details

property	value
status	complete
benchmark	212263.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n139.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	3.90353 seconds
cpu usage	12.5043
user time	12.0758
system time	0.428502
max virtual memory	3.7771716E7
max residence set size	1147400.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 129 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) QDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) QDP (9) QDPOrderProof [EQUIVALENT, 52 ms] (10) QDP (11) PisEmptyProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(1(2(x1))) -> 0(2(1(1(x1)))) 0(1(2(x1))) -> 0(2(1(3(x1)))) 0(1(2(x1))) -> 0(2(1(1(3(x1))))) 0(1(2(x1))) -> 0(2(4(1(1(x1))))) 0(1(2(x1))) -> 0(2(4(1(3(x1))))) 0(3(2(x1))) -> 0(2(1(3(x1)))) 0(3(2(x1))) -> 0(2(1(1(3(x1))))) 0(3(2(x1))) -> 0(0(2(1(1(3(x1)))))) 0(1(1(2(x1)))) -> 0(2(1(1(3(x1))))) 0(1(2(2(x1)))) -> 0(2(2(1(1(x1))))) 0(1(2(2(x1)))) -> 0(2(3(2(1(x1))))) 0(1(3(2(x1)))) -> 0(2(1(4(3(x1))))) 0(1(3(2(x1)))) -> 3(3(0(2(1(x1))))) 0(1(3(2(x1)))) -> 3(0(2(4(1(1(x1)))))) 0(1(5(2(x1)))) -> 5(0(2(1(1(x1))))) 0(3(2(2(x1)))) -> 0(0(2(3(2(x1))))) 0(3(2(2(x1)))) -> 0(0(4(2(3(2(x1)))))) 2(0(3(2(x1)))) -> 1(3(0(2(2(x1))))) 3(0(3(2(x1)))) -> 3(0(0(0(2(3(x1)))))) 3(1(5(2(x1)))) -> 0(2(1(5(3(x1))))) 3(3(5(2(x1)))) -> 3(0(2(1(5(3(x1)))))) 4(5(2(2(x1)))) -> 2(5(0(2(4(1(x1)))))) 5(0(1(2(x1)))) -> 0(2(1(3(4(5(x1)))))) 5(0(2(2(x1)))) -> 2(0(2(4(1(5(x1)))))) 5(0(3(2(x1)))) -> 3(0(2(1(4(5(x1)))))) 5(1(2(2(x1)))) -> 0(2(1(5(2(1(x1)))))) 5(1(2(2(x1)))) -> 2(1(5(2(1(1(x1)))))) 0(1(2(4(2(x1))))) -> 4(2(1(0(2(1(x1)))))) 0(1(2(5(2(x1))))) -> 2(0(2(1(5(4(x1)))))) 0(1(5(1(2(x1))))) -> 1(0(2(1(1(5(x1)))))) 0(1(5(5(2(x1))))) -> 0(2(1(5(5(1(x1)))))) 0(5(0(1(2(x1))))) -> 0(4(5(0(2(1(x1)))))) 0(5(0(3(2(x1))))) -> 0(5(0(0(2(3(x1)))))) 0(5(5(2(2(x1))))) -> 0(2(1(5(5(2(x1)))))) 3(0(3(1(2(x1))))) -> 1(3(3(0(2(3(x1)))))) 3(0(3(4(2(x1))))) -> 1(3(4(0(2(3(x1)))))) 4(5(1(4(2(x1))))) -> 2(4(4(4(1(5(x1)))))) 5(0(1(3(2(x1))))) -> 3(5(0(2(1(3(x1)))))) 5(0(3(1(2(x1))))) -> 0(2(1(4(3(5(x1)))))) 5(0(4(2(2(x1))))) -> 2(0(2(4(1(5(x1)))))) 5(1(0(3(2(x1))))) -> 0(4(3(5(1(2(x1)))))) 5(1(0(3(2(x1))))) -> 5(3(1(1(0(2(x1)))))) 5(1(0(5(2(x1))))) -> 3(5(5(0(2(1(x1)))))) 5(1(0(5(2(x1))))) -> 5(0(2(1(5(5(x1)))))) 5(2(0(3(2(x1))))) -> 0(2(5(2(3(1(x1)))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 2(1(0(x1))) -> 1(1(2(0(x1)))) 2(1(0(x1))) -> 3(1(2(0(x1)))) 2(1(0(x1))) -> 3(1(1(2(0(x1))))) 2(1(0(x1))) -> 1(1(4(2(0(x1))))) 2(1(0(x1))) -> 3(1(4(2(0(x1))))) 2(3(0(x1))) -> 3(1(2(0(x1)))) 2(3(0(x1))) -> 3(1(1(2(0(x1))))) 2(3(0(x1))) -> 3(1(1(2(0(0(x1)))))) 2(1(1(0(x1)))) -> 3(1(1(2(0(x1))))) 2(2(1(0(x1)))) -> 1(1(2(2(0(x1))))) 2(2(1(0(x1)))) -> 1(2(3(2(0(x1))))) 2(3(1(0(x1)))) -> 3(4(1(2(0(x1))))) popout

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all output return to SRS Standard