details

property	value
status	complete
benchmark	abbaaaaaaa-aaaaaaaabbaabb.srs.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n150.star.cs.uiowa.edu
space	Wenzel_16

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.7897 seconds
cpu usage	4.07304
user time	3.8726
system time	0.20044
max virtual memory	1.9008216E7
max residence set size	309504.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 5 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(b(a(a(a(a(a(a(a(x1)))))))))) -> a(a(a(a(a(a(a(a(b(b(a(a(b(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(a(b(b(a(x1)))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(a(a(b(b(a(x1)))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(a(a(b(b(x))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(a(b(b(x))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(a(a(b(b(x))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 7, 8, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70 Node 7 is start node and node 8 is final node. Those nodes are connected through the following edges: * 7 to 9 labelled b_1(0)* 8 to 8 labelled #_1(0)* 9 to 11 labelled b_1(0)* 11 to 13 labelled a_1(0)* 13 to 15 labelled a_1(0)* 15 to 17 labelled b_1(0)* 17 to 19 labelled b_1(0)* 19 to 21 labelled a_1(0)* 19 to 59 labelled b_1(1)* 21 to 23 labelled a_1(0)* 21 to 59 labelled b_1(1)* 23 to 25 labelled a_1(0)* 23 to 59 labelled b_1(1)* 25 to 27 labelled a_1(0)* 25 to 59 labelled b_1(1)* 27 to 29 labelled a_1(0)* 27 to 59 labelled b_1(1)* 29 to 31 labelled a_1(0)* 29 to 59 labelled b_1(1)* 31 to 8 labelled a_1(0)* 31 to 59 labelled b_1(1)* 59 to 60 labelled b_1(1)* 60 to 61 labelled a_1(1)* 61 to 62 labelled a_1(1)* 62 to 63 labelled b_1(1)* 63 to 64 labelled b_1(1)* 64 to 65 labelled a_1(1)* 64 to 59 labelled b_1(1)* 65 to 66 labelled a_1(1)* 65 to 59 labelled b_1(1)* 66 to 67 labelled a_1(1)* 66 to 59 labelled b_1(1)* 67 to 68 labelled a_1(1)* 67 to 59 labelled b_1(1)* 68 to 69 labelled a_1(1)* 68 to 59 labelled b_1(1)* 69 to 70 labelled a_1(1)* 69 to 59 labelled b_1(1)* 70 to 8 labelled a_1(1)* 70 to 59 labelled b_1(1) ---------------------------------------- (6) YES popout

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