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SRS Standard pair #487088315
details
property
value
status
complete
benchmark
85294.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n141.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
MultumNonMulta 20 June 2020 20G sparse
configuration
default
runtime (wallclock)
17.4677 seconds
cpu usage
67.7864
user time
57.058
system time
10.7284
max virtual memory
2.6390904E7
max residence set size
1.368938E7
stage attributes
key
value
starexec-result
YES
output
YES After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4, 5->5 }, it remains to prove termination of the 40-rule system { 0 1 2 3 -> 3 4 5 , 1 2 0 5 5 -> 1 5 4 0 , 2 0 3 4 2 -> 3 1 2 4 , 5 5 5 5 0 -> 5 4 4 3 , 0 1 2 4 3 5 -> 2 4 5 3 0 , 0 3 0 4 2 0 -> 2 3 4 1 2 , 4 5 0 4 0 0 0 -> 4 3 4 2 5 0 , 0 1 0 2 1 4 4 2 -> 0 2 0 3 3 4 5 4 , 2 0 0 1 5 0 5 2 -> 2 0 5 2 1 1 , 3 4 1 4 3 0 3 2 -> 5 3 5 4 3 1 1 , 5 3 0 1 5 5 0 5 -> 5 0 4 2 1 3 4 , 5 5 5 3 1 3 4 4 -> 1 5 2 4 4 5 4 , 0 1 5 4 2 5 3 3 4 -> 2 0 5 4 3 0 1 0 4 , 0 3 3 1 2 2 0 4 5 -> 2 3 4 4 4 0 3 1 , 4 3 4 0 5 3 0 0 5 4 -> 3 1 1 2 1 2 0 4 2 , 4 2 5 4 5 2 1 1 0 2 1 -> 4 2 3 4 1 0 5 4 5 2 1 , 5 5 4 2 5 3 1 0 5 3 1 -> 2 2 2 2 2 0 3 5 1 2 1 , 5 5 5 0 3 5 2 4 1 2 4 -> 1 0 3 3 5 0 3 1 4 4 , 0 3 3 2 0 1 1 2 1 3 0 5 -> 2 3 0 2 5 4 1 0 1 2 4 3 , 3 3 2 5 2 5 4 5 0 5 4 2 1 -> 2 1 2 3 3 4 4 2 0 3 4 1 , 4 3 4 2 2 5 4 5 0 0 0 2 5 -> 4 4 5 1 4 5 0 1 0 5 3 , 3 4 0 4 1 2 3 5 2 1 4 4 0 3 -> 3 2 2 5 0 4 5 5 0 5 5 4 1 2 , 4 0 5 4 4 4 5 0 2 5 2 3 4 5 -> 4 1 0 4 3 4 2 3 1 3 2 3 3 , 5 3 5 4 2 4 4 5 0 5 4 1 2 2 -> 5 0 2 5 5 1 5 3 4 1 1 0 2 , 2 2 4 3 4 4 2 1 5 2 1 4 0 2 0 -> 3 5 3 3 1 2 1 3 0 4 5 3 4 0 , 0 2 0 2 5 2 2 1 4 5 0 3 1 5 0 2 -> 0 4 3 5 5 5 1 3 0 4 5 0 2 2 4 , 5 0 0 2 0 2 2 0 1 1 3 4 4 3 3 5 -> 5 4 0 3 4 4 1 0 0 3 5 1 4 5 5 5 , 5 0 2 3 2 4 4 3 4 1 0 0 0 4 4 3 -> 5 2 4 4 4 0 1 1 4 2 5 5 1 3 , 0 2 0 2 0 1 1 3 5 2 0 4 4 1 5 5 5 -> 4 1 3 4 1 1 3 1 0 4 2 2 5 3 3 , 0 4 3 0 2 1 3 3 3 0 5 1 2 3 2 5 4 0 -> 1 5 5 5 2 2 1 2 0 4 0 1 4 1 5 4 4 , 2 2 3 2 3 2 2 4 1 2 4 5 1 4 4 0 4 0 -> 5 2 2 0 4 4 5 4 2 3 2 3 1 0 5 3 3 4 , 2 4 1 1 1 2 5 4 4 2 0 0 1 4 5 5 5 0 -> 3 3 2 4 5 2 5 4 5 4 5 3 3 3 0 5 0 2 3 , 3 2 0 2 1 0 3 1 3 4 3 5 2 1 0 0 3 0 -> 5 2 4 0 1 5 2 3 3 5 4 4 5 2 3 3 3 0 , 2 5 1 2 0 4 1 2 4 3 2 0 4 3 1 3 5 2 5 -> 2 4 5 1 2 3 0 4 1 3 2 3 4 2 0 3 3 3 , 4 4 4 1 1 1 2 1 1 0 4 3 2 3 1 3 0 3 5 -> 4 1 0 2 3 3 0 1 1 4 5 3 1 1 5 3 2 2 3 5 , 3 5 3 3 0 0 4 4 4 4 0 1 1 5 2 5 0 5 0 2 -> 2 0 5 2 4 3 3 4 5 4 3 1 4 0 0 2 5 1 1 , 4 1 5 3 2 5 5 5 2 5 5 3 5 5 5 3 5 0 2 0 -> 4 1 4 0 5 2 1 3 4 3 1 1 0 4 3 3 2 0 , 0 0 4 0 0 0 0 1 0 4 4 5 3 2 2 4 0 5 3 0 5 -> 0 2 2 2 1 2 4 4 5 0 5 1 0 0 5 5 2 5 3 2 , 2 2 0 3 4 0 5 2 5 2 2 5 2 5 5 1 5 2 4 1 4 -> 0 0 5 2 4 1 4 3 4 3 2 4 4 3 4 4 1 1 4 , 2 5 5 5 0 2 3 2 4 0 0 1 5 2 3 2 3 0 1 0 5 -> 2 0 3 4 5 3 3 2 2 1 5 2 2 2 4 2 5 4 0 1 } The system was reversed. After renaming modulo { 3->0, 2->1, 1->2, 0->3, 5->4, 4->5 }, it remains to prove termination of the 40-rule system { 0 1 2 3 -> 4 5 0 , 4 4 3 1 2 -> 3 5 4 2 , 1 5 0 3 1 -> 5 1 2 0 , 3 4 4 4 4 -> 0 5 5 4 , 4 0 5 1 2 3 -> 3 0 4 5 1 , 3 1 5 3 0 3 -> 1 2 5 0 1 , 3 3 3 5 3 4 5 -> 3 4 1 5 0 5 , 1 5 5 2 1 3 2 3 -> 5 4 5 0 0 3 1 3 , 1 4 3 4 2 3 3 1 -> 2 2 1 4 3 1 , 1 0 3 0 5 2 5 0 -> 2 2 0 5 4 0 4 , 4 3 4 4 2 3 0 4 -> 5 0 2 1 5 3 4 , 5 5 0 2 0 4 4 4 -> 5 4 5 5 1 4 2 , 5 0 0 4 1 5 4 2 3 -> 5 3 2 3 0 5 4 3 1 , 4 5 3 1 1 2 0 0 3 -> 2 0 3 5 5 5 0 1 , 5 4 3 3 0 4 3 5 0 5 -> 1 5 3 1 2 1 2 2 0 , 2 1 3 2 2 1 4 5 4 1 5 -> 2 1 4 5 4 3 2 5 0 1 5 , 2 0 4 3 2 0 4 1 5 4 4 -> 2 1 2 4 0 3 1 1 1 1 1 , 5 1 2 5 1 4 0 3 4 4 4 -> 5 5 2 0 3 4 0 0 3 2 , 4 3 0 2 1 2 2 3 1 0 0 3 -> 0 5 1 2 3 2 5 4 1 3 0 1 , 2 1 5 4 3 4 5 4 1 4 1 0 0 -> 2 5 0 3 1 5 5 0 0 1 2 1 , 4 1 3 3 3 4 5 4 1 1 5 0 5 -> 0 4 3 2 3 4 5 2 4 5 5 , 0 3 5 5 2 1 4 0 1 2 5 3 5 0 -> 1 2 5 4 4 3 4 4 5 3 4 1 1 0 , 4 5 0 1 4 1 3 4 5 5 5 4 3 5 -> 0 0 1 0 2 0 1 5 0 5 3 2 5 , 1 1 2 5 4 3 4 5 5 1 5 4 0 4 -> 1 3 2 2 5 0 4 2 4 4 1 3 4 , 3 1 3 5 2 1 4 2 1 5 5 0 5 1 1 -> 3 5 0 4 5 3 0 2 1 2 0 0 4 0 , 1 3 4 2 0 3 4 5 2 1 1 4 1 3 1 3 -> 5 1 1 3 4 5 3 0 2 4 4 4 0 5 3 , 4 0 0 5 5 0 2 2 3 1 1 3 1 3 3 4 -> 4 4 4 5 2 4 0 3 3 2 5 5 0 3 5 4 , 0 5 5 3 3 3 2 5 0 5 5 1 0 1 3 4 -> 0 2 4 4 1 5 2 2 3 5 5 5 1 4 , 4 4 4 2 5 5 3 1 4 0 2 2 3 1 3 1 3 -> 0 0 4 1 1 5 3 2 0 2 2 5 0 2 5 , 3 5 4 1 0 1 2 4 3 0 0 0 2 1 3 0 5 3 -> 5 5 4 2 5 2 3 5 3 1 2 1 1 4 4 4 2 , 3 5 3 5 5 2 4 5 1 2 5 1 1 0 1 0 1 1 -> 5 0 0 4 3 2 0 1 0 1 5 4 5 5 3 1 1 4 , 3 4 4 4 5 2 3 3 1 5 5 4 1 2 2 2 5 1 -> 0 1 3 4 3 0 0 0 4 5 4 5 4 1 4 5 1 0 0 , 3 0 3 3 2 1 4 0 5 0 2 0 3 2 1 3 1 0 -> 3 0 0 0 1 4 5 5 4 0 0 1 4 2 3 5 1 4 , 4 1 4 0 2 0 5 3 1 0 5 1 2 5 3 1 2 4 1 -> 0 0 0 3 1 5 0 1 0 2 5 3 0 1 2 4 5 1 , 4 0 3 0 2 0 1 0 5 3 2 2 1 2 2 2 5 5 5 -> 4 0 1 1 0 4 2 2 0 4 5 2 2 3 0 0 1 3 2 5 , 1 3 4 3 4 1 4 2 2 3 5 5 5 5 3 3 0 0 4 0 -> 2 2 4 1 3 3 5 2 0 5 4 5 0 0 5 1 4 3 1 , 3 1 3 4 0 4 4 4 0 4 4 1 4 4 4 1 0 4 2 5 -> 3 1 0 0 5 3 2 2 0 5 0 2 1 4 3 5 2 5 , 4 3 0 4 3 5 1 1 0 4 5 5 3 2 3 3 3 3 5 3 3 -> 1 0 4 1 4 4 3 3 2 4 3 4 5 5 1 2 1 1 1 3 , 5 2 5 1 4 2 4 4 1 4 1 1 4 1 4 3 5 0 3 1 1 -> 5 2 2 5 5 0 5 5 1 0 5 0 5 2 5 1 4 3 3 , 4 3 2 3 0 1 0 1 4 2 3 3 5 1 0 1 3 4 4 4 1 -> 2 3 5 4 1 5 1 1 1 4 2 1 1 0 0 4 5 0 3 1 } Applying sparse 2-tiling [Hofbauer/Geser/Waldmann, FSCD 2019]. After renaming modulo { (0,0)->0, (0,1)->1, (1,2)->2, (2,3)->3, (3,0)->4, (0,4)->5, (4,5)->6, (5,0)->7, (3,1)->8, (3,2)->9, (0,2)->10, (3,3)->11, (0,3)->12, (3,4)->13, (3,5)->14, (0,5)->15, (3,7)->16, (0,7)->17, (1,0)->18, (1,4)->19, (2,0)->20, (2,4)->21, (4,0)->22, (4,4)->23, (5,4)->24, (6,0)->25, (6,4)->26, (4,3)->27, (4,2)->28, (2,1)->29, (2,2)->30, (2,5)->31, (2,7)->32, (1,3)->33, (5,3)->34, (6,3)->35, (1,5)->36, (5,1)->37, (1,1)->38, (1,7)->39, (4,1)->40, (5,5)->41, (6,1)->42, (6,5)->43, (4,7)->44, (5,2)->45, (5,7)->46, (6,2)->47 }, it remains to prove termination of the 1960-rule system { 0 1 2 3 4 -> 5 6 7 0 , 0 1 2 3 8 -> 5 6 7 1 , 0 1 2 3 9 -> 5 6 7 10 , 0 1 2 3 11 -> 5 6 7 12 ,
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