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SRS Standard pair #487089472
details
property
value
status
complete
benchmark
abaaba-aabababaab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n022.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.61368 seconds
cpu usage
3.67284
user time
3.51143
system time
0.161408
max virtual memory
1.88784E7
max residence set size
286480.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(x1)))))) -> a(a(b(a(b(a(b(a(a(b(x1)))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(x1)))))) -> b(a(a(b(a(b(a(b(a(a(x1)))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(a(b(a(x1)))))) -> b(a(a(b(a(b(a(b(a(a(x1)))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(a(b(x))))) -> b(a(a(b(a(b(a(b(a(x))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(x))))) -> b(a(a(b(a(b(a(b(a(x))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(a(b(x))))) -> b(a(a(b(a(b(a(b(a(x))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 437, 438, 475, 476, 477, 478, 479, 480, 481, 482, 483, 484, 485, 486, 487, 488, 489, 490 Node 437 is start node and node 438 is final node. Those nodes are connected through the following edges: * 437 to 475 labelled b_1(0)* 438 to 438 labelled #_1(0)* 475 to 476 labelled a_1(0)* 476 to 477 labelled a_1(0)* 477 to 478 labelled b_1(0)* 478 to 479 labelled a_1(0)* 479 to 480 labelled b_1(0)* 480 to 481 labelled a_1(0)* 480 to 483 labelled b_1(1)* 481 to 482 labelled b_1(0)* 482 to 438 labelled a_1(0)* 482 to 483 labelled b_1(1)* 483 to 484 labelled a_1(1)* 484 to 485 labelled a_1(1)* 485 to 486 labelled b_1(1)* 486 to 487 labelled a_1(1)* 487 to 488 labelled b_1(1)* 488 to 489 labelled a_1(1)* 488 to 483 labelled b_1(1)* 489 to 490 labelled b_1(1)* 490 to 438 labelled a_1(1)* 490 to 483 labelled b_1(1) ---------------------------------------- (6) YES
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