SRS Standard pair #487089344

details

property	value
status	complete
benchmark	torpa4.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n023.star.cs.uiowa.edu
space	Secret_05_SRS

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	5.07849 seconds
cpu usage	20.4127
user time	17.0907
system time	3.32206
max virtual memory	6044148.0
max residence set size	73364.0

stage attributes

key	value
starexec-result	YES

output

YES

Problem:
 a(b(c(a(x1)))) -> b(a(c(b(a(b(x1))))))
 a(d(x1)) -> c(x1)
 a(f(f(x1))) -> g(x1)
 b(g(x1)) -> g(b(x1))
 c(x1) -> f(f(x1))
 c(a(c(x1))) -> b(c(a(b(c(x1)))))
 c(d(x1)) -> a(a(x1))
 g(x1) -> c(a(x1))
 g(x1) -> d(d(d(d(x1))))

Proof:
 String Reversal Processor:
  a(c(b(a(x1)))) -> b(a(b(c(a(b(x1))))))
  d(a(x1)) -> c(x1)
  f(f(a(x1))) -> g(x1)
  g(b(x1)) -> b(g(x1))
  c(x1) -> f(f(x1))
  c(a(c(x1))) -> c(b(a(c(b(x1)))))
  d(c(x1)) -> a(a(x1))
  g(x1) -> a(c(x1))
  g(x1) -> d(d(d(d(x1))))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [f](x0) = x0 + 3,
    
    [c](x0) = x0 + 6,
    
    [d](x0) = x0 + 2,
    
    [g](x0) = x0 + 10,
    
    [a](x0) = x0 + 4,
    
    [b](x0) = x0
   orientation:
    a(c(b(a(x1)))) = x1 + 14 >= x1 + 14 = b(a(b(c(a(b(x1))))))
    
    d(a(x1)) = x1 + 6 >= x1 + 6 = c(x1)
    
    f(f(a(x1))) = x1 + 10 >= x1 + 10 = g(x1)
    
    g(b(x1)) = x1 + 10 >= x1 + 10 = b(g(x1))
    
    c(x1) = x1 + 6 >= x1 + 6 = f(f(x1))
    
    c(a(c(x1))) = x1 + 16 >= x1 + 16 = c(b(a(c(b(x1)))))
    
    d(c(x1)) = x1 + 8 >= x1 + 8 = a(a(x1))
    
    g(x1) = x1 + 10 >= x1 + 10 = a(c(x1))
    
    g(x1) = x1 + 10 >= x1 + 8 = d(d(d(d(x1))))
   problem:
    a(c(b(a(x1)))) -> b(a(b(c(a(b(x1))))))
    d(a(x1)) -> c(x1)
    f(f(a(x1))) -> g(x1)
    g(b(x1)) -> b(g(x1))
    c(x1) -> f(f(x1))
    c(a(c(x1))) -> c(b(a(c(b(x1)))))
    d(c(x1)) -> a(a(x1))
    g(x1) -> a(c(x1))
   Matrix Interpretation Processor: dim=1
    
    interpretation:
     [f](x0) = x0,
     
     [c](x0) = x0,
     
     [d](x0) = 4x0 + 12,
     
     [g](x0) = 2x0 + 4,
     
     [a](x0) = 2x0 + 4,
     
     [b](x0) = x0
    orientation:
     a(c(b(a(x1)))) = 4x1 + 12 >= 4x1 + 12 = b(a(b(c(a(b(x1))))))
     
     d(a(x1)) = 8x1 + 28 >= x1 = c(x1)
     
     f(f(a(x1))) = 2x1 + 4 >= 2x1 + 4 = g(x1)
     
     g(b(x1)) = 2x1 + 4 >= 2x1 + 4 = b(g(x1))
     
     c(x1) = x1 >= x1 = f(f(x1))
     
     c(a(c(x1))) = 2x1 + 4 >= 2x1 + 4 = c(b(a(c(b(x1)))))
     
     d(c(x1)) = 4x1 + 12 >= 4x1 + 12 = a(a(x1))
     
     g(x1) = 2x1 + 4 >= 2x1 + 4 = a(c(x1))
    problem:
     a(c(b(a(x1)))) -> b(a(b(c(a(b(x1))))))
     f(f(a(x1))) -> g(x1)
     g(b(x1)) -> b(g(x1))
     c(x1) -> f(f(x1))

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