(x1:S))))) -> 0#(0(1(4(2(x1:S))))) 0#(0(4(3(x1:S)))) -> 0#(0(2(1(4(x1:S))))) 0#(0(4(3(x1:S)))) -> 0#(2(1(4(x1:S)))) 0#(0(4(3(x1:S)))) -> 1#(4(x1:S)) 0#(0(4(3(x1:S)))) -> 3#(0(0(2(1(4(x1:S)))))) 0#(0(4(3(x1:S)))) -> 4#(x1:S) 0#(0(4(x1:S))) -> 0#(0(3(2(x1:S)))) 0#(0(4(x1:S))) -> 0#(3(2(x1:S))) 0#(0(4(x1:S))) -> 4#(0(0(3(2(x1:S))))) 0#(0(5(3(x1:S)))) -> 0#(3(x1:S)) 0#(0(5(3(x1:S)))) -> 0#(5(2(5(0(3(x1:S)))))) 0#(0(5(5(3(x1:S))))) -> 0#(3(2(5(x1:S)))) 0#(0(5(5(3(x1:S))))) -> 0#(5(0(3(2(5(x1:S)))))) 0#(0(5(x1:S))) -> 0#(5(2(0(x1:S)))) 0#(0(5(x1:S))) -> 0#(x1:S) 0#(1(0(3(x1:S)))) -> 0#(3(0(x1:S))) 0#(1(0(3(x1:S)))) -> 0#(x1:S) 0#(1(0(3(x1:S)))) -> 1#(0(3(0(x1:S)))) 0#(1(0(3(x1:S)))) -> 3#(0(x1:S)) 0#(1(1(0(x1:S)))) -> 0#(0(1(2(x1:S)))) 0#(1(1(0(x1:S)))) -> 1#(0(0(1(2(x1:S))))) 0#(1(3(x1:S))) -> 0#(x1:S) 0#(1(3(x1:S))) -> 1#(0(x1:S)) 0#(1(3(x1:S))) -> 3#(2(2(1(0(x1:S))))) 0#(3(0(x1:S))) -> 0#(2(3(4(0(x1:S))))) 0#(3(0(x1:S))) -> 3#(4(0(x1:S))) 0#(3(0(x1:S))) -> 4#(0(x1:S)) 0#(3(x1:S)) -> 0#(2(1(3(x1:S)))) 0#(3(x1:S)) -> 1#(3(x1:S)) 0#(4(0(0(x1:S)))) -> 0#(4(0(2(1(0(x1:S)))))) 0#(4(0(0(x1:S)))) -> 0#(2(1(0(x1:S)))) 0#(4(0(0(x1:S)))) -> 1#(0(x1:S)) 0#(4(0(0(x1:S)))) -> 4#(0(2(1(0(x1:S))))) 0#(4(1(3(x1:S)))) -> 0#(3(x1:S)) 0#(4(1(3(x1:S)))) -> 1#(4(2(0(3(x1:S))))) 0#(4(1(3(x1:S)))) -> 4#(2(0(3(x1:S)))) popout

output may be truncated. 'popout' for the full output.

job log

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